Quantum Systems: Dynamics and Control 1

Σχετικά έγγραφα
Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

6.1. Dirac Equation. Hamiltonian. Dirac Eq.

CHAPTER 101 FOURIER SERIES FOR PERIODIC FUNCTIONS OF PERIOD

Problem Set 9 Solutions. θ + 1. θ 2 + cotθ ( ) sinθ e iφ is an eigenfunction of the ˆ L 2 operator. / θ 2. φ 2. sin 2 θ φ 2. ( ) = e iφ. = e iφ cosθ.

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:

Derivation of Optical-Bloch Equations

The Simply Typed Lambda Calculus

Second Order Partial Differential Equations

5. Choice under Uncertainty

derivation of the Laplacian from rectangular to spherical coordinates

The challenges of non-stable predicates

Abstract Storage Devices

General 2 2 PT -Symmetric Matrices and Jordan Blocks 1

Section 8.3 Trigonometric Equations

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ.

Reminders: linear functions

Matrices and Determinants

EE512: Error Control Coding

Approximation of distance between locations on earth given by latitude and longitude

ST5224: Advanced Statistical Theory II

Space-Time Symmetries

Solutions to the Schrodinger equation atomic orbitals. Ψ 1 s Ψ 2 s Ψ 2 px Ψ 2 py Ψ 2 pz

Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit

Homework 8 Model Solution Section

If we restrict the domain of y = sin x to [ π, π ], the restrict function. y = sin x, π 2 x π 2

If we restrict the domain of y = sin x to [ π 2, π 2

Solutions to Exercise Sheet 5

Bounding Nonsplitting Enumeration Degrees

Other Test Constructions: Likelihood Ratio & Bayes Tests

Example Sheet 3 Solutions

Numerical Analysis FMN011

2 Composition. Invertible Mappings

A Bonus-Malus System as a Markov Set-Chain. Małgorzata Niemiec Warsaw School of Economics Institute of Econometrics

Spherical Coordinates

Concrete Mathematics Exercises from 30 September 2016

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013

TMA4115 Matematikk 3

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

Fractional Colorings and Zykov Products of graphs

SUPERPOSITION, MEASUREMENT, NORMALIZATION, EXPECTATION VALUES. Reading: QM course packet Ch 5 up to 5.6

4.6 Autoregressive Moving Average Model ARMA(1,1)

Areas and Lengths in Polar Coordinates

Statistical Inference I Locally most powerful tests

C.S. 430 Assignment 6, Sample Solutions

Lecture 2. Soundness and completeness of propositional logic

Probability and Random Processes (Part II)

Solar Neutrinos: Fluxes

Information*Loss*and* Entanglement*in* Quantum*Theory* Jürg%Fröhlich% ETH%Zurich%&%IHES%

Strain gauge and rosettes

Every set of first-order formulas is equivalent to an independent set

Figure A.2: MPC and MPCP Age Profiles (estimating ρ, ρ = 2, φ = 0.03)..

Partial Differential Equations in Biology The boundary element method. March 26, 2013

Dynamic types, Lambda calculus machines Section and Practice Problems Apr 21 22, 2016

Areas and Lengths in Polar Coordinates

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +

Uniform Convergence of Fourier Series Michael Taylor

Congruence Classes of Invertible Matrices of Order 3 over F 2

Differentiation exercise show differential equation

Mock Exam 7. 1 Hong Kong Educational Publishing Company. Section A 1. Reference: HKDSE Math M Q2 (a) (1 + kx) n 1M + 1A = (1) =

What happens when two or more waves overlap in a certain region of space at the same time?

Quadratic Expressions

Homework 3 Solutions

The Pohozaev identity for the fractional Laplacian

2. Let H 1 and H 2 be Hilbert spaces and let T : H 1 H 2 be a bounded linear operator. Prove that [T (H 1 )] = N (T ). (6p)

w o = R 1 p. (1) R = p =. = 1

Integrals in cylindrical, spherical coordinates (Sect. 15.7)

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1

Θεωρητική Επιστήμη Υλικών

(1) Describe the process by which mercury atoms become excited in a fluorescent tube (3)

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

2. THEORY OF EQUATIONS. PREVIOUS EAMCET Bits.

Bayesian statistics. DS GA 1002 Probability and Statistics for Data Science.

6.3 Forecasting ARMA processes

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

HW 3 Solutions 1. a) I use the auto.arima R function to search over models using AIC and decide on an ARMA(3,1)

Exercise 1.1. Verify that if we apply GS to the coordinate basis Gauss form ds 2 = E(u, v)du 2 + 2F (u, v)dudv + G(u, v)dv 2

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

Inverse trigonometric functions & General Solution of Trigonometric Equations

CRASH COURSE IN PRECALCULUS

PARTIAL NOTES for 6.1 Trigonometric Identities

Differential equations

Quantum Statistical Mechanics (equilibrium) solid state, magnetism black body radiation neutron stars molecules lasers, superuids, superconductors

SCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions

Main source: "Discrete-time systems and computer control" by Α. ΣΚΟΔΡΑΣ ΨΗΦΙΑΚΟΣ ΕΛΕΓΧΟΣ ΔΙΑΛΕΞΗ 4 ΔΙΑΦΑΝΕΙΑ 1

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1

1. Αφετηρία από στάση χωρίς κριτή (self start όπου πινακίδα εκκίνησης) 5 λεπτά µετά την αφετηρία σας από το TC1B KALO LIVADI OUT

Math 6 SL Probability Distributions Practice Test Mark Scheme

5.4 The Poisson Distribution.

( ) 2 and compare to M.

Sequent Calculi for the Modal µ-calculus over S5. Luca Alberucci, University of Berne. Logic Colloquium Berne, July 4th 2008

ECE 308 SIGNALS AND SYSTEMS FALL 2017 Answers to selected problems on prior years examinations

1 String with massive end-points

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

HOMEWORK#1. t E(x) = 1 λ = (b) Find the median lifetime of a randomly selected light bulb. Answer:

1. (a) (5 points) Find the unit tangent and unit normal vectors T and N to the curve. r(t) = 3cost, 4t, 3sint

Finite Field Problems: Solutions

ΚΥΠΡΙΑΚΟΣ ΣΥΝΔΕΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY 21 ος ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ Δεύτερος Γύρος - 30 Μαρτίου 2011

forms This gives Remark 1. How to remember the above formulas: Substituting these into the equation we obtain with

b. Use the parametrization from (a) to compute the area of S a as S a ds. Be sure to substitute for ds!

Transcript:

Quantum Systems: Dynamics and Control 1 Mazyar Mirrahimi and Pierre Rouchon 3 February 7, 018 1 See the web page: http://cas.ensmp.fr/~rouchon/masterupmc/index.html INRIA Paris, QUANTIC research team 3 Mines ParisTech, QUANTIC research team

Outline 1 Photon Box: a key example Open quantum systems in discrete-time

Models of open quantum systems are based on three features 4 1 Schrödinger: wave funct. ψ H or density op. ρ ψ ψ d dt ψ = i H ψ, d dt ρ = i [H, ρ], H = H 0 + uh 1 Entanglement and tensor product for composite systems (S, M: Hilbert space H = H S H M Hamiltonian H = H S I M + H int + I S H M observable on sub-system M only: O = I S O M. 3 Randomness and irreversibility induced by the measurement of observable O with spectral decomp. µ λ µp µ : measurement outcome µ with proba. P µ = ψ P µ ψ = Tr (ρp µ depending on ψ, ρ just before the measurement measurement back-action if outcome µ = y: ψ ψ + = P y ψ ψ Py ψ, ρ ρ + = P yρp y Tr (ρp y 4 S. Haroche, J.M. Raimond: Exploring the Quantum: Atoms, Cavities and Photons. Oxford University Press, 006.

Composite system built with a harmonic oscillator and a qubit. System S corresponds to a quantized harmonic oscillator: { } H S = H c = c n n (c n n=0 l (C, n=0 where n represents the Fock state associated to exactly n photons inside the cavity Meter M is a qubit, a -level system (idem spin-1/ system : H M = H a = C, each atom admits two energy levels and is described by a wave function c g g + c e e with c g + c e = 1; atoms leaving B are all in state g State of the full system Ψ H S H M = H c H a : Ψ = + n=0 c ng n g + c ne n e, c ne, c ng C. Ortho-normal basis: ( n g, n e n N.

Markov model (1 R 1 R C D B B R When atom comes out B, Ψ B of the full system is separable Ψ B = ψ g. Just before the measurement in D, the state is in general entangled (not separable: ( ( Ψ R = U SM ψ g = Mg ψ g + ( M e ψ e where U SM is a unitary transformation (Schrödinger propagator defining the linear measurement operators M g and M e on H S. Since U SM is unitary, M gm g + M em e = I.

Markov model ( Just before D, the field/atom state is entangled: M g ψ g + M e ψ e Denote by µ {g, e} the measurement outcome in detector D: with probability P µ = ψ M µm µ ψ we get µ. Just after the measurement outcome µ = y, the state becomes separable: ( Ψ D = 1 (M y ψ y = Py M e ψ k ψk M e M e ψ k M y ψ M y M y ψ ψ y. Markov process: ψ k ψ t=k t, k N, t sampling period, M g ψ k with y k = g, probability P g = ψ k M gm g ψ k ; ψk M ψ k+1 = g M g ψ k with y k = e, probability P e = ψ k M em e ψ k.

Dispersive case U R1 = 1 (I + g e e g U R = 1 (I + e iη g e e iη e g U C = g g e iφ(n + e e e iφ(n+i where φ(n = ϑ 0 + ϑn. With η = (ϕ 0 ϑ 0 ϑ π, the measurement operators M g and M e are the following bounded operators: M g = cos(ϕ 0 + Nϑ, M e = sin(ϕ 0 + Nϑ up to irrelevant global phases. Exercise: Show that M gm g + M em e = I.

Resonant case: U SM = U R U C U R1 U R1 = e i θ 1 σ y = cos ( θ 1 + sin ( θ1 ( g e e g and ( U C = g g cos Θ ( N + e e cos ( Θ N + g e sin N Θ N + I a e g a and U R = I ( Θ sin N N The measurement operators M g and M e are the following bounded operators: ( M g = cos ( θ 1 ( cos Θ N sin ( Θ θ 1 sin N a M e = sin ( θ 1 ( cos Θ N + 1 cos ( θ 1 N a ( Θ sin N N Exercise: Show that M gm g + M em e = I.

Markov process with detection inefficiency With pure state ρ = ψ ψ, we have 1 ρ + = ψ + ψ + = ( M µ ρm Tr M µ ρm µ µ ( when the atom collapses in µ = g, e with proba. Tr M µ ρm µ. Detection efficiency: the probability to detect the atom is η [0, 1]. Three possible outcomes for y: y = g if detection in g, y = e if detection in e and y = 0 if no detection. The only possible update is based on ρ: expectation ρ + of ψ + ψ + knowing ρ and the outcome y {g, e, 0}. M gρm g Tr(M if y = g, probability η Tr (M gρm g gρm g ρ + = M eρm e Tr(M if y = e, probability η Tr (M eρm e eρm e M g ρm g + M e ρm e if y = 0, probability 1 η For η = 0: ρ + = M g ρm g + M e ρm e = K(ρ = E ( ρ + ρ defines a Kraus map.

LKB photon-box: Markov process with detection errors (1 With pure state ρ = ψ ψ, we have 1 ρ + = ψ + ψ + = ( M µ ρm Tr M µ ρm µ µ ( when the atom collapses in µ = g, e with proba. Tr M µ ρm µ. Detection error rates: P(y = e/µ = g = η g [0, 1] the probability of erroneous assignation to e when the atom collapses in g; P(y = g/µ = e = η e [0, 1] (given by the contrast of the Ramsey fringes. Bayesian law: expectation ρ + of ψ + ψ + knowing ρ and the imperfect detection y. (1 η gm gρm g +ηemeρm e ((1 Tr((1 η gm gρm g +η em eρm e if y = g, prob. Tr η gm gρm g + η em eρm e ; ρ + = η gm gρm g +(1 ηemeρm e (η Tr(η gm gρm g +(1 η em eρm e if y = e, prob. Tr gm gρm g + (1 η em eρm e. ρ + does not remain pure: the quantum state ρ + becomes a mixed state; ψ + becomes physically irrelevant.

LKB photon-box: Markov process with detection errors ( We get ρ + = (1 η gm gρm g +ηemeρm e Tr((1 η gm gρm g +η em eρm e, ((1 with prob. Tr η gm gρm g + η em eρm e ; η gm gρm g +(1 ηemeρm e Tr(η gm gρm g +(1 η em eρm e ( with prob. Tr η gm gρm g + (1 η em eρm e. Key point: ( Tr (1 η g M g ρm g + η e M e ρm e ( and Tr η g M g ρm g + (1 η e M e ρm e are the probabilities to detect y = g and e, knowing ρ. Reformulation with quantum maps : set K g (ρ = (1 η g M g ρm g+η e M e ρm e, K e (ρ = η g M g ρm g+(1 η e M e ρm e. ρ + = K y(ρ Tr (K y (ρ when we detect y The probability to detect y knowing ρ is Tr (K y (ρ. We have the following Kraus map: E ( ρ + ρ = K g (ρ + K e (ρ = K(ρ = M g ρm g + M e ρm e.

Outline 1 Photon Box: a key example Open quantum systems in discrete-time

General structure of Markov model in discrete time Any open model of quantum system in discrete time is governed by a Markov chain of the form ρ k+1 = K y k (ρ k Tr (K yk (ρ k, with the probability Tr (K yk (ρ k to have the measurement outcome y k knowing ρ k 1. The structure of the super-operators K y is as follows. Each K y is a linear completely positive map (a quantum operation, a partial Kraus map 5 and y K y(ρ = K(ρ is a Kraus map, i.e. K(ρ = µ K µρk µ with µ K µk µ = I. 5 Each K y admits the expression K y(ρ = µ K y,µρk y,µ where (K y,µ are bounded operators on H.

Schrödinger view point of ensemble average dynamics Without measurement record, the quantum state ρ k obeys to the master equation ρ k+1 = K(ρ k. since E (ρ k+1 ρ k = K(ρ k (ensemble average. K is always a contraction (not strict in general for the following two such metrics. For any density operators ρ and ρ we have K(ρ K(ρ 1 ρ ρ 1 and F (K(ρ, K(ρ F (ρ, ρ where the trace norm 1 and fidelity F are given by ( ρρ ρ ρ 1 Tr ( ρ ρ and F (ρ, ρ Tr ρ.