IIT JEE (2013) (Trigonomtery 1) Solutions

Σχετικά έγγραφα

Inverse trigonometric functions & General Solution of Trigonometric Equations

Matrices and Determinants

Section 8.3 Trigonometric Equations

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

2. THEORY OF EQUATIONS. PREVIOUS EAMCET Bits.

Presentation of complex number in Cartesian and polar coordinate system

1. For each of the following power series, find the interval of convergence and the radius of convergence:

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0.

Trigonometry 1.TRIGONOMETRIC RATIOS

Areas and Lengths in Polar Coordinates

MathCity.org Merging man and maths

Advanced Subsidiary Unit 1: Understanding and Written Response

Section 7.6 Double and Half Angle Formulas

SUPERPOSITION, MEASUREMENT, NORMALIZATION, EXPECTATION VALUES. Reading: QM course packet Ch 5 up to 5.6

α β

Homework 3 Solutions

Example Sheet 3 Solutions

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

Answers - Worksheet A ALGEBRA PMT. 1 a = 7 b = 11 c = 1 3. e = 0.1 f = 0.3 g = 2 h = 10 i = 3 j = d = k = 3 1. = 1 or 0.5 l =

Homework for 1/27 Due 2/5

2 Composition. Invertible Mappings

CRASH COURSE IN PRECALCULUS

EN40: Dynamics and Vibrations

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

SCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions

Statistical Inference I Locally most powerful tests

MATHEMATICS. 1. If A and B are square matrices of order 3 such that A = -1, B =3, then 3AB = 1) -9 2) -27 3) -81 4) 81

EE512: Error Control Coding

CHAPTER 103 EVEN AND ODD FUNCTIONS AND HALF-RANGE FOURIER SERIES

ΚΥΠΡΙΑΚΟΣ ΣΥΝΔΕΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY 21 ος ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ Δεύτερος Γύρος - 30 Μαρτίου 2011

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007

Areas and Lengths in Polar Coordinates

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 24/3/2007

PARTIAL NOTES for 6.1 Trigonometric Identities

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +

If we restrict the domain of y = sin x to [ π, π ], the restrict function. y = sin x, π 2 x π 2

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Ordinary Level

The Simply Typed Lambda Calculus

If we restrict the domain of y = sin x to [ π 2, π 2

Other Test Constructions: Likelihood Ratio & Bayes Tests

Econ 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1

4.6 Autoregressive Moving Average Model ARMA(1,1)

Finite Field Problems: Solutions

C.S. 430 Assignment 6, Sample Solutions

Paper Reference. Paper Reference(s) 1776/04 Edexcel GCSE Modern Greek Paper 4 Writing. Thursday 21 May 2009 Afternoon Time: 1 hour 15 minutes

Exercises 10. Find a fundamental matrix of the given system of equations. Also find the fundamental matrix Φ(t) satisfying Φ(0) = I. 1.

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1

A Note on Intuitionistic Fuzzy. Equivalence Relation

FREE VIBRATION OF A SINGLE-DEGREE-OF-FREEDOM SYSTEM Revision B

Math 6 SL Probability Distributions Practice Test Mark Scheme

Solve the difference equation

TRIGONOMETRIC FUNCTIONS

derivation of the Laplacian from rectangular to spherical coordinates

Mock Exam 7. 1 Hong Kong Educational Publishing Company. Section A 1. Reference: HKDSE Math M Q2 (a) (1 + kx) n 1M + 1A = (1) =

Trigonometric Formula Sheet

SHORT REVISION. FREE Download Study Package from website: 2 5π (c)sin 15 or sin = = cos 75 or cos ; 12

Second Order Partial Differential Equations

Paper Reference. Paper Reference(s) 6665/01 Edexcel GCE Core Mathematics C3 Advanced. Thursday 11 June 2009 Morning Time: 1 hour 30 minutes

n r f ( n-r ) () x g () r () x (1.1) = Σ g() x = Σ n f < -n+ r> g () r -n + r dx r dx n + ( -n,m) dx -n n+1 1 -n -1 + ( -n,n+1)

6.1. Dirac Equation. Hamiltonian. Dirac Eq.

Partial Differential Equations in Biology The boundary element method. March 26, 2013

MATH 38061/MATH48061/MATH68061: MULTIVARIATE STATISTICS Solutions to Problems on Matrix Algebra

Quadratic Expressions

Math221: HW# 1 solutions

Approximation of distance between locations on earth given by latitude and longitude

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Ordinary Level

Solutions to Exercise Sheet 5

6.3 Forecasting ARMA processes

Differential equations

Potential Dividers. 46 minutes. 46 marks. Page 1 of 11

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS International General Certificate of Secondary Education

ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ. Ψηφιακή Οικονομία. Διάλεξη 10η: Basics of Game Theory part 2 Mαρίνα Μπιτσάκη Τμήμα Επιστήμης Υπολογιστών

Second Order RLC Filters

Nowhere-zero flows Let be a digraph, Abelian group. A Γ-circulation in is a mapping : such that, where, and : tail in X, head in

1. Matrix Algebra and Linear Economic Models

Strain gauge and rosettes

The challenges of non-stable predicates

p n r

Outline. M/M/1 Queue (infinite buffer) M/M/1/N (finite buffer) Networks of M/M/1 Queues M/G/1 Priority Queue

Fourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics

9.09. # 1. Area inside the oval limaçon r = cos θ. To graph, start with θ = 0 so r = 6. Compute dr

Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit

Review Test 3. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Srednicki Chapter 55

physicsandmathstutor.com

Solution Series 9. i=1 x i and i=1 x i.

1. If log x 2 y 2 = a, then dy / dx = x 2 + y 2 1] xy 2] y / x. 3] x / y 4] none of these

On a four-dimensional hyperbolic manifold with finite volume

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 6/5/2006

Chapter 6: Systems of Linear Differential. be continuous functions on the interval

Ψηφιακή Επεξεργασία Εικόνας

Volume of a Cuboid. Volume = length x breadth x height. V = l x b x h. The formula for the volume of a cuboid is

Differentiation exercise show differential equation

Cambridge International Examinations Cambridge International General Certificate of Secondary Education

Bessel function for complex variable

ECE 308 SIGNALS AND SYSTEMS FALL 2017 Answers to selected problems on prior years examinations

ST5224: Advanced Statistical Theory II

Transcript:

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 (+) PAPER B IIT JEE (0) (Trigoomtery ) Solutios TOWARDS IIT JEE IS NOT A JOURNEY, IT S A BATTLE, ONLY THE TOUGHEST WILL SURVIVE TIME: 60 MINS MAX. MARKS: 76 MARKING SCHEME I Sectio I (Total Marks: ), for each questio you will be awarded marks if you darke ONLY the bubble correspodig to the correct aswer ad zero marks if o bubble is darkeed. I all other cases, mius oe () mark will be awarded. I Sectio II (Total Marks: 6), for each questio you will be awarded marks if you darke ALL the bubble(s) correspodig to the correct aswer(s) ONLY ad zero marks otherwise. There are o egative marks i this sectio. I Sectio III (Total Marks: ), for each questio you will be awarded marks if you darke ONLY the bubble correspodig to the correct aswer ad zero marks otherwise. There are o egative marks i this sectio. I Sectio IV (Total Marks: 6), for each questio you will be awarded marks for each row i which you have darkeed ALL the bubble(s) correspodig to the correct aswer(s) ONLY ad zero marks otherwise. Thus, each questio i this sectio carries a maximum of 8 marks. There are o egative marks i this sectio. NAME OF THE CANDIDATE CONTACT NUMBER L.K. Gupta (Mathematics Classes) PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 Sectio- I (Total Marks : ) (Sigle Correct Aswer Type) This sectio cotais 8 multiple choice questios. Each questio has four choices (a), (b), (c), (d) out of which ONLY ONE is correct.. si si si9 If k = ta 7 ta ad k =, the cos cos9 cos 7 (a) k = k (b)k = k + (c) k = k (d) oe of these As. (a) Sol: we have, k ta7θ taθ (ta7θ ta9θ) (ta9θ taθ) (taθ taθ) siθ siθ Now, taθ taθ cosθcosθ cosθ siθ si9θ Similarly, ta9θ taθ ad ta7θ ta9θ cos9θ cos7θ si9θ siθ siθ k k cos7θ cos9θ cosθ. If 0 0 < < 80 0, the... cos, the beig umber of s, is equal to, (a) cos As. (a) Sol: (b) cos... ( cosθ) ( umber of s)... cosθ/) (( ) umber of s).. cos (θ/ ) { cos (θ/ ) } cos(θ/ ) (c) cos (d) oe of these PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677. If ta / ad ta/ are the roots of the equatio 8x 6 x + 5 =0, the cos ( +) is equal to 67 (a) (b) 67 75 75 (c) (d)oe of these As. (a) Sol: 6 ta / ta /, 8 5 ta / ta / 8 ta ta ta ta / ta/ ta 6 cos( ) 5 7 ta 8 6 7 9 676 67 6 9 676 75 7. The value of cos cos cos cos cos cos cos is equal to 5 5 5 5 5 5 5 (a) / 6 (b) / 7 (c) / 8 (d) oe of these As. (b) Sol: π π π π 5π 6π 7π cos cos cos cos cos cos cos 5 5 5 5 5 5 5 π π π 8π π 5π 6π cos cos cos cos π cos cos cos 5 5 5 5 5 5 5 π π π 8π π π π cos cos cos cos cos cos cos 5 5 5 5 5 5 5 5 π π π 8π cos cos cos cos 5 5 5 5 PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 π si. 5. 8 π.si 5 π si π 5. 7 7 π si 5 5. If si x six = 6 m c cos x where c,c,c,...,.c are costats,the m 0 6 m0 (a) c c c c = 0 (b) c c c 6 (c) c c 0 (d) c c 0 0 6 5 6 6 As. (a) Sol: si x six si x(si x si x) si x( si x) ( cos x) ( ( cos x)) ( cos x cos x)(cos x ) so that Co,C 6,C 9,C6 ad C C C5 0 C C C C 0 0 6 6 cos x 9cos x 6cos x 6. ta7 is equal to ( ) (a) As. (a) Sol. (b) (c) (d) ta7 = ta 5 ta5 ta 5 or PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 ta7 = ( ) ( ) 7. 6 0 0 If si ad 50 50, the si( / ) is equal to 65 7 (a) (b) 5 5 (c) 5 (d) 5 Sol: (a) 6 0 0 si ad 50 50 65 si( / ) cos( / ) 8. If 57 cos 65 5 50 5 x y z, the x y z is equal to cos cos cos (a) (b) 0 (c) (d) oe of these As. (b) Sol x y z k say cos cos x y z k cos cos cos PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 5

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 k cos cos cos k cos cos 0 Sectio II (Total Marks : 6) (Multiple Correct Aswer (s) Type) This sectio cotais multiple choice questios. Each questio has four choices (a), (b), (c), ad (d) out of which ONE or MORE may be correct. 9. If x sec ta ad y = cosec cot, the y y (a) x (b) x (c) y y As. (c, d) Sol. si cos We have, x =, y cos si ( si )( cos ) Multiplyig, we get xy cossi si cos sicos sicos cossi si cos cossi ( si ) si cos ( cos ) ad x y cossi si cos ( xy ) cossi Thus, xy x y 0 y x ad y = x y x x y (d) xy x y 0 x PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 6

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 0. Let f ta sec sec sec. sec, the (a) f (b) f f f5 6 6 8 As. (a, b, c, d) Sol r f ta / sec r 0 r r r cos ta / r 0 cos r cos ta / r cos r 0 ta / r 0 cos r cos. ta /. cos /. si. si.. si. cos ta r 0 cos cos Alterate. (a) : f ta 6 Alterate. (b) : f ta Alterate. (c) : f ta 6 Alterate (d) : f 5 ta 8 r. If x cos A, where A B, the y cosb A B x ta A y tab (a) ta x y PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 7

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 A B x ta A y tab (b) ta x y sia B y si A xsib (c) si A B y si A xsib (d) xcos A y cos B 0 As. (a, b, c) Sol x cos A y cosb x y say cos A cosb x cos A,y cosb Alterate. (a) : RHS = x ta A y tab x y cos A ta A cosb tab cos A cosb si A sib cos A cosb A B A B si cos A B A B cos cos A B ta LHS Alterate. (b) : RHS = x ta A y tab x y cos A ta A cosb tab cos A cosb si A sib cos A cosb A B A B cos si A B A B cos cos PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 8

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 A B ta LHS Alterate. (c) : RHS = y si A x sib y si A x sib cosb si A cos AsiB cosb si A cos A sib sia B LHS si A B Alterate. (d) : LHS = x cos A + y cos B = cos A cos B 0. If cos, si are the roots of the equatio x b x 0 ad cos, si are the roots of the equatio x x 0, the b is equal to (a) (b) (c) (d) As. (b, c) Sol We have, cos si cos si cos b b b, b b 0 Sectio III (Total Marks : ) (Iteger Aswer Type) This sectio cotais 6 questios. The aswer to each of the questios is a sigle-digit iteger, ragig from 0 to 9.The bubble correspodig to the correct aswer is to be darkeed i the ANSWER SHEET. PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 9

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677. If cos A =, the si A 5 A si. Fid the value of λ. As. 0 Sol. si 5A si A = 6 (cos A cos A ) 6(cos A cos A cos A) 9 7 6... 6 6 = 8 6 7 6 = λ = 0.. If P cos x si x, the P 6 P... As. 0 Sol. 6 6 P6 P (cos x si x) (cos x si x) = [(cos x si x) cos x si x(cos x si x) [(cos x si x) cos x si x) ( cos x si x) ( cos x si x) = 0 6 5. If acos bcos 6cos 9cos is a idetity, the a =.. As. Sol. 6 Give, a cos bcos 6cos 9cos 6 9cos 6cos a(cos cos ) bcos 6 = a(6cos cos cos ) bcos 6 9a cos ( b a)cos 6acos Comparig, we get 9a 9 a ; b a 0 b =a = a =. 6. If sec k is 5 0, the value of 7 5cot is. The the value of 0 9 (sec ) k PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 0

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 As. Sol. 5 sec ta (sec ) 7 5 7 5cot So that 6 8 0 k =. 9 (sec ) 9 8 6 7. Cos cos cos cos cos cos equals. The fid the value of 65 65 65 65 65 65 k 68 k As. Sol. 6 6 si. 65 si Required result = 65 si 65 si 65 6 6 si 65 6si 65 6si 65 6si 65 68 k =. 8. If 0 cos90 0 si50 As. Sol. Here, cos, the the value of 0 0 0 0 90 cos(70 0 ) si0 0 0 0 0 ad si 50 si(70 0 ) cos0 The give expressio 0 0 si0 cos0 0 cos60 0 0 0 si0 si60 cos0 0 0 0 0 si60 cos0 cos60 si0 = 0 0 0 si0 cos0 si60 0 0 si(60 0 ) = 0 si0 9 8 97 78 must be PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 6 56 6 The, 9 8 97 9 8 97 9 = 56++97=785 9 8 97 78 =. Sectio IV (Total Marks : 6) (Matrix-Match Type) This sectio cotais questios. Each questio has four statemets (a, b, c ad d) give i Colum I ad five statemets (p, q, r, s ad t) i Colum II. Ay give statemets i Colum I ca have correct matchig with ONE or MORE statemets(s)give i Colum II. For example, if for a give questio, statemet B matches with the statemets give i q ad r, the for the particular questio, agaist statemet B, darke the bubbles correspodig to q ad r i the ANSWER SHEET. 9. (a) (b) Colum If maximum ad miimum values 7 6ta ta of for all real values ( ta ) of are ad respectively, the If maximum ad miimum values of 5 cos cos for all real values of are ad respectively, the Colum II (P) (Q) 6 (c) If maximum ad miimum values of si cos for all real values of are ad respectively, the (R) 6 (S) 0 (T) PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 As. (a)r, s ; (b)r, t ; (c) p, q. Sol (A) Let y = 7 6ta ta ta 7 cos 6 si cos si cos cos 7 si si cos y 8 8, 6, 0 R, S (B) Let y = 5 cos cos / = 5cos cos si cos si cos si 7 y 7 y 0 0, 6, R, T (C) Let y = + si cos cos cos = + cos cos = + cos PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 cos cos cos y,, 6 P, Q 0. Observe the followig colums : Colum I Colum II (A) I a Δ ABC (P) A B C si A B C si cos, si si si (B) I a (Q) A B C cos A B C cos cos Δ ABC, si si si (C) I s Δ ABC, (R) A B C si A B C si si cos cos cos (S) A B C cos cos si (T) A B C cos cos si As. (a)r, t ; (b)p, s; (c) q. Sol: si A si B si C A B C si si si si A B A B C C si cos cos si C A B C si cos cos PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 A B C C C A B C B A si si si 8 8 C B A si si si A B C si si si (R) A B C cos cos si A B C cos cos si (T) (B) si A si B si C A B C si si si si A B A B C si cos cos si C C A B C si cos cos A B C C C A B C B A si cos cos 8 8 C B A si cos cos A B C cos cos si S A B C si si cos A B C si si cos (P) (C) cos A cos B cos C PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 5

L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 A B C cos cos cos cos A B A B C C cos cos cos cos C A B C cos cos cos A B C C C A B C B A cos si si 8 8 C B A cos si si C B A cos si si C B A cos cos cos A B C cos cos cos (Q) PIONEER EDUCATION (THE BEST WAY TO SUCCESS): S.C.O. 0, SECTOR 0 D, CHANDIGARH 6