Lecture 16 - Weyl s Character Formula I: The Weyl Function and the Kostant Partition Function

Σχετικά έγγραφα
Lecture 13 - Root Space Decomposition II

Lecture 10 - Representation Theory III: Theory of Weights

Lecture 15 - Root System Axiomatics

EE512: Error Control Coding

2 Composition. Invertible Mappings

Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit

Homework 3 Solutions

Fourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics

Finite Field Problems: Solutions

Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3

6.1. Dirac Equation. Hamiltonian. Dirac Eq.

Affine Weyl Groups. Gabriele Nebe. Summerschool GRK 1632, September Lehrstuhl D für Mathematik

Partial Differential Equations in Biology The boundary element method. March 26, 2013

2. THEORY OF EQUATIONS. PREVIOUS EAMCET Bits.

Example Sheet 3 Solutions

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

Approximation of distance between locations on earth given by latitude and longitude

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1

Areas and Lengths in Polar Coordinates

Math221: HW# 1 solutions

Every set of first-order formulas is equivalent to an independent set

Srednicki Chapter 55

ST5224: Advanced Statistical Theory II

SCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions

Matrices and Determinants

Areas and Lengths in Polar Coordinates

forms This gives Remark 1. How to remember the above formulas: Substituting these into the equation we obtain with

4.6 Autoregressive Moving Average Model ARMA(1,1)

Tridiagonal matrices. Gérard MEURANT. October, 2008

Congruence Classes of Invertible Matrices of Order 3 over F 2

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

Statistical Inference I Locally most powerful tests

Reminders: linear functions

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

Concrete Mathematics Exercises from 30 September 2016

5. Choice under Uncertainty

Section 8.3 Trigonometric Equations

Second Order Partial Differential Equations

3.2 Simple Roots and Weyl Group

CRASH COURSE IN PRECALCULUS

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:

g-selberg integrals MV Conjecture An A 2 Selberg integral Summary Long Live the King Ole Warnaar Department of Mathematics Long Live the King

Numerical Analysis FMN011

w o = R 1 p. (1) R = p =. = 1

C.S. 430 Assignment 6, Sample Solutions

Homomorphism in Intuitionistic Fuzzy Automata

( ) 2 and compare to M.

SCITECH Volume 13, Issue 2 RESEARCH ORGANISATION Published online: March 29, 2018

Fractional Colorings and Zykov Products of graphs

Nowhere-zero flows Let be a digraph, Abelian group. A Γ-circulation in is a mapping : such that, where, and : tail in X, head in

ω ω ω ω ω ω+2 ω ω+2 + ω ω ω ω+2 + ω ω+1 ω ω+2 2 ω ω ω ω ω ω ω ω+1 ω ω2 ω ω2 + ω ω ω2 + ω ω ω ω2 + ω ω+1 ω ω2 + ω ω+1 + ω ω ω ω2 + ω

Section 9.2 Polar Equations and Graphs

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ.

On the Galois Group of Linear Difference-Differential Equations

2. Let H 1 and H 2 be Hilbert spaces and let T : H 1 H 2 be a bounded linear operator. Prove that [T (H 1 )] = N (T ). (6p)

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0.

Inverse trigonometric functions & General Solution of Trigonometric Equations

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

Generating Set of the Complete Semigroups of Binary Relations

ORDINAL ARITHMETIC JULIAN J. SCHLÖDER

On a four-dimensional hyperbolic manifold with finite volume

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 6/5/2006

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +

Solution Series 9. i=1 x i and i=1 x i.

derivation of the Laplacian from rectangular to spherical coordinates

SOLVING CUBICS AND QUARTICS BY RADICALS

The challenges of non-stable predicates

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

Uniform Convergence of Fourier Series Michael Taylor

Other Test Constructions: Likelihood Ratio & Bayes Tests

Laplace Expansion. Peter McCullagh. WHOA-PSI, St Louis August, Department of Statistics University of Chicago

MINIMAL CLOSED SETS AND MAXIMAL CLOSED SETS

THE SECOND ISOMORPHISM THEOREM ON ORDERED SET UNDER ANTIORDERS. Daniel A. Romano

DIRECT PRODUCT AND WREATH PRODUCT OF TRANSFORMATION SEMIGROUPS

b. Use the parametrization from (a) to compute the area of S a as S a ds. Be sure to substitute for ds!

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013

Solutions to Exercise Sheet 5

CE 530 Molecular Simulation

Integrals in cylindrical, spherical coordinates (Sect. 15.7)

Trigonometric Formula Sheet

If we restrict the domain of y = sin x to [ π, π ], the restrict function. y = sin x, π 2 x π 2

1 String with massive end-points

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 24/3/2007

Lecture 2. Soundness and completeness of propositional logic

Homework 8 Model Solution Section

Quadratic Expressions

If we restrict the domain of y = sin x to [ π 2, π 2

A Two-Sided Laplace Inversion Algorithm with Computable Error Bounds and Its Applications in Financial Engineering

Similarly, we may define hyperbolic functions cosh α and sinh α from the unit hyperbola

Problem Set 9 Solutions. θ + 1. θ 2 + cotθ ( ) sinθ e iφ is an eigenfunction of the ˆ L 2 operator. / θ 2. φ 2. sin 2 θ φ 2. ( ) = e iφ. = e iφ cosθ.

The Simply Typed Lambda Calculus

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1

Parametrized Surfaces

Homomorphism of Intuitionistic Fuzzy Groups

About these lecture notes. Simply Typed λ-calculus. Types

Pg The perimeter is P = 3x The area of a triangle is. where b is the base, h is the height. In our case b = x, then the area is

Galatia SIL Keyboard Information

Tevfik Bilgin, Necat Gorentas, and I. Gokhan Kelebek

A Note on Intuitionistic Fuzzy. Equivalence Relation

Transcript:

Lecture 16 - Weyl s Character Formula I: The Weyl Function and the Kostant Partition Function March 22, 2013 References: A. Knapp, Lie Groups Beyond an Introduction. Ch V Fulton-Harris, Representation Theory. Ch 24, 25 R. Cahn, Semi-Simple Lie Algebras and Their Representations. Ch XIII 1 Formal Characters and Characters We defined a formal character to be any element in the group algebra over the weight lattice. We express such elements as formal linear combinations over e(λ), where the λ lie in the weight lattice in g. Given an irreducible representation V Λ (with, of course, Λ dominant integral), we define the representation s formal character to be χ Λ = λ N λ e(λ) (1) where λ ranges over the weights in the weight scheme of V Λ. Humphrey s handles formal characters in an awkward way, which we will not adopt. But to explain, for Humphreys the formal symbols e(λ) is interpreted to be a function on g, namely the characteristic function of λ. That is, e(λ)(x) = 0 if x λ, and e(λ)(λ) = 1. However this does not commute with the usual multiplication of formal characters (namely algebra multiplication in the group algebra), so Humphreys switches to a convolution-type multiplication. We will not do this. Instead, we treat e(λ) as the formal symbol e 2πiλ or Exp(2πiλ), and interpret it as an operator (nonlinear) on g as follows e 2πiλ (x) = e 2πi(λ, x) (2) 1

where the inner product is the Killing inner product. Formal characters are then functions on g, given by ch Λ (x) = λ N λ e 2πi(λ, x) (3) This interpretation is natural in the following sense. Given a (real) Lie group G with maximal torus H, we saw that H preserves the weight-space decomposition. Given a weight λ, we have a map, χ λ : H S 1 C, given (implicitly) by X.v λ = ξ λ (X) v λ. (4) for X H. This is called the multiplicative character of the representation. Now we have already see that H = Exp(2πi h), so if X = Exp(2πih) for some h h, then Then the formal character is ξ λ (h) = e 2πiλ(h) = e 2πi(λ, h ). (5) ( ch Λ (h ) = T r V Λ e 2πih ). (6) 2 Weyl s Function and Alternating Functions Given an algebra g with base and positive roots Φ +, consider the Weyl function Q Q = (e(α/2) e( α/2)) = e(δ) (1 e( α)) This is an alternating function, in the sense that if σ W, then σ Q Q σ = (det σ) Q. (8) To see this, note that if σ = σ β, β is a basic reflection, then σ β sends β to β and permutes the remaining roots. Then Q(σ β x) = (e ) πi(α, σβx) e πi(α, σ βx) = = (e πi(σ βα, x) e πi(σ βα, x) ) (e πi(σ ββ, x) e πi(σ ββ, x) ) = (e πi(β, x) e πi(β, x)) = Q(x) \{β} \{β} (e πi(σ βα, x) e πi(σ βα, x) ) (e πi(α, x) πi(α, e x)) (7) (9) 2

Now given any function T on g we can alternate it as follows. Define an operator on functions A = σ W (det σ) σ (10) (where the factor acts on functions via external multiplication) and compose with T to obtain We check T (σ α x) = σ W(det σ)t (σσ α x) T = AT. (11) = σ W(det σ α σ)t (σx) (12) = (det σ α ) σ W(det σ)t (σx) = (det σ α ) T (x). We compute a second useful expressions for Q. Proposition 2.1 (Weyl Denominator Formula) We have that Q is the alternation of e(δ). Specifically Q = A e(δ) Q(x) = = σ W(det σ)e(σδ) (det σ) e 2πi(σδ, x) = σ W σ W (det σ) e 2πi(δ, σx) (13) Pf. The highest weight exponential in Q is clearly e 1 2 α>0 α = e δ, while the lowest weight exponential is e( δ). Thus Q is the alternation of a sum of exponentials e(ρ) that can be expressed as follows: Q = A β e(δ β) (14) where the sum ranges over those β that are sums of positive roots. Since every root is W- conjugate to a dominant root, we only need consider those β so that δ β has non-negaitve Dynkin coefficients. However, if ρ has any Dynkin coefficient zero, then Ae(ρ) = 0. To see this, note that if (ρ, α i ) = 0, then σ i ρ = ρ where σ i is the reflection in α i. Then on the one hand σ i Ae(ρ) = Ae(ρ), and on the other σ i Ae(ρ) = Ae(σ i ρ) = Ae(ρ). Thus Ae(ρ) = 0. Therefore Q = Ae(δ) (15) 3

3 The Kostant Partition Formula If λ is any weight in the root lattice, meaning λ = α<0 n αα where n α Z, define P (λ) (16) to be the number of ways of expressing λ as a sum of positive roots (not counting multiplicities or order, so for instance 2α + β, β + α + α, and α + β + α count as just one way). Obviously if γ is a positive sum of negative roots, then P (γ) = 0. One use of the partition function is in expressing the character of a Verma module. We have that U(n ) is (vector-space) isomorphic to the polynomial generated by the y α for α Φ +, and that V Λ is a vector space over U(n ).v + where v + is any highest weight vector. Thus χ V Λ = µ P (Λ µ)e(µ) = e(λ) ν P (ν) e( ν) (17) where µ ranges over all points in the weight lattice and ν ranges over all points that are finite sums of roots with non-negative integral coefficients. Define K, which we will call the Kostant character, to be K = ν P (ν)e( ν) (18) so that χ V Λ = e(λ) K. Lemma 3.1 We have K = α>0 (1 + e( α) + e( 2α) +... ) (19) Pf. If ν is a positive sum of weights, then e( ν) is in the product on the right. Further, its coefficient is precisely the number of ways that e( ν) can be expressed as a product e( α)... e( ζ) for α,..., ζ Φ +. The following lemma gives the relation between the Kostant partition function and Q. Namely, K is just Q with a phase shift. Lemma 3.2 We have Q K = e(δ) (20) or Q(x) K(x) = e 2πi(δ, x) (21) 4

Pf. Since Q = (e(α/2) e( α/2)) = e δ e( α)) (22) α>0 α>0(1 we have e δ Q K = α>0(1 e( α)) (1 + e( α)... ) = 1. (23) Therefore Q ch V Λ = e(λ + δ). 5