TABLES OF SOME INDEFINITE INTEGRALS OF BESSEL FUNCTIONS

Μέγεθος: px
Εμφάνιση ξεκινά από τη σελίδα:

Download "TABLES OF SOME INDEFINITE INTEGRALS OF BESSEL FUNCTIONS"

Transcript

1 Werner Rosenheinrich Ernst - Abbe - Hochschule Jena First variant: University of Applied Sciences Germany TABLES OF SOME INDEFINITE INTEGRALS OF BESSEL FUNCTIONS Integrals of the type J 0 d or J 0 aj 0 b d are well-known Most of the following integrals are not found in the widely used tables of Gradstein/Ryshik, Bateman/Erdélyi, Abramowitz/ Stegun, Prudnikov/Brychkov/Marichev or Jahnke/Emde/Lösch The goal of this table was to get tables for practicians So the integrals should be epressed by Bessel and Struve functions Indeed, there occured some eceptions Generally, integrals of the type µ J ν d may be written with Lommel functions, see 8], 10-74, or ], III In many cases reccurence relations define more integrals in a simple way Partially the integrals may be found by MAPLE as well In some cases MAPLE gives results with hypergeometric functions, see also ], 96, or 4] Some known integrals are included for completeness Here Z ν denotes some Bessel function or modified Bessel function of the first kind Partially the functions Y ν sometimes called Neumann s functions or Weber s functions and denoted by N ν ] and the Hankel functions H ν 1 and H ν are also considered The same holds for the modified Bessel function of the second kind K ν When a formula is continued in the net line, then the last sign + or - is repeated in the beginning of the new line On page 41 the used special functions and defined functions are described *E* - This sign marks formulas, that were incorrect in previous editions The pages with corrected errors are listed in the errata in the end I wish to epress my thanks to B Eckstein, S O Zafra, Yao Sun and F Nouguier for their remarks 1

2 References: 1] M Abramowitz, I Stegun: Handbook of Mathematical Functions, Dover Publications, NY, 1970 ] Y L Luke: Mathematical Functions and their Approimations, Academic Press, NY, 1975 ] Y L Luke: Integrals of Bessel Functions, MacGraw-Hill, NY, 196 4] A P Prudnikov, A Bryqkov, O I Mariqev: Integraly i r dy, t : Specialьnye funkcii, Nauka, Moskva, 00; FIZMATLIT, 00 5] E Jahnke, F Emde, F Lösch: Tafeln höherer Funktionen, 6 Auflage, B G Teubner, Stuttgart, ] I S Gradstein, I M Ryshik: Summen-, Produkt- und Integraltafeln / Tables of Series, Products, and Integrals, Band 1 / Volume 1, Verlag Harri Deutsch, Thun Frankfurt/M, ] I S Gradstein, I M Ryshik: Summen-, Produkt- und Integraltafeln / Tables of Series, Products, and Integrals, Band / Volume, Verlag Harri Deutsch, Thun Frankfurt/M, ] G N Watson: A Treatise on the Theory of Bessel Functions, Cambridge, University Press, 19 / ] P Humbert: Bessel-integral functions, Proceedings of the Edinburgh Mathematical Society Series, 19, : ] B A Peavy, Indefinite Integrals Involving Bessel Functions JOURNAL OF RESEARCH of the National Bureau of Standards - B, vol 718, Nos and, April - September 1967, pp ] B G Korenev: Vvedenie v teori besselevyh funkci i, Nauka, Moskva, ] S K H Auluck, Some integral identities involving products of general solutions of Bessel s equation of integral order, arivorg/abs/

3 1 1 n Z ν with integer values of n Contents 1 Integrals with one Bessel function 111 n Z n+1 Z n 1 Z n Z n Z n+1 Z n Z ν, ν > Higher Antiderivatives 44 1 Elementary Function and Bessel Function 11 n+1/ J ν 46 a Z ν d 46 b Integrals 51 c Recurrence { Formulas } 56 1 n e ± Iν 57 K ν a Integrals with e 57 b Integrals with e 59 { } sinh 1 n I ν 6 14 n cosh { sin cos } J ν n e a J ν 68 a General facts 68 b The Case a > 0 69 c The Case a < 0 77 d Integrals 8 e Special Cases n 1/ { sin cos } J ν n 1/ e ± I ν 9 a n 1/ e I ν 9 b n 1/ e I ν 94 c General formulas n+1 ln Z n ln Z n+ν ln Z ν 104 a The Functions Λ k and Λ k 104 b Basic Integrals 108 c Integrals of n ln Z c Integrals of n+1 ln Z n e ± ln Z ν Some Cases of n e ± Z 0 α 11 1 Special Function and Bessel Function 11 Orthogonal Polynomials 1 a Legendre Polynomials P n 1 b Chebyshev Polynomials T n 18

4 c Chebyshev Polynomials U n 14 d Laguerre Polynomials L n 146 e Hermite Polynomials H n Eponential Integral Sine and Cosine Integral 157 Products of two Bessel Functions 1 Bessel Functions with the the same Argument : 11 n+1 Zν n Zν n Zν 168 a The Functions Θ and Ω 168 b Integrals n Z 0 Z n+1 Z 0 Z n+1 Z 0 Z n+1 J 0 I n J 0 I n J 1 I n+1 J 1 I n+1] J µ Y ν 190 a n+1 J 0 Y b n J 0 Y c n J 0 Y 1 19 d n 1 J 0 Y 1 19 e n J 1 Y f n 1 J 0 Y g n+1 J 1 Y h n J 1 Y Bessel Functions with different Arguments α and β : 1 n+1 Z ν αz ν β 198 a ν = b ν = 1 08 n Z 0 αz 1 β 19 n Z ν αz ν β 4 a Basic Integrals 4 b Integrals 44 4 n+1 Z 0 αz 1 β 51 5 n+1 J 0 αi 0 β 55 6 n J 0 αi 1 β 57 7 n J 1 αi 0 β 59 8 n+1 J 1 αi 1 β 61 9 n+1 J ν αy ν β 6 Bessel Functions with different Arguments and + α 1 1 Z ν Z 1 + α and + α] 1 Z 1 + αz 1 d 64 4 Elementary Function and two Bessel Functions 41 n+1 ln Z ν d and n ln Z 0 Z 1 d 65 4 n ln Z ν Z ν d 7 a Integrals with 4n+ ln J 0 Z 0 7 4

5 a Integrals with 4n+1 ln J 1 Z 1 7 c Integrals with n+1 ln I ν K ν 74 d Integrals with n+ ln I ν K 1 ν 76 4 Some Cases of n ln Z ν Zν α d ep/ sin / cos Z ν Z 1 d Some Cases of n e α Z ν Z 1 d Some Cases of { } sin / cos n α Z sinh / cosh µ Zν β d 9 a { } sin n α Z µ Z ν β d 9 cos b { sinh n cosh } α Z µ Z ν β d 98 Products of three Bessel Functions 1 n Z0 m Z1 m 0 a Basic Integral Z0 0 b Basic Integral Z 0 Z1 06 c Basic Integral Z1 09 d n Z0 17 e n Z0 Z 1 0 f n Z 0 Z1 g n Z1 5 h Recurrence Relations 9 n Z κ α Z µ β Z ν γ 0 a n Z κ Z µ Z ν 0 b n Z κ α Z µ β Z ν α + β 41 c n Z κ α Z µ β Z ν α ± β 67 4 Products of four Bessel Functions 41 m Z0 n Z1 4 n 70 a Eplicit Integrals 70 b Basic Integral Z c Basic Integral Z0 Z1 70 d Basic Integral Z e Integrals of m Z0 4 8 f Integrals of m Z0 Z 1 85 g Integrals of m Z0 Z1 89 h Integrals of m Z 0 Z1 9 i Integrals of m Z j Recurrence relations 95 5 Quotients Denominator p Z 0 + q Z a Typ f Z µ /p Z 0 + q Z 1 ] Denominator p Z 0 + q Z 1 ] 401 a Typ f Z µ /p Z 0 + q Z 1 ] 401 b Typ f Z0 n Z1 n /p Z 0 + q Z 1 ], n = 0, 1, Denominator p Z 0 + q Z 1 ] 405 a Typ f Z µ /p Z 0 + q Z 1 ] Denominator p Z 0 + q Z 1 ]

6 a Typ f Z µ /p Z 0 + q Z 1 ] Denominator p Z0 + q Z1 408 a Typ f Z0 n Z1 n /p Z0 + q Z1 ], n = 0, 1, 408 b Typ f Z0 n Z1 n /p Z0 + q Z 0 Z 1 + rz1 ], n = 0, 1, Denominator a Z 0 + b Z 1 + p Z0 0 Z 1 + r Z Miscellaneous Used special functions and defined functions 41 8 Errata 41 6

7 1 Integrals with one Bessel Function: See also 10], 11 n Z ν with integer values of n 111 Integrals of the type n Z 0 d Let Φ = π J 1 H 0 J 0 H 1 ], where H ν denotes the Struve function, see 1], chapter 1117, 1118 and 1 And let Ψ = π I 0 L 1 I 1 L 0 ] be defined with the modified Struve function L ν Furthermore, let Φ Y = π Y 1 H 0 Y 0 H 1 ], Φ 1 π ] H = H 1 1 H 0 H 1 0 H 1, Φ π ] H = H 1 H 0 H 0 H 1 and Ψ K = π K 0 L 1 + K 1 L 0 ] In the following formulas J ν may be substituted by Y ν and simultaneously Φ by Φ Y or H ν p, p = 1, and Φ p H Well-known integrals: J 0 d = J 0 + Φ = Λ 0 I 0 d = I 0 + Ψ = Λ 0 K 0 d = K 0 + Ψ K The new-defined function Λ 0 is discussed in 110 a on page 104 and so is Λ 0 on page 106 See also 1], 111 H p 0 Y 0 d = Y 0 + Φ Y d = Hp 0 + Φp H, p = 1, J 0 d = J 1 Φ I 0 d = I 1 + Ψ K 0 d = K 1 + Ψ K 4 J 0 d = 4 9 J 1 + J 0 + 9Φ 4 I 0 d = I 1 I 0 + 9Ψ 4 K 0 d = K 1 K 0 + 9Ψ K E 7

8 6 J 0 d = J J 0 5Φ 6 I 0 d = I I 0 + 5Ψ 6 K 0 d = K K 0 + 5Ψ K and so on 8 J 0 d = J J Φ 8 I 0 d = I I Ψ 10 J 0 d = J J Φ 10 I 0 d = I I Ψ 1 J 0 d = J 0 + Let J Φ 1 I 0 d = I I Ψ n!! = and n!! = 1 in the case n 0 General formulas: and + + n J 0 d = n 1 k=0 n { 4 n n, n = m 1 5 n n, n = m + 1 n 1 k n 1!!] n k 1 J 0 + n 1 k!!] n k!!] k=0 ] 1 k n 1!! n k J n n 1!!] Φ = n 1 k!! = n 1 k=0 k=0 1 k n!] n k! n k 1! n k 1 k+1 n! J 0 + n k! n k! ] 1 k n! n k! k n k n! n k! n k=0 n I 0 d = n 1 n 1!!] n k 1 n 1 k!!] n k!!] ] n! J n n Φ n! ] n 1!! n k I 1 n 1 k!! k=0 I 0 + n 1!!] Ψ = 8

9 n k=0 Recurrence formulas: = n 1 ] n! n k! k n k I 1 n! n k! k=0 n!] n k! n k 1! n k 1 k+1 n! n k! n k! ] n! I 0 + n Ψ n! n+ J 0 d = n + 1 n+1 J 0 + n+ J 1 n + 1 n+ I 0 d = n + 1 n+1 I 0 + n+ I 1 + n + 1 n+ K 0 d = n + 1 n+1 K 0 n+ K 1 + n + 1 n J 0 d n I 0 d n K 0 d In the case n < 0 the previous formulas give J0 d = J J 0 Φ I0 d = 1 I 0 I 1 + Ψ K0 d = 1 K 0 + K 1 + Ψ K J0 4 d = ] 9 J 0 1 J 1 + Φ I0 4 d = 1 4 ] 9 I I 1 + Ψ K0 4 d = 1 4 ] 9 K K 1 + Ψ K J0 6 d = J I0 6 d = I K ] K 1 + Ψ K K0 6 d = 1 5 J0 8 d = I0 8 d = ] J 0 Φ ] I 1 + Ψ and so on J ] 5 6 J 1 + Φ I J d = J I0 10 d = ] J 0 Φ I 0 9 ] I 1 + Ψ E E 9

10 ] I 1 + Ψ J0 1 d = I0 1 d = J ] J 1 + Φ I I 1 + Ψ General formula: With n!! as defined on page 8 holds J0 d 1 n n 1 n = n 1!!] + 1 k k + 1!! k 1!! k 1 J 0 k=0 ] n 1 1 k k + 1!!] k J 1 + Φ = k=0 = 1n n n! n! 1 n k=0 { n k k +! k! k+1 k + 1! k! k+1 J 0 1 k k+ k=0 ] } k +! k+1 J 1 + Φ k + 1! With obviously modifications one gets the the formulas for the integrals n I 0 d and n K 0 d ] 10

11 11 Integrals of the type n+1 Z 0 d In the following formulas J ν may be substituted by Y ν or H p ν, p = 1, J 0 d = J 1 I 0 d = I 1 K 0 d = K 1 J 0 d = J J 1 ] I 0 d = + 4 I 1 I 0 ] K 0 d = + 4 K 1 + K 0 ] 5 J 0 d = 4 J J 1 ] 5 I 0 d = I I 0 ] 5 K 0 d = K K 0 ] 7 J 0 d = J J 1 ] 7 I 0 d = I I 0 ] 7 K 0 d = K K 0 ] 9 J 0 d = = J J 1 ] 9 I 0 d = = I I 0 ] 9 K 0 d = = K K 0 ] Let m J 0 d = P m J 0 + Q m J 1 ] and m I 0 d = Q mi 1 P mi 0 ], m K 0 d = Q mk 1 + P mk 0 ], then holds P 11 = Q 11 = P11 = Q 11 = *E* 11

12 P 1 = Q 1 = P1 = Q 1 = P 15 = Q 15 = P 15 = = *E* Q 15 = Recurrence formulas: n+1 J 0 d = n n J 0 + n+1 J 1 4n n+1 I 0 d = n n I 0 + n+1 I 1 + 4n n+1 K 0 d = n n K 0 n+1 K 1 + 4n k=0 n 1 J 0 d General formula: With n!! as defined on page 8 holds n 1 n+1 J 0 d = 1 k n!!] n k n k!!] n k!!] = n 1 1 k k=0 n ] + 1 k n!! n+1 k J 1 = n k!! k=0 n J 0 + k+1 n! n k n k! n k 1! k=0 n 1 I 0 d n 1 K 0 d J 0 + ] 1 k k n! n+1 k J 1 n k! With obviously modifications one gets the the formulas for the integrals n+1 I 0 d and n+1 K 0 d *E* 1

13 11 Integrals of the type n 1 Z 0 d The basic integral J0 d can be epressed by 0 1 J 0 t t J 0 t dt dt or = Ji 0, t see 1], equation and the following formulas There are given asymptotic epansions and polynomial approimations as well Tables of these functions may be found by 1], 111] or 11] The function Ji 0 is introduced and discussed in 9] For fast computations of this integrals one should use approimations with Chebyshev polynomials, see ], tables 9 I got the information from F Nouguier, that there is an error in a formula in 9], p 78 The true formula is The power series in Ji 0 ln = sin π π I0 d can be used without numerical problems γ ln + sin π π = ln + k=1 s=1 1 s 1 s Ji 0s ln s] 1 k k k! E In the following formulas J ν may be substituted by Y ν or H ν p, p = 1, J0 d = J 0 + J J0 d 4 I0 d = I 0 I I0 d 4 J0 d 1 5 = J J J0 d 64 I0 d 1 5 = I I I0 d 64 J0 d 7 = J J 1 1 J0 d 04 I0 d 7 = I I I0 d 04 J0 d 9 = = J J 1 + I0 d 9 = = I I 1 + J0 d 11 = E J J0 d J I0 d 11 = I I J0 d I0 d I0 d 1

14 Descending recurrence formulas: n 1 J 0 d = 1 4n n 1 I 0 d = 1 4n n+1 J 1 n n J 0 n+1 I 1 n n I 0 + General formula: With n!! as defined on page 8 holds J0 d n+1 = ] n+1 J 0 d ] n+1 I 0 d { n 1 n 1 = 1n k k +!! k!! } n!!] 1 k+ J 0 1 k k!!] J0 d k+1 J 1 + = E k=0 k=0 { n 1 n 1 = 1n n n! 1 k k+1 k + 1! k! k+ J 0 1 k k k! } J0 d k+1 J 1 + E k=0 With obviously modifications one gets the the formula for the integral n 1 I 0 d k=0 14

15 114 Integrals of the type n Z 1 d In the following formulas J ν may be substituted by Y ν or H p ν, p = 1, J 1 d = J 0 I 1 d = I 0 K 1 d = K 0 J 1 d = J 1 J 0 ] I 1 d = I 0 I 1 ] K 1 d = K 0 + K 1 ] 4 J 1 d = 4 16 J 1 8 J 0 ] 4 I 1 d = + 8 I I 1 ] 4 K 1 d = + 8 K K 1 ] 6 J 1 d = J J 0 ] 6 I 1 d = I I 1 ] 6 K 1 d = K K 1 ] 8 J 1 d = = J J 0 ] 8 I 1 d = = I I 1 ] 8 K 1 d = = K K 1 ] 10 J 1 d = J J 0 ] 10 I 1 d = I I 1 ] 10 K 1 d = K

16 K 1 ] Let m J 1 d = Q m J 1 P m J 0 ] and m I 1 d = P mi 0 Q mi 1 ], m K 1 d = P mi 0 + Q mi 1 ], then holds P 1 = Q 1 = P 1 = Q 1 = *E* P 14 = Q 14 = P14 = Q 14 = Recurrence formulas: n+ J 1 d = n+ J 0 + n + n+1 J 1 4nn + 1 n J 1 d n+ I 1 d = n+ I 0 n + n+1 I 1 + 4nn + 1 n+ K 1 d = n+ K 0 n + n+1 K 1 + 4nn + 1 n I 1 d n K 1 d General formula: With n!! as defined on page 8 holds n 1 n k n!!] n!!] n 1 k J 1 d = 1 n k!!] = n 1 k=0 1 k k=0 n 1 k=0 n 1 n!! n!! n k n k!!] n k!!] J 0 = 1 k k+1 n! n 1! n 1 k n 1 k!] J 1 k=0 1 k k n! n 1!! n k J 0 n k! n 1 k! J 1 With obviously modifications one gets the the formulas for the integrals n I 1 d and n K 1 d 16

17 115 Integrals of the type n Z 1 d About the integrals see 11, page 1 J0 d and I0 d In the following formulas J 0 may be substituted by Y 0 and simultaneously J 1 by Y 1 J1 d = 1 J J0 d I1 d = 1 I I0 d J1 d 4 = 1 8 J J 1 1 J0 d 16 I1 d 4 = 1 8 I I I0 d 16 J1 d 6 = = J J J0 d 84 I1 d 6 = I I I0 d 84 J1 d 8 = = J J 1 1 J0 d 184 I1 d 8 = I I I0 d 184 J1 d 10 = Recurrence formulas: = J J J0 d I1 d 10 = = I I I0 d E E J1 d J 0 n+ = 4nn + 1 n I1 d I 0 n+ = 4nn + 1 n J 1 n + n+1 1 4nn + 1 I 1 n + n nn + 1 J1 d n I1 d n 17

18 General formula: With n!! as defined on page 8 holds J1 d 1 n+1 n = n!! n!! { n n 1 k k +!! k!! } 1 k+ J 0 1 k k!!] J0 d k+1 J 1 + = k=0 k=0 1 n+1 = n 1 n! n 1! n 1 1 k k+1 k + 1! k! k+ J 0 1 k k k! ] J0 d k+1 J 1 + n k=0 With obviously modifications one gets the the formula for the integral n I 1 d k=0 18

19 116 Integrals of the type n+1 Z 1 d Φ, Φ Y, Ψ and Ψ K are the same as in 111, page 7 In the following formulas J ν may be substituted by Y ν and simultaneously Φ by Φ Y or H ν p, p = 1, and Φ p H J 1 d = Φ I 1 d = Ψ K 1 d = Ψ K J 1 d = J 1 J 0 Φ I 1 d = I 1 + I 0 Ψ K 1 d = K 1 K 0 + Ψ K 5 J 1 d = J J Φ 5 I 1 d = I I 0 45Ψ 5 K 1 d = K K Ψ K 7 J 1 d = J J Φ E 7 I 1 d = I I Ψ 7 K 1 d = K K Ψ K 9 J 1 d = = J J Φ 9 I 1 d = = I I Ψ 9 K 1 d = = K K Ψ General formula: With n!! as defined on page 8 holds n 1 n+1 k n + 1!! n 1!! n k J 1 d = 1 n 1 k!!] J 1 n 1 k=0 k=0 k n + 1!! n 1!! n+1 k 1 J n n + 1!! n 1!! Φ = n + 1 k!! n 1 k!! 19

20 n 1 k=0 n 1 = 1 k n +! n! n k!] n k k+1 n + 1! n! n k!] J 1 k=0 k n +! n! n + 1 k! n k! n+1 k 1 k J 0 + n + 1! n! n + k! n k! + 1 n n +! n! n+1 n + 1! n! Φ With obviously modifications one gets the the formulas for the integrals n+1 I 1 d and n+1 K 1 d Recurrence formulas: n+1 J 1 d = n+1 J 0 + n + 1 n J 1 n 1n + 1 n 1 J 1 d n+1 I 1 d = n+1 I 0 n + 1 n I 1 + n 1n + 1 n+1 K 1 d = n+1 K 0 n + 1 n K 1 + n 1n + 1 n 1 I 1 d n 1 K 1 d Descending: J1 d J 0 n+1 = 4n 1 n 1 J 1 n + 1 n 1 J1 d 4n 1 n 1 I1 d I 0 n+1 = 4n 1 n 1 I 1 n + 1 n + 1 I1 d 4n 1 n 1 K1 d K 0 n+1 = 4n 1 n 1 K 1 n + 1 n + 1 K1 d 4n 1 n 1 J1 d = J 0 J 1 + Φ I1 d = I 0 I 1 + Ψ K1 d = K 0 K 1 Ψ K J1 d = 1 ] 1 J J 0 Φ I1 d = 1 ] + 1 I I 0 + Ψ K1 d = 1 ] + 1 K 1 1 K 0 Ψ K J1 5 d = J 0 4 ] J 1 + Φ I1 5 d = I ] I 1 + Ψ K1 5 d = K ] K 1 Ψ K J1 7 d = J ] J 0 Φ 0

21 I1 7 d = K1 7 d = = = = J1 11 d = 6 I K J1 9 d = 7 J I1 9 d = 7 I K1 9 d = ] I 0 + Ψ ] K 0 Ψ k ] J 1 + Φ ] I 1 + Ψ 7 K J I1 11 d = K1 11 d = 9 ] J 0 Φ I ] I 0 + Ψ K 0 + Ψ K General formula: With n!! as defined on page 8 holds { J1 d 1 n n+1 = + n + 1!! n 1!! n 1 k=0 ] ] I 1 Ψ K K 1 1 k k + 1!! k 1!! k+1 J 0 } n 1 k k + 1!!] 1 1 J 1 + Φ = k=0 k+ { = n+1 n 1 n + 1! n! 1 k k +! k! n +! n! k+1 k + 1! k! k+1 J 0 k=0 } n k k +!] k+ k + 1!] k+ J 1 + Φ k=0 With obviously modifications one gets the the formulas for the integrals n 1 I 1 d and n 1 K 1 d 1

22 117 Integrals of the type n Z ν d, ν > 1 : From the well-known recurrence relations one gets immadiately J ν+1 d = J ν + J ν 1 d and I ν+1 d = I ν I ν 1 d With this formulas follows J ν t dt = Λ 0 0 κ=1 n J κ 1, J ν+1 t dt = 1 J 0 0 κ=1 n J κ 0 I ν t dt = 1 n Λ 0+ n 1 n+κ I κ 1, κ=1 0 I ν+1 t dt = 1 n I 0 1]+ n 1 n+κ I κ The integrals Λ 0 and Λ 0 are defined on page 7 and discussed on page 104 and 106 Holds n n Y ν d = Y 0 + Φ Y Y κ 1, Y ν+1 d = Y 0 Y κ 1 H 1 ν H ν d = H1 0 + Φ1 d = H 0 + Φ κ=1 H n κ=1 H n κ=1 H 1 κ 1, H κ 1, H 1 ν+1 d = H1 H ν+1 d = H { K ν d = 1 n K 0 + π } K 0L 1 + K 1 L 0 ] + K ν+1 d = 1 n+1 K 0 + About the functions Φ Y, Φ 1 H, Φ H see page 7 Further on, holds t J ν+1 t dt = ν + 1Λ 0 J 0 + ] ν 1 t J ν t dt = J 1 + J κ+1 κ=1 t I ν+1 t dt = 1 ν+1 ν + 1Λ 0 I 0 κ=1 κ=1 κ=1 0 n κ=1 0 n κ=1 H 1 κ 1 H κ 1 n 1 n+κ K κ 1, κ=1 n 1 n+κ+1 K κ κ=1 ] ν J κ κ=1 ν 1 4 κ=0 ν 1 + ν1 J 0 ] 4 κ=1 ν κj κ+1 ν κj κ ] ν ν 1 1 κ I κ 4 1 κ ν κi κ+1 ] ν 1 ν 1 t I ν t dt = 1 I ν κ I κ+1 + ν1 I 0 ] 4 1 κ ν κi κ Some of the previous sums may cause numerical problems, if is located near 0 For instance, the sum 0 gives with = 0 t I 6 t dt = J 1 J + J J 0 + 8J 4J = = , κ=1 κ=0 κ=1

23 which means the loss of 10 decimal digits For that reason the value of such integrals should be computed by the power series or other formulas See also the following remark In the following the integrals are epressed by Z 0 and Z 1 Integrals with n 4 are written eplicitely: at first n = 0, 1,,, 4, after them n = 1, In the other cases the functions P ν n, Q n ν and the coefficients R n ν, S ν n describe the integral n J ν d = P ν n J 0 + Q n ν J 1 + R n ν Λ 0 + S ν n J0 d Furthermore, let n I ν d = P n, ν I 0 + Q n, ν I 1 + R n, ν Λ 0 + S ν n, I0 d Concerning 1 Z 0 d see 11, page 1 Simple recurrence formula: n J ν+1 d = ν n 1 J ν d n J ν 1 d n I ν+1 d = ν n 1 J ν d + n J ν 1 d The integrals of n Z 0 and n Z 1 to start this recurrences are already described Remark: Let F ν m denote the antiderivative of m Z ν as given in the following tables They do not eist in the point = 0 in the case ν + m < 0 However, even if ν + m 0 the value of F ν m 0 sometimes turns out to be a limit of the type For instance, holds J d = J 0 J 1 = F with lim F = With L ν,m = lim 0 F ν m for the Bessel functions J ν and L ν,m for the modified Bessel functions I ν one has the following limits in the tables of integrals The values L ν,m = 0 are omitted: L, 1 = 1/, L, 1 = 1/ L,0 = 1, L, = 1/8; L,0 = 1, L, = 1/8 L 4,1 = 4, L 4, 1 = 1/4, L 4, = 1/48; L 4,1 = 4, L 4, 1 = 1/4, L 4, = 1/48 L 5, = 4, L 5,0 = 1, L 5, = 1/4, L 5, 4 = 1/84; L 5, = 4, L 5,0 = 1, L 5, = 1/4, L 5, 4 = 1/84 L 6, = 19, L 6,1 = 6, L 6, 1 = 1/6, L 6, = 1/19, L 6, 5 = 1/840; L 6, = 19, L 6,1 = 6, L 6, 1 = 1/6, L 6, = 1/19, L 6, 5 = 1/840 L 7,4 = 190, L 7, = 48, L 7,0 = 1, L 7, = 1/48, L 7, 4 = 1/190, L 7, 6 = 1/46080; L 7,4 = 190, L 7, = 48, L 7,0 = 1, L 7, = 1/48, L 7, 4 = 1/190, L 7, 6 = 1/46080 L 8,5 = 040, L 8, = 480, L 8,1 = 8, L 8, 1 = 1/8, L 8, = 1/480, L 8, 5 = 1/040; L 8,5 = 040, L 8, = 480, L 8,1 = 8, L 8, 1 = 1/8, L 8, = 1/480, L 8, 5 = 1/040 L 9,6 = 560, L 9,4 = 5760, L 9, = 80, L 9,0 = 1, L 9, = 1/80, L 9, 4 = 1/5760, L 9, 6 = 1/560; L 9,6 = 560, L 9,4 = 5760, L 9, = 80, L 9,0 = 1, L 9, = 1/80, L 9, 4 = 1/5760, L 9, 6 = 1/560 L 10,7 = , L 10,5 = 80640, L 10, = 960, L 10,1 = 10, L 10, 1 = 1/10, L 10, = 1/960, L 10, 5 = 1/80640; L 10,7 = , L 10,5 = 80640, L 10, = 960, L 10,1 = 10, L 10, 1 = 1/10, L 10, = 1/960, L 10, 5 = 1/80640

24 In the described cases of limits of the type the numerical computation of F ν m causes difficulties, if 0 < << 1 Then it is preferable to use the power series, which has a fast convergengence for such values of With m + ν 0 holds 0 t m J ν t dt = m+ν+1 ν 1 k k k! ν + k! 4 k m + ν k k=0 and From this one has For instance, 0 t m I ν t dt = m+ν+1 ν F m ν = L ν,m k=0 k k! ν + k! 4 k m + ν k t m J ν t dt and F,m ν = L ν,m + J d = J 0 J = 0 t m I ν t dt = = = = It was a loss of seven decimal digits at = 000 This value may be found without problems by the power series: F 000 = = ] = = = In the previous value, signed by *, the last digit should be instead of 4 and the result had to finish with 8 The integrals with I ν may be computed in the same way This method can be used even if ν + m < 0 For instance, J 4 1 J 4 J 4 7 d = d d and the second integral is given in the following tables For the first one holds with the power series of the function J 4 1 J d = = d = 1 1 = d = = ln = = = = Here are no differences of nearly the same values = 4

25 Z : J d = J 1 + Λ 0 I d = I 1 Λ 0 J d = J 0 J 1 I d = I 0 + I 1 J d = J 0 J 1 + Λ 0 I d = I 0 + I 1 + Λ 0 J d = 4 J 0 8 J 1 I d = 4 I I 1 4 J d = 5 J 0 15 J 1 15Λ 0 4 I d = 5 + I I Λ 0 J d = J 1 I d = I 1 J d = 1 J 0 + J Λ 0 I d = 1 I 0 I Λ 0 P 5 = 6 8, Q 5 = , R 5 = 0, S 5 = 0 P 5, = 6 + 8, Q 5, = , R 5, = 0, S 5, = 0 P 6 = , Q 6 = , R 6 = 15, S 6 = 0 P 6, = , Q 6, = , R 6, = 15, S 6, = 0 P 7 = , Q 7 = , R 7 = 0, S 7 = 0 P 7, = , Q 7, = , R 7, = 0, S 7, = 0 P 8 = , Q 8 = , R 8 = 14175, S 8 = 0 P 8, = , Q 8, = , R 8, = 14175, S 8, = 0 P 9 = , Q 9 = , R 9 = 0, S 9 = 0 5

26 P 9, = , Q 9, = , R 9, = 0, S 9, = 0 P 10 = , Q 10 = , R 10 = , S 10 = 0 P 10, = , Q 10, = , R 10, = , S 10, = 0 P = 1 4, Q = + 4 8, R = 0, S = 1 8 P, = 1 4, Q, = 4 8, R, = 0, S, = 1 8 P 4 = 15, Q 4 = , R 4 = 1 15, S 4 = 0 P 4, = + 15, Q 4, = , R 4, = 1 15, S 4, = 0 P 5 = , Q 5 = , R 5 = 0, S 5 = 1 96 P 5, = , Q 5, = , R 5, = 0, S 5, = 1 96 P 6 = , Q 6 = , R 6 = 1 15, S 6 = 0 P 6, = , Q 6, = , R 6, = 1 15, S 6, = 0 Z : J d = J 0 4 J 1 I d = I 0 4 I 1 J d = J 0 8J 1 + Λ 0 I d = I 0 8I 1 + Λ 0 J d = 8J 0 6J 1 I d = + 8I 0 6I 1 J d = 15 J 0 7 J Λ 0 I d = + 15 I 0 7 I 1 15Λ 0 4 J d = 4 J J 1 4 I d = + 4 I I 1 J d = 4 J J Λ 0 6

27 I d = 4 I I 1 1 Λ 0 J d = J 0 J 1 I d = I 0 I 1 P 5 = , Q 5 = , R 5 = 105, S 5 = 0 P 5, = , Q 5, = , R 5, = 105, S 5, = 0 P 6 = , Q 6 = , R 6 = 0, S 6 = 0 P 6, = , Q 6, = , R 6, = 0, S 6, = 0 P 7 = , Q 7 = , R 7 = 85, S 7 = 0 P 7, = , Q 7, = , R 7, = 85, S 7, = 0 P 8 = , Q 8 = , R 8 = 0, S 8 = 0 P 8, = , Q 8, = , R 8, = 0, S 8, = 0 P 9 = , Q 9 = , R 9 = 15595, S 9 = 0 P 9, = , Q 9, = , R 9, = 15595, S 9, = 0 P 10 = , Q 10 = , R 10 = 0, S 10 = 0 P 10, = , Q 10, = , R 10, = 0, S 10, = 0 P = , Q = , R = 1 15, S = 0 P, = 1 15, Q, = , R, = 1 15, S, = 0 P 4 = , Q 4 = , R 4 = 0, S 4 = 1 48 P 4, = , Q 4, = , R 4, = 0, S 4, = 1 48 P 5 = , Q 5 = , R 5 = 1 105, S 5 = 0 P 5, = , Q 5, = , R 5, = 1 105, S 5, = 0 P 6 = , Q 6 = , R 6 = 0, S 6 = P 6, = , Q 6, = , R 6, = 0, S 6, =

28 Z 4 : J 4 d = 8J 0 16J 1 + Λ 0 I 4 d = 8I I 1 + Λ 0 J 4 d = 8J J 1 I 4 d = 8I I 1 J 4 d = 9J J Λ 0 I 4 d = 9I I 1 15Λ 0 J 4 d = 10 48J J 1 I 4 d = I I 1 4 J 4 d = J J Λ 0 4 I 4 d = I I Λ 0 J4 d = 6J J 1 I4 d = 6J J 1 J4 d = J J Λ 0 I4 d = 7 15 I I Λ 0 P 5 4 = , Q 5 4 = , R 5 4 = 0, S 5 4 = 0 P 5, 4 = , Q 5, 4 = , R 5, 4 = 0, S 5, 4 = 0 P 6 4 = , Q 6 4 = , R 6 4 = 945, S 6 4 = 0 P 6, 4 = , Q 6, 4 = , R 6, 4 = 945, S 6, 4 = 0 P 7 4 = , Q 7 4 = , R 7 4 = 0, S 7 4 = 0 P 7, 4 = , Q 7, 4 = , R 7, 4 = 0, S 7, 4 = 0 P 8 4 = , Q 8 4 = , R 8 4 = 1185, S 8 4 = 0 8

TABLES OF SOME INDEFINITE INTEGRALS OF BESSEL FUNCTIONS

TABLES OF SOME INDEFINITE INTEGRALS OF BESSEL FUNCTIONS Werner Rosenheinrich 191016 Ernst - Abbe - Hochschule Jena First variant: 40900 University of Applied Sciences Germany TABLES OF SOME INDEFINITE INTEGRALS OF BESSEL FUNCTIONS Integrals of the type J 0

Διαβάστε περισσότερα

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS CHAPTER 5 SOLVING EQUATIONS BY ITERATIVE METHODS EXERCISE 104 Page 8 1. Find the positive root of the equation x + 3x 5 = 0, correct to 3 significant figures, using the method of bisection. Let f(x) =

Διαβάστε περισσότερα

2 Composition. Invertible Mappings

2 Composition. Invertible Mappings Arkansas Tech University MATH 4033: Elementary Modern Algebra Dr. Marcel B. Finan Composition. Invertible Mappings In this section we discuss two procedures for creating new mappings from old ones, namely,

Διαβάστε περισσότερα

SPECIAL FUNCTIONS and POLYNOMIALS

SPECIAL FUNCTIONS and POLYNOMIALS SPECIAL FUNCTIONS and POLYNOMIALS Gerard t Hooft Stefan Nobbenhuis Institute for Theoretical Physics Utrecht University, Leuvenlaan 4 3584 CC Utrecht, the Netherlands and Spinoza Institute Postbox 8.195

Διαβάστε περισσότερα

Homework 3 Solutions

Homework 3 Solutions Homework 3 Solutions Igor Yanovsky (Math 151A TA) Problem 1: Compute the absolute error and relative error in approximations of p by p. (Use calculator!) a) p π, p 22/7; b) p π, p 3.141. Solution: For

Διαβάστε περισσότερα

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β 3.4 SUM AND DIFFERENCE FORMULAS Page Theorem cos(αβ cos α cos β -sin α cos(α-β cos α cos β sin α NOTE: cos(αβ cos α cos β cos(α-β cos α -cos β Proof of cos(α-β cos α cos β sin α Let s use a unit circle

Διαβάστε περισσότερα

Section 8.3 Trigonometric Equations

Section 8.3 Trigonometric Equations 99 Section 8. Trigonometric Equations Objective 1: Solve Equations Involving One Trigonometric Function. In this section and the next, we will exple how to solving equations involving trigonometric functions.

Διαβάστε περισσότερα

Math221: HW# 1 solutions

Math221: HW# 1 solutions Math: HW# solutions Andy Royston October, 5 7.5.7, 3 rd Ed. We have a n = b n = a = fxdx = xdx =, x cos nxdx = x sin nx n sin nxdx n = cos nx n = n n, x sin nxdx = x cos nx n + cos nxdx n cos n = + sin

Διαβάστε περισσότερα

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =? Teko Classes IITJEE/AIEEE Maths by SUHAAG SIR, Bhopal, Ph (0755) 3 00 000 www.tekoclasses.com ANSWERSHEET (TOPIC DIFFERENTIAL CALCULUS) COLLECTION # Question Type A.Single Correct Type Q. (A) Sol least

Διαβάστε περισσότερα

EE512: Error Control Coding

EE512: Error Control Coding EE512: Error Control Coding Solution for Assignment on Finite Fields February 16, 2007 1. (a) Addition and Multiplication tables for GF (5) and GF (7) are shown in Tables 1 and 2. + 0 1 2 3 4 0 0 1 2 3

Διαβάστε περισσότερα

ST5224: Advanced Statistical Theory II

ST5224: Advanced Statistical Theory II ST5224: Advanced Statistical Theory II 2014/2015: Semester II Tutorial 7 1. Let X be a sample from a population P and consider testing hypotheses H 0 : P = P 0 versus H 1 : P = P 1, where P j is a known

Διαβάστε περισσότερα

Fourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics

Fourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics Fourier Series MATH 211, Calculus II J. Robert Buchanan Department of Mathematics Spring 2018 Introduction Not all functions can be represented by Taylor series. f (k) (c) A Taylor series f (x) = (x c)

Διαβάστε περισσότερα

CRASH COURSE IN PRECALCULUS

CRASH COURSE IN PRECALCULUS CRASH COURSE IN PRECALCULUS Shiah-Sen Wang The graphs are prepared by Chien-Lun Lai Based on : Precalculus: Mathematics for Calculus by J. Stuwart, L. Redin & S. Watson, 6th edition, 01, Brooks/Cole Chapter

Διαβάστε περισσότερα

Concrete Mathematics Exercises from 30 September 2016

Concrete Mathematics Exercises from 30 September 2016 Concrete Mathematics Exercises from 30 September 2016 Silvio Capobianco Exercise 1.7 Let H(n) = J(n + 1) J(n). Equation (1.8) tells us that H(2n) = 2, and H(2n+1) = J(2n+2) J(2n+1) = (2J(n+1) 1) (2J(n)+1)

Διαβάστε περισσότερα

Matrices and Determinants

Matrices and Determinants Matrices and Determinants SUBJECTIVE PROBLEMS: Q 1. For what value of k do the following system of equations possess a non-trivial (i.e., not all zero) solution over the set of rationals Q? x + ky + 3z

Διαβάστε περισσότερα

Solutions to Exercise Sheet 5

Solutions to Exercise Sheet 5 Solutions to Eercise Sheet 5 jacques@ucsd.edu. Let X and Y be random variables with joint pdf f(, y) = 3y( + y) where and y. Determine each of the following probabilities. Solutions. a. P (X ). b. P (X

Διαβάστε περισσότερα

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch: HOMEWORK 4 Problem a For the fast loading case, we want to derive the relationship between P zz and λ z. We know that the nominal stress is expressed as: P zz = ψ λ z where λ z = λ λ z. Therefore, applying

Διαβάστε περισσότερα

4.6 Autoregressive Moving Average Model ARMA(1,1)

4.6 Autoregressive Moving Average Model ARMA(1,1) 84 CHAPTER 4. STATIONARY TS MODELS 4.6 Autoregressive Moving Average Model ARMA(,) This section is an introduction to a wide class of models ARMA(p,q) which we will consider in more detail later in this

Διαβάστε περισσότερα

DiracDelta. Notations. Primary definition. Specific values. General characteristics. Traditional name. Traditional notation

DiracDelta. Notations. Primary definition. Specific values. General characteristics. Traditional name. Traditional notation DiracDelta Notations Traditional name Dirac delta function Traditional notation x Mathematica StandardForm notation DiracDeltax Primary definition 4.03.02.000.0 x Π lim ε ; x ε0 x 2 2 ε Specific values

Διαβάστε περισσότερα

Bessel functions. ν + 1 ; 1 = 0 for k = 0, 1, 2,..., n 1. Γ( n + k + 1) = ( 1) n J n (z). Γ(n + k + 1) k!

Bessel functions. ν + 1 ; 1 = 0 for k = 0, 1, 2,..., n 1. Γ( n + k + 1) = ( 1) n J n (z). Γ(n + k + 1) k! Bessel functions The Bessel function J ν (z of the first kind of order ν is defined by J ν (z ( (z/ν ν Γ(ν + F ν + ; z 4 ( k k ( Γ(ν + k + k! For ν this is a solution of the Bessel differential equation

Διαβάστε περισσότερα

derivation of the Laplacian from rectangular to spherical coordinates

derivation of the Laplacian from rectangular to spherical coordinates derivation of the Laplacian from rectangular to spherical coordinates swapnizzle 03-03- :5:43 We begin by recognizing the familiar conversion from rectangular to spherical coordinates (note that φ is used

Διαβάστε περισσότερα

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

Chapter 6: Systems of Linear Differential. be continuous functions on the interval Chapter 6: Systems of Linear Differential Equations Let a (t), a 2 (t),..., a nn (t), b (t), b 2 (t),..., b n (t) be continuous functions on the interval I. The system of n first-order differential equations

Διαβάστε περισσότερα

The Simply Typed Lambda Calculus

The Simply Typed Lambda Calculus Type Inference Instead of writing type annotations, can we use an algorithm to infer what the type annotations should be? That depends on the type system. For simple type systems the answer is yes, and

Διαβάστε περισσότερα

Areas and Lengths in Polar Coordinates

Areas and Lengths in Polar Coordinates Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the

Διαβάστε περισσότερα

Srednicki Chapter 55

Srednicki Chapter 55 Srednicki Chapter 55 QFT Problems & Solutions A. George August 3, 03 Srednicki 55.. Use equations 55.3-55.0 and A i, A j ] = Π i, Π j ] = 0 (at equal times) to verify equations 55.-55.3. This is our third

Διαβάστε περισσότερα

Section 7.6 Double and Half Angle Formulas

Section 7.6 Double and Half Angle Formulas 09 Section 7. Double and Half Angle Fmulas To derive the double-angles fmulas, we will use the sum of two angles fmulas that we developed in the last section. We will let α θ and β θ: cos(θ) cos(θ + θ)

Διαβάστε περισσότερα

Areas and Lengths in Polar Coordinates

Areas and Lengths in Polar Coordinates Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the

Διαβάστε περισσότερα

6.3 Forecasting ARMA processes

6.3 Forecasting ARMA processes 122 CHAPTER 6. ARMA MODELS 6.3 Forecasting ARMA processes The purpose of forecasting is to predict future values of a TS based on the data collected to the present. In this section we will discuss a linear

Διαβάστε περισσότερα

Example Sheet 3 Solutions

Example Sheet 3 Solutions Example Sheet 3 Solutions. i Regular Sturm-Liouville. ii Singular Sturm-Liouville mixed boundary conditions. iii Not Sturm-Liouville ODE is not in Sturm-Liouville form. iv Regular Sturm-Liouville note

Διαβάστε περισσότερα

An Inventory of Continuous Distributions

An Inventory of Continuous Distributions Appendi A An Inventory of Continuous Distributions A.1 Introduction The incomplete gamma function is given by Also, define Γ(α; ) = 1 with = G(α; ) = Z 0 Z 0 Z t α 1 e t dt, α > 0, >0 t α 1 e t dt, α >

Διαβάστε περισσότερα

PARTIAL NOTES for 6.1 Trigonometric Identities

PARTIAL NOTES for 6.1 Trigonometric Identities PARTIAL NOTES for 6.1 Trigonometric Identities tanθ = sinθ cosθ cotθ = cosθ sinθ BASIC IDENTITIES cscθ = 1 sinθ secθ = 1 cosθ cotθ = 1 tanθ PYTHAGOREAN IDENTITIES sin θ + cos θ =1 tan θ +1= sec θ 1 + cot

Διαβάστε περισσότερα

SCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions

SCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions SCHOOL OF MATHEMATICAL SCIENCES GLMA Linear Mathematics 00- Examination Solutions. (a) i. ( + 5i)( i) = (6 + 5) + (5 )i = + i. Real part is, imaginary part is. (b) ii. + 5i i ( + 5i)( + i) = ( i)( + i)

Διαβάστε περισσότερα

C.S. 430 Assignment 6, Sample Solutions

C.S. 430 Assignment 6, Sample Solutions C.S. 430 Assignment 6, Sample Solutions Paul Liu November 15, 2007 Note that these are sample solutions only; in many cases there were many acceptable answers. 1 Reynolds Problem 10.1 1.1 Normal-order

Διαβάστε περισσότερα

Inverse trigonometric functions & General Solution of Trigonometric Equations. ------------------ ----------------------------- -----------------

Inverse trigonometric functions & General Solution of Trigonometric Equations. ------------------ ----------------------------- ----------------- Inverse trigonometric functions & General Solution of Trigonometric Equations. 1. Sin ( ) = a) b) c) d) Ans b. Solution : Method 1. Ans a: 17 > 1 a) is rejected. w.k.t Sin ( sin ) = d is rejected. If sin

Διαβάστε περισσότερα

Second Order Partial Differential Equations

Second Order Partial Differential Equations Chapter 7 Second Order Partial Differential Equations 7.1 Introduction A second order linear PDE in two independent variables (x, y Ω can be written as A(x, y u x + B(x, y u xy + C(x, y u u u + D(x, y

Διαβάστε περισσότερα

Approximation of distance between locations on earth given by latitude and longitude

Approximation of distance between locations on earth given by latitude and longitude Approximation of distance between locations on earth given by latitude and longitude Jan Behrens 2012-12-31 In this paper we shall provide a method to approximate distances between two points on earth

Διαβάστε περισσότερα

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ.

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ. Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο The time integral of a force is referred to as impulse, is determined by and is obtained from: Newton s 2 nd Law of motion states that the action

Διαβάστε περισσότερα

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required) Phys460.nb 81 ψ n (t) is still the (same) eigenstate of H But for tdependent H. The answer is NO. 5.5.5. Solution for the tdependent Schrodinger s equation If we assume that at time t 0, the electron starts

Διαβάστε περισσότερα

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R + Chapter 3. Fuzzy Arithmetic 3- Fuzzy arithmetic: ~Addition(+) and subtraction (-): Let A = [a and B = [b, b in R If x [a and y [b, b than x+y [a +b +b Symbolically,we write A(+)B = [a (+)[b, b = [a +b

Διαβάστε περισσότερα

2. THEORY OF EQUATIONS. PREVIOUS EAMCET Bits.

2. THEORY OF EQUATIONS. PREVIOUS EAMCET Bits. EAMCET-. THEORY OF EQUATIONS PREVIOUS EAMCET Bits. Each of the roots of the equation x 6x + 6x 5= are increased by k so that the new transformed equation does not contain term. Then k =... - 4. - Sol.

Διαβάστε περισσότερα

Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit

Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit Ting Zhang Stanford May 11, 2001 Stanford, 5/11/2001 1 Outline Ordinal Classification Ordinal Addition Ordinal Multiplication Ordinal

Διαβάστε περισσότερα

Partial Differential Equations in Biology The boundary element method. March 26, 2013

Partial Differential Equations in Biology The boundary element method. March 26, 2013 The boundary element method March 26, 203 Introduction and notation The problem: u = f in D R d u = ϕ in Γ D u n = g on Γ N, where D = Γ D Γ N, Γ D Γ N = (possibly, Γ D = [Neumann problem] or Γ N = [Dirichlet

Διαβάστε περισσότερα

Uniform Convergence of Fourier Series Michael Taylor

Uniform Convergence of Fourier Series Michael Taylor Uniform Convergence of Fourier Series Michael Taylor Given f L 1 T 1 ), we consider the partial sums of the Fourier series of f: N 1) S N fθ) = ˆfk)e ikθ. k= N A calculation gives the Dirichlet formula

Διαβάστε περισσότερα

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

Chapter 6: Systems of Linear Differential. be continuous functions on the interval Chapter 6: Systems of Linear Differential Equations Let a (t), a 2 (t),..., a nn (t), b (t), b 2 (t),..., b n (t) be continuous functions on the interval I. The system of n first-order differential equations

Διαβάστε περισσότερα

SCITECH Volume 13, Issue 2 RESEARCH ORGANISATION Published online: March 29, 2018

SCITECH Volume 13, Issue 2 RESEARCH ORGANISATION Published online: March 29, 2018 Journal of rogressive Research in Mathematics(JRM) ISSN: 2395-028 SCITECH Volume 3, Issue 2 RESEARCH ORGANISATION ublished online: March 29, 208 Journal of rogressive Research in Mathematics www.scitecresearch.com/journals

Διαβάστε περισσότερα

If we restrict the domain of y = sin x to [ π, π ], the restrict function. y = sin x, π 2 x π 2

If we restrict the domain of y = sin x to [ π, π ], the restrict function. y = sin x, π 2 x π 2 Chapter 3. Analytic Trigonometry 3.1 The inverse sine, cosine, and tangent functions 1. Review: Inverse function (1) f 1 (f(x)) = x for every x in the domain of f and f(f 1 (x)) = x for every x in the

Διαβάστε περισσότερα

ExpIntegralE. Notations. Primary definition. Specific values. Traditional name. Traditional notation. Mathematica StandardForm notation

ExpIntegralE. Notations. Primary definition. Specific values. Traditional name. Traditional notation. Mathematica StandardForm notation ExpIntegralE Notations Traditional name Exponential integral E Traditional notation E Mathematica StandardForm notation ExpIntegralE, Primary definition 06.34.0.000.0 E t t t ; Re 0 Specific values Specialied

Διαβάστε περισσότερα

Evaluation of some non-elementary integrals of sine, cosine and exponential integrals type

Evaluation of some non-elementary integrals of sine, cosine and exponential integrals type Noname manuscript No. will be inserted by the editor Evaluation of some non-elementary integrals of sine, cosine and exponential integrals type Victor Nijimbere Received: date / Accepted: date Abstract

Διαβάστε περισσότερα

If we restrict the domain of y = sin x to [ π 2, π 2

If we restrict the domain of y = sin x to [ π 2, π 2 Chapter 3. Analytic Trigonometry 3.1 The inverse sine, cosine, and tangent functions 1. Review: Inverse function (1) f 1 (f(x)) = x for every x in the domain of f and f(f 1 (x)) = x for every x in the

Διαβάστε περισσότερα

Finite Field Problems: Solutions

Finite Field Problems: Solutions Finite Field Problems: Solutions 1. Let f = x 2 +1 Z 11 [x] and let F = Z 11 [x]/(f), a field. Let Solution: F =11 2 = 121, so F = 121 1 = 120. The possible orders are the divisors of 120. Solution: The

Διαβάστε περισσότερα

Appendix to On the stability of a compressible axisymmetric rotating flow in a pipe. By Z. Rusak & J. H. Lee

Appendix to On the stability of a compressible axisymmetric rotating flow in a pipe. By Z. Rusak & J. H. Lee Appendi to On the stability of a compressible aisymmetric rotating flow in a pipe By Z. Rusak & J. H. Lee Journal of Fluid Mechanics, vol. 5 4, pp. 5 4 This material has not been copy-edited or typeset

Διαβάστε περισσότερα

Every set of first-order formulas is equivalent to an independent set

Every set of first-order formulas is equivalent to an independent set Every set of first-order formulas is equivalent to an independent set May 6, 2008 Abstract A set of first-order formulas, whatever the cardinality of the set of symbols, is equivalent to an independent

Διαβάστε περισσότερα

Other Test Constructions: Likelihood Ratio & Bayes Tests

Other Test Constructions: Likelihood Ratio & Bayes Tests Other Test Constructions: Likelihood Ratio & Bayes Tests Side-Note: So far we have seen a few approaches for creating tests such as Neyman-Pearson Lemma ( most powerful tests of H 0 : θ = θ 0 vs H 1 :

Διαβάστε περισσότερα

Tridiagonal matrices. Gérard MEURANT. October, 2008

Tridiagonal matrices. Gérard MEURANT. October, 2008 Tridiagonal matrices Gérard MEURANT October, 2008 1 Similarity 2 Cholesy factorizations 3 Eigenvalues 4 Inverse Similarity Let α 1 ω 1 β 1 α 2 ω 2 T =......... β 2 α 1 ω 1 β 1 α and β i ω i, i = 1,...,

Διαβάστε περισσότερα

Homework 8 Model Solution Section

Homework 8 Model Solution Section MATH 004 Homework Solution Homework 8 Model Solution Section 14.5 14.6. 14.5. Use the Chain Rule to find dz where z cosx + 4y), x 5t 4, y 1 t. dz dx + dy y sinx + 4y)0t + 4) sinx + 4y) 1t ) 0t + 4t ) sinx

Διαβάστε περισσότερα

Notations. Primary definition. Specific values. General characteristics. Traditional name. Traditional notation. Mathematica StandardForm notation

Notations. Primary definition. Specific values. General characteristics. Traditional name. Traditional notation. Mathematica StandardForm notation KelvinKei Notations Traditional name Kelvin function of the second kind Traditional notation kei Mathematica StandardForm notation KelvinKei Primary definition 03.5.0.000.0 kei kei 0 Specific values Values

Διαβάστε περισσότερα

9.09. # 1. Area inside the oval limaçon r = cos θ. To graph, start with θ = 0 so r = 6. Compute dr

9.09. # 1. Area inside the oval limaçon r = cos θ. To graph, start with θ = 0 so r = 6. Compute dr 9.9 #. Area inside the oval limaçon r = + cos. To graph, start with = so r =. Compute d = sin. Interesting points are where d vanishes, or at =,,, etc. For these values of we compute r:,,, and the values

Διαβάστε περισσότερα

forms This gives Remark 1. How to remember the above formulas: Substituting these into the equation we obtain with

forms This gives Remark 1. How to remember the above formulas: Substituting these into the equation we obtain with Week 03: C lassification of S econd- Order L inear Equations In last week s lectures we have illustrated how to obtain the general solutions of first order PDEs using the method of characteristics. We

Διαβάστε περισσότερα

Instruction Execution Times

Instruction Execution Times 1 C Execution Times InThisAppendix... Introduction DL330 Execution Times DL330P Execution Times DL340 Execution Times C-2 Execution Times Introduction Data Registers This appendix contains several tables

Διαβάστε περισσότερα

On the k-bessel Functions

On the k-bessel Functions International Mathematical Forum, Vol. 7, 01, no. 38, 1851-1857 On the k-bessel Functions Ruben Alejandro Cerutti Faculty of Exact Sciences National University of Nordeste. Avda. Libertad 5540 (3400) Corrientes,

Διαβάστε περισσότερα

CHAPTER 101 FOURIER SERIES FOR PERIODIC FUNCTIONS OF PERIOD

CHAPTER 101 FOURIER SERIES FOR PERIODIC FUNCTIONS OF PERIOD CHAPTER FOURIER SERIES FOR PERIODIC FUNCTIONS OF PERIOD EXERCISE 36 Page 66. Determine the Fourier series for the periodic function: f(x), when x +, when x which is periodic outside this rge of period.

Διαβάστε περισσότερα

Problem Set 3: Solutions

Problem Set 3: Solutions CMPSCI 69GG Applied Information Theory Fall 006 Problem Set 3: Solutions. [Cover and Thomas 7.] a Define the following notation, C I p xx; Y max X; Y C I p xx; Ỹ max I X; Ỹ We would like to show that C

Διαβάστε περισσότερα

Exercises 10. Find a fundamental matrix of the given system of equations. Also find the fundamental matrix Φ(t) satisfying Φ(0) = I. 1.

Exercises 10. Find a fundamental matrix of the given system of equations. Also find the fundamental matrix Φ(t) satisfying Φ(0) = I. 1. Exercises 0 More exercises are available in Elementary Differential Equations. If you have a problem to solve any of them, feel free to come to office hour. Problem Find a fundamental matrix of the given

Διαβάστε περισσότερα

Problem Set 9 Solutions. θ + 1. θ 2 + cotθ ( ) sinθ e iφ is an eigenfunction of the ˆ L 2 operator. / θ 2. φ 2. sin 2 θ φ 2. ( ) = e iφ. = e iφ cosθ.

Problem Set 9 Solutions. θ + 1. θ 2 + cotθ ( ) sinθ e iφ is an eigenfunction of the ˆ L 2 operator. / θ 2. φ 2. sin 2 θ φ 2. ( ) = e iφ. = e iφ cosθ. Chemistry 362 Dr Jean M Standard Problem Set 9 Solutions The ˆ L 2 operator is defined as Verify that the angular wavefunction Y θ,φ) Also verify that the eigenvalue is given by 2! 2 & L ˆ 2! 2 2 θ 2 +

Διαβάστε περισσότερα

Mock Exam 7. 1 Hong Kong Educational Publishing Company. Section A 1. Reference: HKDSE Math M Q2 (a) (1 + kx) n 1M + 1A = (1) =

Mock Exam 7. 1 Hong Kong Educational Publishing Company. Section A 1. Reference: HKDSE Math M Q2 (a) (1 + kx) n 1M + 1A = (1) = Mock Eam 7 Mock Eam 7 Section A. Reference: HKDSE Math M 0 Q (a) ( + k) n nn ( )( k) + nk ( ) + + nn ( ) k + nk + + + A nk... () nn ( ) k... () From (), k...() n Substituting () into (), nn ( ) n 76n 76n

Διαβάστε περισσότερα

Pg The perimeter is P = 3x The area of a triangle is. where b is the base, h is the height. In our case b = x, then the area is

Pg The perimeter is P = 3x The area of a triangle is. where b is the base, h is the height. In our case b = x, then the area is Pg. 9. The perimeter is P = The area of a triangle is A = bh where b is the base, h is the height 0 h= btan 60 = b = b In our case b =, then the area is A = = 0. By Pythagorean theorem a + a = d a a =

Διαβάστε περισσότερα

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007 Οδηγίες: Να απαντηθούν όλες οι ερωτήσεις. Αν κάπου κάνετε κάποιες υποθέσεις να αναφερθούν στη σχετική ερώτηση. Όλα τα αρχεία που αναφέρονται στα προβλήματα βρίσκονται στον ίδιο φάκελο με το εκτελέσιμο

Διαβάστε περισσότερα

Section 9.2 Polar Equations and Graphs

Section 9.2 Polar Equations and Graphs 180 Section 9. Polar Equations and Graphs In this section, we will be graphing polar equations on a polar grid. In the first few examples, we will write the polar equation in rectangular form to help identify

Διαβάστε περισσότερα

Arithmetical applications of lagrangian interpolation. Tanguy Rivoal. Institut Fourier CNRS and Université de Grenoble 1

Arithmetical applications of lagrangian interpolation. Tanguy Rivoal. Institut Fourier CNRS and Université de Grenoble 1 Arithmetical applications of lagrangian interpolation Tanguy Rivoal Institut Fourier CNRS and Université de Grenoble Conference Diophantine and Analytic Problems in Number Theory, The 00th anniversary

Διαβάστε περισσότερα

Second Order RLC Filters

Second Order RLC Filters ECEN 60 Circuits/Electronics Spring 007-0-07 P. Mathys Second Order RLC Filters RLC Lowpass Filter A passive RLC lowpass filter (LPF) circuit is shown in the following schematic. R L C v O (t) Using phasor

Διαβάστε περισσότερα

Lecture 34 Bootstrap confidence intervals

Lecture 34 Bootstrap confidence intervals Lecture 34 Bootstrap confidence intervals Confidence Intervals θ: an unknown parameter of interest We want to find limits θ and θ such that Gt = P nˆθ θ t If G 1 1 α is known, then P θ θ = P θ θ = 1 α

Διαβάστε περισσότερα

New bounds for spherical two-distance sets and equiangular lines

New bounds for spherical two-distance sets and equiangular lines New bounds for spherical two-distance sets and equiangular lines Michigan State University Oct 8-31, 016 Anhui University Definition If X = {x 1, x,, x N } S n 1 (unit sphere in R n ) and x i, x j = a

Διαβάστε περισσότερα

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1 Conceptual Questions. State a Basic identity and then verify it. a) Identity: Solution: One identity is cscθ) = sinθ) Practice Exam b) Verification: Solution: Given the point of intersection x, y) of the

Διαβάστε περισσότερα

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0.

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0. DESIGN OF MACHINERY SOLUTION MANUAL -7-1! PROBLEM -7 Statement: Design a double-dwell cam to move a follower from to 25 6, dwell for 12, fall 25 and dwell for the remader The total cycle must take 4 sec

Διαβάστε περισσότερα

Fractional Colorings and Zykov Products of graphs

Fractional Colorings and Zykov Products of graphs Fractional Colorings and Zykov Products of graphs Who? Nichole Schimanski When? July 27, 2011 Graphs A graph, G, consists of a vertex set, V (G), and an edge set, E(G). V (G) is any finite set E(G) is

Διαβάστε περισσότερα

A summation formula ramified with hypergeometric function and involving recurrence relation

A summation formula ramified with hypergeometric function and involving recurrence relation South Asian Journal of Mathematics 017, Vol. 7 ( 1): 1 4 www.sajm-online.com ISSN 51-151 RESEARCH ARTICLE A summation formula ramified with hypergeometric function and involving recurrence relation Salahuddin

Διαβάστε περισσότερα

Congruence Classes of Invertible Matrices of Order 3 over F 2

Congruence Classes of Invertible Matrices of Order 3 over F 2 International Journal of Algebra, Vol. 8, 24, no. 5, 239-246 HIKARI Ltd, www.m-hikari.com http://dx.doi.org/.2988/ija.24.422 Congruence Classes of Invertible Matrices of Order 3 over F 2 Ligong An and

Διαβάστε περισσότερα

Durbin-Levinson recursive method

Durbin-Levinson recursive method Durbin-Levinson recursive method A recursive method for computing ϕ n is useful because it avoids inverting large matrices; when new data are acquired, one can update predictions, instead of starting again

Διαβάστε περισσότερα

Solution Series 9. i=1 x i and i=1 x i.

Solution Series 9. i=1 x i and i=1 x i. Lecturer: Prof. Dr. Mete SONER Coordinator: Yilin WANG Solution Series 9 Q1. Let α, β >, the p.d.f. of a beta distribution with parameters α and β is { Γ(α+β) Γ(α)Γ(β) f(x α, β) xα 1 (1 x) β 1 for < x

Διαβάστε περισσότερα

Similarly, we may define hyperbolic functions cosh α and sinh α from the unit hyperbola

Similarly, we may define hyperbolic functions cosh α and sinh α from the unit hyperbola Universit of Hperbolic Functions The trigonometric functions cos α an cos α are efine using the unit circle + b measuring the istance α in the counter-clockwise irection along the circumference of the

Διαβάστε περισσότερα

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8  questions or comments to Dan Fetter 1 Eon : Fall 8 Suggested Solutions to Problem Set 8 Email questions or omments to Dan Fetter Problem. Let X be a salar with density f(x, θ) (θx + θ) [ x ] with θ. (a) Find the most powerful level α test

Διαβάστε περισσότερα

ω ω ω ω ω ω+2 ω ω+2 + ω ω ω ω+2 + ω ω+1 ω ω+2 2 ω ω ω ω ω ω ω ω+1 ω ω2 ω ω2 + ω ω ω2 + ω ω ω ω2 + ω ω+1 ω ω2 + ω ω+1 + ω ω ω ω2 + ω

ω ω ω ω ω ω+2 ω ω+2 + ω ω ω ω+2 + ω ω+1 ω ω+2 2 ω ω ω ω ω ω ω ω+1 ω ω2 ω ω2 + ω ω ω2 + ω ω ω ω2 + ω ω+1 ω ω2 + ω ω+1 + ω ω ω ω2 + ω 0 1 2 3 4 5 6 ω ω + 1 ω + 2 ω + 3 ω + 4 ω2 ω2 + 1 ω2 + 2 ω2 + 3 ω3 ω3 + 1 ω3 + 2 ω4 ω4 + 1 ω5 ω 2 ω 2 + 1 ω 2 + 2 ω 2 + ω ω 2 + ω + 1 ω 2 + ω2 ω 2 2 ω 2 2 + 1 ω 2 2 + ω ω 2 3 ω 3 ω 3 + 1 ω 3 + ω ω 3 +

Διαβάστε περισσότερα

Right Rear Door. Let's now finish the door hinge saga with the right rear door

Right Rear Door. Let's now finish the door hinge saga with the right rear door Right Rear Door Let's now finish the door hinge saga with the right rear door You may have been already guessed my steps, so there is not much to describe in detail. Old upper one file:///c /Documents

Διαβάστε περισσότερα

Lecture 2. Soundness and completeness of propositional logic

Lecture 2. Soundness and completeness of propositional logic Lecture 2 Soundness and completeness of propositional logic February 9, 2004 1 Overview Review of natural deduction. Soundness and completeness. Semantics of propositional formulas. Soundness proof. Completeness

Διαβάστε περισσότερα

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013 Notes on Average Scattering imes and Hall Factors Jesse Maassen and Mar Lundstrom Purdue University November 5, 13 I. Introduction 1 II. Solution of the BE 1 III. Exercises: Woring out average scattering

Διαβάστε περισσότερα

Parametrized Surfaces

Parametrized Surfaces Parametrized Surfaces Recall from our unit on vector-valued functions at the beginning of the semester that an R 3 -valued function c(t) in one parameter is a mapping of the form c : I R 3 where I is some

Διαβάστε περισσότερα

ORDINAL ARITHMETIC JULIAN J. SCHLÖDER

ORDINAL ARITHMETIC JULIAN J. SCHLÖDER ORDINAL ARITHMETIC JULIAN J. SCHLÖDER Abstract. We define ordinal arithmetic and show laws of Left- Monotonicity, Associativity, Distributivity, some minor related properties and the Cantor Normal Form.

Διαβάστε περισσότερα

Computing the Macdonald function for complex orders

Computing the Macdonald function for complex orders Macdonald p. 1/1 Computing the Macdonald function for complex orders Walter Gautschi wxg@cs.purdue.edu Purdue University Macdonald p. 2/1 Integral representation K ν (x) = complex order ν = α + iβ e x

Διαβάστε περισσότερα

GAUSS-LAGUERRE AND GAUSS-HERMITE QUADRATURE ON 64, 96 AND 128 NODES

GAUSS-LAGUERRE AND GAUSS-HERMITE QUADRATURE ON 64, 96 AND 128 NODES GAUSS-LAGUERRE AND GAUSS-HERMITE QUADRATURE ON 64, 96 AND 128 NODES RICHARD J. MATHAR Abstract. The manuscript provides tables of abscissae and weights for Gauss- Laguerre integration on 64, 96 and 128

Διαβάστε περισσότερα

6.1. Dirac Equation. Hamiltonian. Dirac Eq.

6.1. Dirac Equation. Hamiltonian. Dirac Eq. 6.1. Dirac Equation Ref: M.Kaku, Quantum Field Theory, Oxford Univ Press (1993) η μν = η μν = diag(1, -1, -1, -1) p 0 = p 0 p = p i = -p i p μ p μ = p 0 p 0 + p i p i = E c 2 - p 2 = (m c) 2 H = c p 2

Διαβάστε περισσότερα

( ) 2 and compare to M.

( ) 2 and compare to M. Problems and Solutions for Section 4.2 4.9 through 4.33) 4.9 Calculate the square root of the matrix 3!0 M!0 8 Hint: Let M / 2 a!b ; calculate M / 2!b c ) 2 and compare to M. Solution: Given: 3!0 M!0 8

Διαβάστε περισσότερα

Strain gauge and rosettes

Strain gauge and rosettes Strain gauge and rosettes Introduction A strain gauge is a device which is used to measure strain (deformation) on an object subjected to forces. Strain can be measured using various types of devices classified

Διαβάστε περισσότερα

Lecture 15 - Root System Axiomatics

Lecture 15 - Root System Axiomatics Lecture 15 - Root System Axiomatics Nov 1, 01 In this lecture we examine root systems from an axiomatic point of view. 1 Reflections If v R n, then it determines a hyperplane, denoted P v, through the

Διαβάστε περισσότερα

The k-α-exponential Function

The k-α-exponential Function Int Journal of Math Analysis, Vol 7, 213, no 11, 535-542 The --Exponential Function Luciano L Luque and Rubén A Cerutti Faculty of Exact Sciences National University of Nordeste Av Libertad 554 34 Corrientes,

Διαβάστε περισσότερα

DERIVATION OF MILES EQUATION FOR AN APPLIED FORCE Revision C

DERIVATION OF MILES EQUATION FOR AN APPLIED FORCE Revision C DERIVATION OF MILES EQUATION FOR AN APPLIED FORCE Revision C By Tom Irvine Email: tomirvine@aol.com August 6, 8 Introduction The obective is to derive a Miles equation which gives the overall response

Διαβάστε περισσότερα

A Note on Intuitionistic Fuzzy. Equivalence Relation

A Note on Intuitionistic Fuzzy. Equivalence Relation International Mathematical Forum, 5, 2010, no. 67, 3301-3307 A Note on Intuitionistic Fuzzy Equivalence Relation D. K. Basnet Dept. of Mathematics, Assam University Silchar-788011, Assam, India dkbasnet@rediffmail.com

Διαβάστε περισσότερα

The ε-pseudospectrum of a Matrix

The ε-pseudospectrum of a Matrix The ε-pseudospectrum of a Matrix Feb 16, 2015 () The ε-pseudospectrum of a Matrix Feb 16, 2015 1 / 18 1 Preliminaries 2 Definitions 3 Basic Properties 4 Computation of Pseudospectrum of 2 2 5 Problems

Διαβάστε περισσότερα

Trigonometric Formula Sheet

Trigonometric Formula Sheet Trigonometric Formula Sheet Definition of the Trig Functions Right Triangle Definition Assume that: 0 < θ < or 0 < θ < 90 Unit Circle Definition Assume θ can be any angle. y x, y hypotenuse opposite θ

Διαβάστε περισσότερα

Potential Dividers. 46 minutes. 46 marks. Page 1 of 11

Potential Dividers. 46 minutes. 46 marks. Page 1 of 11 Potential Dividers 46 minutes 46 marks Page 1 of 11 Q1. In the circuit shown in the figure below, the battery, of negligible internal resistance, has an emf of 30 V. The pd across the lamp is 6.0 V and

Διαβάστε περισσότερα

F-TF Sum and Difference angle

F-TF Sum and Difference angle F-TF Sum and Difference angle formulas Alignments to Content Standards: F-TF.C.9 Task In this task, you will show how all of the sum and difference angle formulas can be derived from a single formula when

Διαβάστε περισσότερα