26. [Surface Area] sq. units. sq. units. Area of 1 face = Area: base & top = 2 20 3 = 120. Area: front & back = 2 30 3 = 180 S.A.



Σχετικά έγγραφα
24. [Surface Area] cm 2. Area: base & top = = 120. Area of 1 face = Area: front & back = = 180 TSA = =

(a,b) Let s review the general definitions of trig functions first. (See back cover of your book) sin θ = b/r cos θ = a/r tan θ = b/a, a 0

Volume of a Cuboid. Volume = length x breadth x height. V = l x b x h. The formula for the volume of a cuboid is

CHAPTER 12: PERIMETER, AREA, CIRCUMFERENCE, AND 12.1 INTRODUCTION TO GEOMETRIC 12.2 PERIMETER: SQUARES, RECTANGLES,

Example 1: THE ELECTRIC DIPOLE

Homework 8 Model Solution Section

Laplace s Equation in Spherical Polar Coördinates

Matrix Hartree-Fock Equations for a Closed Shell System

Section 7.6 Double and Half Angle Formulas

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:

Areas and Lengths in Polar Coordinates

Areas and Lengths in Polar Coordinates

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

PARTIAL NOTES for 6.1 Trigonometric Identities

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

derivation of the Laplacian from rectangular to spherical coordinates

Section 8.3 Trigonometric Equations

On a four-dimensional hyperbolic manifold with finite volume

( ) 2 and compare to M.

Homework 3 Solutions

2 Composition. Invertible Mappings

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 6/5/2006

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007

Fourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics

10/3/ revolution = 360 = 2 π radians = = x. 2π = x = 360 = : Measures of Angles and Rotations

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1

physicsandmathstutor.com

ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ. Ψηφιακή Οικονομία. Διάλεξη 7η: Consumer Behavior Mαρίνα Μπιτσάκη Τμήμα Επιστήμης Υπολογιστών

Advanced Subsidiary Unit 1: Understanding and Written Response

Potential Dividers. 46 minutes. 46 marks. Page 1 of 11

EE512: Error Control Coding

A, B. Before installation of the foam parts (A,B,C,D) into the chambers we put silicone around. We insert the foam parts in depth shown on diagram.

Mean bond enthalpy Standard enthalpy of formation Bond N H N N N N H O O O

1) Formulation of the Problem as a Linear Programming Model

ΠΑΝΕΠΙΣΤΗΜΙΟ ΠΑΤΡΩΝ ΠΟΛΥΤΕΧΝΙΚΗ ΣΧΟΛΗ ΤΜΗΜΑ ΜΗΧΑΝΙΚΩΝ Η/Υ & ΠΛΗΡΟΦΟΡΙΚΗΣ. του Γεράσιμου Τουλιάτου ΑΜ: 697

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

Space Physics (I) [AP-3044] Lecture 1 by Ling-Hsiao Lyu Oct Lecture 1. Dipole Magnetic Field and Equations of Magnetic Field Lines

Partial Trace and Partial Transpose

TMA4115 Matematikk 3

Στο εστιατόριο «ToDokimasesPrinToBgaleisStonKosmo?» έξω από τους δακτυλίους του Κρόνου, οι παραγγελίες γίνονται ηλεκτρονικά.

List MF19. List of formulae and statistical tables. Cambridge International AS & A Level Mathematics (9709) and Further Mathematics (9231)

Math 6 SL Probability Distributions Practice Test Mark Scheme

The Simply Typed Lambda Calculus

9.09. # 1. Area inside the oval limaçon r = cos θ. To graph, start with θ = 0 so r = 6. Compute dr

Section 9.2 Polar Equations and Graphs

CRASH COURSE IN PRECALCULUS

VBA ΣΤΟ WORD. 1. Συχνά, όταν ήθελα να δώσω ένα φυλλάδιο εργασίας με ασκήσεις στους μαθητές έκανα το εξής: Version ΗΜΙΤΕΛΗΣ!!!!

Finite Field Problems: Solutions

Δημιουργία Λογαριασμού Διαχείρισης Business Telephony Create a Management Account for Business Telephony

ΚΥΠΡΙΑΚΟΣ ΣΥΝΔΕΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY 21 ος ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ Δεύτερος Γύρος - 30 Μαρτίου 2011

Matrices and Determinants

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0.

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

Tutorial Note - Week 09 - Solution

If we restrict the domain of y = sin x to [ π, π ], the restrict function. y = sin x, π 2 x π 2

Test Data Management in Practice

Solution to Review Problems for Midterm III

b. Use the parametrization from (a) to compute the area of S a as S a ds. Be sure to substitute for ds!

If we restrict the domain of y = sin x to [ π 2, π 2

If ABC is any oblique triangle with sides a, b, and c, the following equations are valid. 2bc. (a) a 2 b 2 c 2 2bc cos A or cos A b2 c 2 a 2.

MATH 38061/MATH48061/MATH68061: MULTIVARIATE STATISTICS Solutions to Problems on Matrix Algebra

is like multiplying by the conversion factor of. Dividing by 2π gives you the

Parametrized Surfaces

How to register an account with the Hellenic Community of Sheffield.

14 Lesson 2: The Omega Verb - Present Tense

Fundamental Equations of Fluid Mechanics

Answer sheet: Third Midterm for Math 2339

Modbus basic setup notes for IO-Link AL1xxx Master Block

Pg The perimeter is P = 3x The area of a triangle is. where b is the base, h is the height. In our case b = x, then the area is

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Ordinary Level

4.2 Differential Equations in Polar Coordinates

Εγχειρίδια Μαθηµατικών και Χταποδάκι στα Κάρβουνα

Exercises to Statistics of Material Fatigue No. 5

Fractional Colorings and Zykov Products of graphs

) = ( 2 ) = ( -2 ) = ( -3 ) = ( 0. Solutions Key Spatial Reasoning. 225 Holt McDougal Geometry ARE YOU READY? PAGE 651

Διάρκεια μιας Ομολογίας (Duration) Ανοσοποίηση (Immunization)

Εργαστήριο Ανάπτυξης Εφαρμογών Βάσεων Δεδομένων. Εξάμηνο 7 ο

Chapter 5. Exercise 5A. Chapter minor arc AB = θ = 90 π = major arc AB = minor arc AB =

1999 MODERN GREEK 2 UNIT Z

Review Test 3. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Inverse trigonometric functions & General Solution of Trigonometric Equations

Εγκατάσταση λογισμικού και αναβάθμιση συσκευής Device software installation and software upgrade

Code Breaker. TEACHER s NOTES

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education

Oscillating dipole system Suppose we have two small spheres separated by a distance s. The charge on one sphere changes with time and is described by

Concrete Mathematics Exercises from 30 September 2016

Paper Reference. Paper Reference(s) 1776/04 Edexcel GCSE Modern Greek Paper 4 Writing. Thursday 21 May 2009 Afternoon Time: 1 hour 15 minutes

Analytical Expression for Hessian

e t e r Cylindrical and Spherical Coordinate Representation of grad, div, curl and 2

C.S. 430 Assignment 6, Sample Solutions

Second Order RLC Filters

2. Μηχανικό Μαύρο Κουτί: κύλινδρος με μια μπάλα μέσα σε αυτόν.

EPL 603 TOPICS IN SOFTWARE ENGINEERING. Lab 5: Component Adaptation Environment (COPE)

Instruction Execution Times

Ιστορία νεότερων Μαθηματικών

BRAND MANUAL AND USER GUIDELINES

ANTENNAS and WAVE PROPAGATION. Solution Manual

Ρολό Αλουμινίου Θζςεισ Σοποκζτθςθσ & Επιμζτρθςθ Βιβλίο 201 ο. Rolo Shutter Kind of Installation & Measurment Book 201st

Transcript:

6. [Suface Aea] Skill 6.1 Calculating the suface aea of ectangula pisms and cubes by using nets (1). Find any unknown side lengths. Calculate the aea of each face as shown on the net. Hint: Rectangula pisms have 6 faces of 3 diffeent sizes: base and top () font and back () othe faces () Add togethe the aea of all faces. Hints: Sides maked with a dash ( ) ae of equal length. Sides maked with two dashes ( ) ae of equal length etc. continues on page 306 Q. Find the suface aea of the cube by finding the aea of its net. 5 A. Aea of squae face = 5 units 5 units = 5 sq. units 5 6 = 150 sq. units A cube has 6 identical faces a) Find the suface aea of the ectangula pism by finding the aea of its net. b) Find the suface aea of the cube by finding the aea of its net. 30 0 F o n t Top B a c k 3 F o n t Top B a c k 6 Aea: base & top = 0 3 = 10 Aea: font & back = 30 3 = 180 Aea: othe faces = 30 0 = 100 10 + 180 + 100 =... sq. units Aea of 1 face = =... sq. units page 305 www.mathsmate.net

Skill 6.1 Calculating the suface aea of ectangula pisms and cubes by using nets (). c) Find the suface aea of the squae pism by finding the aea of its net. d) Find the suface aea of the ectangula pism by finding the aea of its net. continued fom page 305 Top 3 Back Top L a te f a ce 8 Top a l Font 1 0 5 Aea: base & top = Aea: 4 lateal faces = =... sq. units Aea: base & top = Aea: font & back = Aea: othe faces = =... sq. units e) Find the suface aea of the squae pism by finding the aea of its net. f) Find the suface aea of the ectangula pism by finding the aea of its net. 4 7 16 4 30 =... sq. units =... sq. units page 306 www.mathsmate.net

Skill 6. Calculating the suface aea of ectangula pisms. Substitute known values into the fomula: ectangula pism cube (length width) + (length height) + (width height) lw + lh + wh = (lw + lh + wh) 6(length length) = 6l l h w Q. Lewis wants to make a box, with a lid, fo his cad collection. The box needs a base of 11 cm by 0 cm and must be 1 cm high. How much wood does Lewis need? a) The locke block needs to be esufaced. What is the suface aea of this ectangula pism disegading its base? A. (lw + lh + wh) whee l = 0, w = 11 and h = 1 = (0 + 0 1 + 11 1) = (0 + 40 + 13) = 59 = 1184 b) Zoe s mattess was ton in emoval. What is the minimum amount of mattess ticking needed to e-cove the mattess? 1.5 yd Subtact 1 base aea 55 cm lw + lh + wh whee l = 110, w = 55 and h = 190 = 110 55 + (110 190) + (55 190) = 6050 + 0,900 + 10,450 = 6050 + 41,800 + 0,900 = 110 cm 190 cm yd 0.5 yd (lw + lh + wh) = = yd c) Find the suface aea of the micowave. 30 cm d) The suface aea of the ectangula pism is 5 squae inches. What is the S.A. if all the dimensions ae doubled? 4 in. in. 50 cm 35 cm 3 in. = = = = page 307 www.mathsmate.net

Skill 6.3 Calculating the suface aea of ectangula composite solids (1). Find any unknown side lengths. Calculate the aea of each face. Add togethe the aea of all faces. OR Identify the base by finding the two, identical paallel faces. Hint: A pism does not necessaily sit on its base. Substitute values into the fomula: continues on page 309 ectangula composite solid Peimete of base height + Aea of base Ph + B h Q. Find the suface aea of the pism. A. 1 in. OR 6 in. 1 in. 6 + 1 + 5 + 1 + 1 + = 16 6 + 6 + + = 16 1 in. 5 in. 5 in. base 6 in. base 6 in. 1 in. in. h = in. in. B = 5 1 + 1 = 5 + = 7 Ph + B whee h = = 16 + 7 = 3 + 14 = 46 Fo P, convet to a ectangle Find unknown side lengths a) Find the suface aea of the pism. 3 cm Fo P, convet to a ectangle Fo B, find all unknown side lengths b) Find the suface aea of the pism. 7 ft 10 cm 10 cm 5 cm 5 cm 5 cm 10 ft 10 + 10 + 8 + 8 = 36 B = 5 5 + 5 8 = 5 + 40 = 65 Ph + B whee h = 3 = 36 3 + 65 = 108 + 130 = B = Ph + B = ft page 308 www.mathsmate.net

Skill 6.3 Calculating the suface aea of ectangula composite solids (). c) Find the suface aea of the pism. 10 m Find unknown side lengths d) Find the suface aea of the pism. 6 yd 4 yd 3 yd continued fom page 308 4 m B = Ph + B whee h = yd B = Ph + B = = m yd e) A window m by 1.5 m and a dooway m by 0.8 m ae in the plan fo this oom. Find the aea of the walls to be painted. 5 m f) Find the suface aea of the pism. 4 m 3 m 9 in. = g) Find the suface aea of the pism. 40 ft 10 ft m = h) Find the suface aea of the pism. 5 cm 3 cm 1 = ft = page 309 www.mathsmate.net

Skill 6.4 Calculating the suface aea of tiangula pisms (1). Find any unknown side lengths. Calculate the aea of each face. Add togethe the aea of all faces. OR Substitute values into the fomula: continues on page 311 tiangula pism Peimete of base height + Aea of base Ph + B h Hint: Do not confuse the height needed to calculate the aea of the tiangula base, with the height (h) of the pism. Q. Find the suface aea of the tiangula pism. A. 6 + 5 + 5 = 16 1 6 cm B = bh whee b = 6, h = 4 4 cm 1 7 cm = (6 4) = 1 5 cm Ph + B whee h = 7 = 16 7 + 1 = 11 + 4 = 136 b h a) Find the suface aea of the tiangula pism. b) Find the suface aea of the tiangula pism. 8 in. 3 in. 5 cm 6 in. 10 in. 1 cm 1 + 1 + 1 = 36 1 A = (1 8) = 48 Ph + B whee h = 5 = 36 5 + 48 = 900 + 96 = Fist find the peimete of base Then find the aea of base A = = page 310 www.mathsmate.net

Skill 6.4 Calculating the suface aea of tiangula pisms (). c) Find the suface aea of the tiangula pism. 5 mm 0 mm d) Find the suface aea of the tiangula pism of cheese. in. 3 in. continued fom page 310 1 mm 1 in. 16 mm.5 in. B = Ph + B whee h = B = = = mm e) Find the suface aea of the tiangula pism. f) Find the suface aea of the tiangula pism. 10 in. 5 ft 5 ft 8 in. 6 in. 6.5 ft 6 in. 6 ft B = B = = = ft page 311 www.mathsmate.net

Skill 6.5 Calculating the suface aea of pyamids (1). Find any unknown side lengths. Calculate the aea of each face. Add togethe the aea of all faces. OR Substitute values into the fomula: egula squae pyamid Aea of base + 4 Aea of tiangle 1 B + 4 ls l + ls l continues on page 313 s l egula tiangula pyamid (egula tetahedon) 4 Aea of equilateal tiangle 1 x 3 4 x x 3 x x 3 ectangula pyamid Aea of base + Aea of tiangles left & ight + Aea of tiangles font & back 1 1 B + ws 1 + ls s 1 s lw + ws 1 + ls l w Q. Find the suface aea of the egula squae pyamid. 8 ft 1 ft a) Find the suface aea of the egula squae pyamid. 5 in. A. l + ls whee l = 8 and s = 1 = 8 8 + 8 1 = 64 + 16 1 = 64 + 19 = 56 ft b) Find the suface aea of one of the salt and peppe shakes given that they ae egula, squae pyamids of base side length 3 cm and slant height 4 cm. 6 in. l + ls whee l = 5 and s = 6 = 5 5 + 5 6 = 5 + 60 = l + ls = page 31 www.mathsmate.net

Skill 6.5 Calculating the suface aea of pyamids (). c) Find the suface aea of the lagest egula squae pyamid, which has a base side length of 00 m and slant height of 50 m. continued fom page 31 d) Find the suface aea of the egula squae pyamid. 18 mm 1 mm = m = mm e) Find the suface aea of the egula squae pyamid. f) Find the suface aea of the ectangula pyamid. 64 ft 40 ft 64 ft 15 in. 40 in. 14 in.4 in. = ft = g) Find the suface aea of the egula tetahedon. [Give you answe as a adical.] h) Find the suface aea of the egula tetahedon. [Give you answe as a adical.] 3 3 cm 1 ft 6 cm = = ft page 313 www.mathsmate.net

Skill 6.6 Calculating the suface aea of composite solids (1). Beak the solid into wokable pats. Substitute values into the appopiate fomula fo suface aea. (see skills 6. to 6.5, pages 307 to 31) continues on page 315 Q. Find the total suface aea of the obelisk. A. S.A. egula squae pyamid (without base) = ls whee l = 8 and s = 10 10 mm 8 mm = 8 10 = 160 S.A. squae pism (without base) 15 mm = 4lh + l whee l = 8 and h = 15 = 4 (8 15) + 8 8 = 4 10 + 64 = 544 S.A. obelisk = 160 + 544 = 704 mm a) Find the suface aea of the solid. 1 36, B = (10 1) = 60 and h = 10 S.A. pism = Ph + B = 36 10 + 60 = 480 S.A. pism face = 480 100 = 380 S.A. cube face = 5l = 5 100 = 500 S.A. solid = 380 + 500 = m c) Find the suface aea of the glasshouse, excluding its base. 4 m h = 10 (height) Find S.A. of the cube without the top face 6 m 13 m 1 m Find S.A. of the tiangula pism without the face that sits on the cube 10 m 0 m l = 10 (height) 5 m 5 m b) Find the suface aea of the solid. 8 in. 15 in. 17 in. = d) Find the suface aea of the obelisk. 10 yd 4 yd 5 yd = m = yd page 314 www.mathsmate.net

Skill 6.6 Calculating the suface aea of composite solids (). e) Find the suface aea of the octahedon. f) Find the suface aea of the solid. continued fom page 314 18 ft 13 cm 1 cm 10 ft 17 cm = ft = g) Lou bought a ectangula box containing 15 tightly packaged eases. What is the suface aea of the box? h) Find the suface aea of the pism. 10 in. 5 in. cm 4 cm 10 cm 4 in. in. 10 in. = = page 315 www.mathsmate.net

Skill 6.7 Calculating the suface aea of basic thee-dimensional ound solids (1). Substitute values into the fomula: continues on page 317 cylinde L.A. = πh B + L.A. = π + πh = π ( + h) h π h cone sphee L.A. = πs B + L.A. 4π s = π + πs = π ( + s) Q. Using π ( + h) and π 3.14, find the suface aea of the cyclinde. 4 cm A. π ( + h) whee = and h = 8 = 3.14 ( + 8) = 1.56 10 = 15.6 a) Use π ( + s) and π 3.14 to find the suface aea of the conical caot. b) Using 4π and π, find the 7 suface aea of the sphee. 4 cm 10 cm 1 ft π( + s) whee =, s = 10 3.14 ( + 10) = 6.8 1 = ft page 316 www.mathsmate.net

continued fom page 316 MMMauve 11 Skill 6.7 Calculating the suface aea of basic thee-dimensional MMLime 11 ound solids (). c) Using 4π and π, find the d) Use π ( + s) and π 3.14 to find how 7 suface aea of the snow globe. much aea still needs to be coveed 6 cm in chocolate to cove the whole cone given that 40 have been coveed so fa. 140 mm 33 44 33 44 1 cm mm e) Using π ( + h) and π 3.14, find the suface aea of the cyclindical stool seat. 40 cm 5 cm f) Using π ( + h) and π, find the 7 suface aea of the can of tuna. 14 cm g) Use π 3.14 to find the suface aea of the cone. [Hint: Pythagoean theoem will help.] h) Use π 3.14 to find the suface aea of the cone. [Hint: Pythagoean theoem will help.] 4 in. 10 in. 4 yd 36 yd yd page 317 www.mathsmate.net

Skill 6.8 Calculating the suface aea of moe complex thee-dimensional ound solids. Substitute values into the appopiate fomula: (see skills 6. to 6.7, pages 307 to 316) Adapt the fomula whee necessay. hemisphee 4π +π = 3π Q. Using π find the suface aea of the 7 hemisphee. 14 in. A. 3π whee = 7 1 = 3 7 7 1 7 = 66 7 = 46 a) Using π 3.14 find the suface aea of the hemisphee. b) Using π 3.14 find the suface aea of the watemelon half. 10 in. 4 ft 3π whee = 4 = 3 3.14 4 4 = 9.4 16 = 150.7 ft c) Use π 3.14 to find the suface aea of the shape. d) Use π to find the suface aea of the shape. 7 8 in. 5 ft 6 ft 10 ft S.A. pism = 0 in. 14 in. L.A. cone = = S.A. cylinde half = = S.A. cylinde = = = = ft = page 318 www.mathsmate.net

Skill 6.9 Expessing the suface aea of thee-dimensional solids in algebaic fom. Substitute values into the appopiate fomula fo suface aea. (see skills 6. to 6.8, pages 307 to 318) Adapt the fomula whee necessay. Q. Wite a fomula fo the suface aea of the cone. A. π( + s) whee = a and s = 4a = π a (a + 4a) = πa 5a = 5πa a 4a a) Wite a fomula fo the suface aea S.A. of the cylinde. b) Wite a fomula fo the suface aea S.A. of the hemisphee. 5d d π( + h) whee = d and h = 5d = πd(d + 5d) = πd 6d... = 1πd =... c) Wite a fomula fo the suface aea S.A. of the obelisk. d) Wite a fomula fo the suface aea S.A. of the cube. a 3d = = =... =... e) Wite a fomula fo the suface aea S.A. of the cylinde. 6x 10x f) Wite a fomula fo the suface aea S.A. of the cone. 7p p = = =... =... page 319 www.mathsmate.net