Mean-Variance Analysis

Σχετικά έγγραφα
EE512: Error Control Coding

SOLUTIONS TO MATH38181 EXTREME VALUES AND FINANCIAL RISK EXAM

SOLUTIONS TO MATH38181 EXTREME VALUES AND FINANCIAL RISK EXAM

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

2 Composition. Invertible Mappings

Every set of first-order formulas is equivalent to an independent set

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:

Statistical Inference I Locally most powerful tests

Credit Risk. Finance and Insurance - Stochastic Analysis and Practical Methods Spring School Jena, March 2009

Homework 3 Solutions

Fractional Colorings and Zykov Products of graphs

Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit

Finite Field Problems: Solutions

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ.

5. Choice under Uncertainty

Example Sheet 3 Solutions

Second Order Partial Differential Equations

2. Let H 1 and H 2 be Hilbert spaces and let T : H 1 H 2 be a bounded linear operator. Prove that [T (H 1 )] = N (T ). (6p)

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +

= λ 1 1 e. = λ 1 =12. has the properties e 1. e 3,V(Y

Exercises 10. Find a fundamental matrix of the given system of equations. Also find the fundamental matrix Φ(t) satisfying Φ(0) = I. 1.

ΜΕΤΡΑ ΚΙΝΔΥΝΟΥ ΣΤΗ ΧΡΗΜΑΤΟΟΙΚΟΝΟΜΙΚΗ

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

Tridiagonal matrices. Gérard MEURANT. October, 2008

MINIMAL CLOSED SETS AND MAXIMAL CLOSED SETS

Homework 8 Model Solution Section

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

Inverse trigonometric functions & General Solution of Trigonometric Equations

Other Test Constructions: Likelihood Ratio & Bayes Tests

Parametrized Surfaces

12. Radon-Nikodym Theorem

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1

ECE Spring Prof. David R. Jackson ECE Dept. Notes 2

Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3

A Note on Intuitionistic Fuzzy. Equivalence Relation

ST5224: Advanced Statistical Theory II

Lecture 21: Properties and robustness of LSE

Reminders: linear functions

Solution Series 9. i=1 x i and i=1 x i.

C.S. 430 Assignment 6, Sample Solutions

w o = R 1 p. (1) R = p =. = 1

Bounding Nonsplitting Enumeration Degrees

ORDINAL ARITHMETIC JULIAN J. SCHLÖDER

Matrices and Determinants

Approximation of distance between locations on earth given by latitude and longitude

Uniform Convergence of Fourier Series Michael Taylor

Generating Set of the Complete Semigroups of Binary Relations

Using Long-Run Consumption-Return Correlations to Test Asset Pricing Models : Internet Appendix

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

SCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions

SOME PROPERTIES OF FUZZY REAL NUMBERS

2. THEORY OF EQUATIONS. PREVIOUS EAMCET Bits.

Nowhere-zero flows Let be a digraph, Abelian group. A Γ-circulation in is a mapping : such that, where, and : tail in X, head in

Math221: HW# 1 solutions

An Inventory of Continuous Distributions

Areas and Lengths in Polar Coordinates

Strain gauge and rosettes

Math 446 Homework 3 Solutions. (1). (i): Reverse triangle inequality for metrics: Let (X, d) be a metric space and let x, y, z X.

Introduction to Risk Parity and Budgeting

D Alembert s Solution to the Wave Equation

Section 8.2 Graphs of Polar Equations

The Simply Typed Lambda Calculus

MATH423 String Theory Solutions 4. = 0 τ = f(s). (1) dτ ds = dxµ dτ f (s) (2) dτ 2 [f (s)] 2 + dxµ. dτ f (s) (3)

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

Section 8.3 Trigonometric Equations

ω ω ω ω ω ω+2 ω ω+2 + ω ω ω ω+2 + ω ω+1 ω ω+2 2 ω ω ω ω ω ω ω ω+1 ω ω2 ω ω2 + ω ω ω2 + ω ω ω ω2 + ω ω+1 ω ω2 + ω ω+1 + ω ω ω ω2 + ω

The challenges of non-stable predicates

THE SECOND ISOMORPHISM THEOREM ON ORDERED SET UNDER ANTIORDERS. Daniel A. Romano

6. MAXIMUM LIKELIHOOD ESTIMATION

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013

derivation of the Laplacian from rectangular to spherical coordinates

6.3 Forecasting ARMA processes

Problem Set 3: Solutions

Lecture 34 Bootstrap confidence intervals

F19MC2 Solutions 9 Complex Analysis

1. Introduction and Preliminaries.

Areas and Lengths in Polar Coordinates

ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ. Ψηφιακή Οικονομία. Διάλεξη 8η: Producer Behavior Mαρίνα Μπιτσάκη Τμήμα Επιστήμης Υπολογιστών

Part III - Pricing A Down-And-Out Call Option

Pg The perimeter is P = 3x The area of a triangle is. where b is the base, h is the height. In our case b = x, then the area is

4.6 Autoregressive Moving Average Model ARMA(1,1)

Congruence Classes of Invertible Matrices of Order 3 over F 2

Introduction to Risk Parity and Budgeting

Exercises to Statistics of Material Fatigue No. 5

Homomorphism in Intuitionistic Fuzzy Automata

A Two-Sided Laplace Inversion Algorithm with Computable Error Bounds and Its Applications in Financial Engineering

SCITECH Volume 13, Issue 2 RESEARCH ORGANISATION Published online: March 29, 2018

HW 3 Solutions 1. a) I use the auto.arima R function to search over models using AIC and decide on an ARMA(3,1)

ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ

Concrete Mathematics Exercises from 30 September 2016

Cyclic or elementary abelian Covers of K 4

5.4 The Poisson Distribution.

CAPM. Το Μοντέλο Αποτίμησης Κεφαλαιουχικών Αγαθών (Capital Asset Pricing Model): ανάλυση ρίσκου και απόδοσης επενδύοντας στις παγκόσμιες χρηματαγορές

( )( ) ( ) ( )( ) ( )( ) β = Chapter 5 Exercise Problems EX α So 49 β 199 EX EX EX5.4 EX5.5. (a)

Space-Time Symmetries

Partial Differential Equations in Biology The boundary element method. March 26, 2013

Lecture 12: Pseudo likelihood approach

Risk! " #$%&'() *!'+,'''## -. / # $

F A S C I C U L I M A T H E M A T I C I

Transcript:

Mean-Variance Analysis Jan Schneider McCombs School of Business University of Texas at Austin Jan Schneider Mean-Variance Analysis

Beta Representation of the Risk Premium risk premium E t [Rt t+τ ] R1 t+τ pt = Cov t[rt t+τ, Mpt t+τ ] E t [Mpt t+τ = ] divide by the price of M t+τ pt Cov t[rt t+τ, Mt ] E t [ Mt ] = ft if a risk-free asset exists this equation holds also for the traded discount factor: Mt, Rt+τ Mt ] Mt ] E t [ Mt ] Rt+τ 1 pt = Cov t[ E t [ plug into equation above: E t [ Mt ] = E t [R t+1 ] R1 t+τ pt = Cov t[r t+1, Var t [ Var t[ Mt ] E t [ Mt ] Rt+τ 1 pt Mt ] Mt ] ( ) E t [ Mt ] Rt+τ 1 pt Jan Schneider Mean-Variance Analysis 1 / 17

Unconditional Beta Representation E[R t+1 ] 1 E[1/R1 t+τ ] pt = Cov[R t+1, R Mt+1 ] Var[R Mt+1 ] ( E[R Mt+1 ] ) 1 E[1/R1 t+τ ] pt 1 E[P ft ] if the risk-free asset exists Jan Schneider Mean-Variance Analysis 2 / 17

Maximum Sharpe Ratio E t [Rt t+τ ] R1 t+τ pt Var t [Rt t+τ ] = R1 t+τ Corr pt t[mpt t+τ, Rt t+τ ] Var t [Mpt t+τ ] R 1+τ ft 1 pt = E t[rt t+τ ] Var t [ t ] if a risk-free asset exists R1 t+τ pt Var t [Mpt t+τ ] 1 pt Vart [M t+1 ] since M t+τ t = M t+τ pt + M t+τ p t Jan Schneider Mean-Variance Analysis 3 / 17

Mean-Variance Efficient Frontier I H t... H t+τ 1 self-financing portfolio portfolio payoff P Ht+τ + D Ht+τ is mean-variance efficient q t to t + τ if P H (q t) = P H (q t) E[P Ht+τ + D Ht+τ q t] = E[P H t+τ + D H t+τ q t] } = Var[P Ht+τ + D Ht+τ q t] Var[P H t+τ + D H t+τ q t] Jan Schneider Mean-Variance Analysis 4 / 17

Mean-Variance Efficient Frontier II Suppose H is mean-variance efficient. Suppose H satisfies conditions on the previous slide. Then: [ ] [ ] H t qt] = E PH t+τ + D H t+τ PHt+τ + D Ht+τ P H (q t) qt = E P H (q t) qt [ ] [ ] PHt+τ + D Ht+τ PH P H (q t) qt Var t+τ + D H t+τ P H (q t) qt E[ and Var[ Ht q t] = Var we have: = E[ Ht q t] = Var[ H t qt] mean-variance efficiency in payoffs mean-variance efficiency in returns Jan Schneider Mean-Variance Analysis 5 / 17

Portfolios of the Discount Factor and the Unity Payoff I Consider the market of all self-financing portfolios between q t and t + τ Define F t+τ q t = { Y : Y = am t+τ pt + b1 t+τ pt for some a, b R } Consider an arbitrary traded payoff Y. Projecting Y on F : Y = Y F + Y F Jan Schneider Mean-Variance Analysis 6 / 17

Portfolios of the Discount Factor and the Unity Payoff II some properties of Y : = 0 = 0 1. E t [Y ] = E t [Y F ] E t [Y F ] = E t [Y F 1 t+τ p t ] + E t [Y F 1 t+τ pt ] = 0 2. Cov t [Y F, Y F ] = 0 Cov t [Y F, Y F ] = E t [Y F Y F ] E t [Y F ] E t [Y F ] = 0 = 0 = 0 3. Y F 0 = Var t [Y F ] > 0 Var t [Y F ] = E t [YF 2 ] > 0 if Y F 0 4. P Yt = P YF t P Yt = E t [M t+τ pt corresponding decomposition for returns: Yt = Y P Yt = Y F + Y F P Yt = Y F P YF t (Y F + Y F )] = E t [Mpt t+τ Y F ] = P YF t + Y F P Yt R YF t+1 z F Jan Schneider Mean-Variance Analysis 7 / 17

Portfolios of the Discount Factor and the Unity Payoff III All payoff in F are mean variance efficient. Proof. Choose an arbitrary traded payoff Y. Then we can decompose Y as on the previous slide. Since P Y = P YF and since Y F only adds noise, Y cannot be mean-variance efficient if Y F 0 Jan Schneider Mean-Variance Analysis 8 / 17

Portfolios of the Discount Factor and the Unity Payoff IV All payoff in E qt are mean variance efficient. Proof.Choose Y F. There exist a m-v efficient traded payoff Y such that P Yt = P Y t and E t [Y ] = E t [Y ] By the argument above Y is in F. Hence Y Y F. But Y Y is also orthogonal to F : E t [(Y Y )1pt t+τ ] + E t [(Y Y )1 t+τ p t ] = E t [Y Y ] = 0 E t [M t+τ pt (Y Y )] = P Yt P Y t = 0 Therefore, since Y Y F and Y Y / F, Y Y = 0. Hence we have for any market between q t and t + τ: Y is mean-variance efficient Y F t+τ q t Jan Schneider Mean-Variance Analysis 9 / 17

2 M-V Efficient Portfolios M-V Frontier any mean-variance efficient return is given by ht = h Mt + (1 h) = + h( Mt ) Jan Schneider Mean-Variance Analysis 10 / 17

Minimum-Variance Portfolio Var t [ ht variance of the return on the previous slide: ] = Var t [R t+τ ]+h 2 Var t [ minimum of the variance: Var t [ ht ] h Mt Rt+τ ]+2hCov t [R t+τ, Mt Rt+τ ] = 0 = h = Cov t[r t+τ, Mt Var t [ Mt If a risk-free asset is traded, then h = 0 and ht ] ] = ft. Jan Schneider Mean-Variance Analysis 11 / 17

Zero-Covariance Portfolio Covariance between two mean-variance efficient returns R h1 and R h2 : Cov t [ h 1 t, Rt+τ h 2 t ] = Var t[r t+τ ] + h 1 h 2 Var t [ Mt ] + (h 1 + h 2 )Cov t [R t+τ, Mt ] hence: Cov t [ h 1 t, Rt+τ h 2 t ] = 0 h 2 = Var t [ h 1 Var t [ Mt ] + h 1 Cov t [R t+τ, Mt ] + Cov t [, Mt ] ] Jan Schneider Mean-Variance Analysis 12 / 17

M-V Efficiency and Beta Representation Choose any traded return t : t = h 1 t Ft + β t ( h 2 t R +z F h 1 t ) = E t [Rt t+τ ] = E t [ h 1 t ] + β ( t Et [ h 2 t ] E t[ h 1 t ]) h 2 t ] = β t = Cov t[rt t+τ Cov t [Rt t+τ, h 2 t ] = β tvar t [, h 2 t ] Var t [ h 2 t ] hence: E t [ t ] = E t [ h 1 t ]+ Cov t[rt t+τ, Var t [ h 2 t ] h 2 t ] ( Et [ h 2 t ] E t[ h 1 t ]) zero-covariance portfolio, = R ft+1 if risk-free asset exists Jan Schneider Mean-Variance Analysis 13 / 17

Market Portfolio M-V Efficient = CAPM Suppose a risk-free asset exists and suppose the market portfolio is mean-variance efficient. Then we have: E t [Rt t+τ ] = ft + Cov t[rt t+τ, Var t [ mt ] mt ] ( Et [ mt ] ) ft This model of expected returns is known as the capital asset pricing model (CAPM). Jan Schneider Mean-Variance Analysis 14 / 17

Mean-Variance Efficient Returns Discount Factor Suppose h 1 t and h 2 t suppose Cov t [ h 1 t, Rt+τ h 2 t ] = 0 Then: M t+τ t = Proof: any return E t[m t+τ t t are mean-variance efficient 1 E t [ h 1 t ] (Rt+τ h 2 t E t [ ] = Et[Rt+τ t ] E t[ h 1 t ] = 1 ( Cov t[rt t+τ, h 2 t ] E t[rt t+τ h 2 t ] E t[rt t+τ h 2 t ])E t[ h 2 t ] E t[ E t [ h 1 t ]Var t[ h 1 t ] h 2 t ] ) Et[ ]E t[ h h 2 t ] 2 t ] Et[Rt+τ h 1 t ] E t[ h 1 t ]Vart[Rt+τ h 2 t ] Jan Schneider Mean-Variance Analysis 15 / 17

CAPM Discount Factor For example, if the CAPM holds: M t+τ t = 1 ft ( Rmt t+τ ft ) Et [Rmt t+τ ] ft Var t [ ft mt ] Jan Schneider Mean-Variance Analysis 16 / 17

Maximizing Sharpe Ratio Sharpe ratio of a portfolio H: E t [R Ht+1 ] R ft+1 SD t [R Ht+1 ] Derivative: = A a=1 since: h a = 1 h a (E t [R at+1 ] R ft+1 ) A A a=1 b=1 h ah b Cov[R at+1, R bt+1 ] (Sharpe ratio) ] Cov h t [R at+1, h b R bt+1 a b (E t[r at+1] R ft+1 )SD t[r Ht+1 ] (E[R Ht+1 ] R ft+1 ) 1 Var[R 2 Ht+1] 1 2 2 h b Cov t[r at+1, R bt+1 ] = Var t[r Ht+1 ] = Et[Rat+1] R ft+1 (E t[r Ht+1 ] R ft+1 )Var t[r Ht+1 ] 1 Cov t[r at+1, R Ht+1 ] Var t[r Ht+1 ] 1 2 b R Ht+1 Jan Schneider Mean-Variance Analysis 17 / 17