Oscillations CHAPTER 3. ν = = 3-1. gram cm 4 E= = sec. or, (1) or, 0.63 sec (2) so that (3)
|
|
- Κρέων Τομαραίοι
- 5 χρόνια πριν
- Προβολές:
Transcript
1 CHAPTER 3 Oscillaios 3-. a) gram cm 4 k dye/cm sec cm ν sec π m π gram π gram π or, ν.6 Hz () or, π τ sec ν τ.63 sec () b) so ha 4 3 ka dye-cm E 4 E 4.5 erg c) The maximum velociy is aaied whe he oal eergy of he oscillaor is equal o he kieic eergy. Therefore, 4 mv max 4.5 erg v max
2 8 CHAPTER 3 or, v 3 cm/sec (4) max 3-. a) The saeme ha a a cerai ime he maximum ampliude has decreased o oehalf he iiial value meas ha or, so ha Sice sec, () β xe Ae A β e β () β l.69 b) Accordig o Eq. (3.38), he agular frequecy is 6.9 sec (4) β (5) where, from Problem 3-, sec. Therefore, so ha ( 6.9 ) ( 6.9) sec 6 (6) which ca be wrie as where Tha is, ν is oly slighly differe from ν. ( 4 5 ) sec ν. (7) π ν ν δ (8) δ 5.4 (9)
3 OSCILLATIONS 8 βτ c) The decreme of he moio is defied o be e e βτ.445 where τ ν. The, 3-3. The iiial kieic eergy (equal o he oal eergy) of he oscillaor is m g ad v cm/sec. mv, where a) Maximum displaceme is achieved whe he oal eergy is equal o he poeial eergy. Therefore, mv kx or, x m v 4 cm k x cm () b) The maximum poeial eergy is or, U kx 4 max U 5 ergs () max 3-4. a) Time average: The posiio ad velociy for a simple harmoic oscillaor are give by where km The ime average of he kieic eergy is x Asi () x Acos () T + τ mx d τ π where τ is he period of oscillaio.
4 8 CHAPTER 3 By iserig () io, we obai or, + τ cos T ma τ d (4) ma T (5) 4 I he same way, he ime average of he poeial eergy is U + τ τ kx d ad sice km, (6) reduces o ka τ ka 4 + τ si d (6) From (5) ad (7) we see ha U ma (7) 4 T U (8) The resul saed i (8) is reasoable o expec from he coservaio of he oal eergy. E T + U (9) This equaliy is valid isaaeously, as well as i he average. O he oher had, whe T ad U are expressed by () ad (), we oice ha hey are described by exacly he same fucio, displaced by a ime τ : T ma cos ma U si Therefore, he ime averages of T ad U mus be equal. The, by akig ime average of (9), we fid b) Space average: The space averages of he kieic ad poeial eergies are T () E U ()
5 OSCILLATIONS 83 ad is readily iegraed o give T A A mx dx () A m U kx dx x A dx A A m A U (4) 6 To iegrae (), we oice ha from () ad () we ca wrie ( A x ) x A cos A si The, subsiuig (5) io (), we fid A m T A x A (5) dx or, 3 m 3 A A A 3 (6) From he compariso of (4) ad (7), we see ha To see ha his resul is reasoable, we plo T T(x) ad U U(x): U U(x) T T(x) m A T (7) 6 T U (8) x T m A A (9) U m x ma A O Eergy E cos. A ma Ad he area bewee T(x) ad he x-axis is jus wice ha bewee U(x) ad he x-axis. x
6 84 CHAPTER Differeiaig he equaio of moio for a simple harmoic oscillaor, we obai Bu from () Therefore, ad subsiuio io () yields x Asi () x A cos () x si A ( x ) cos A (4) x A x The, he fracio of a complee period ha a simple harmoic oscillaor speds wihi a small ierval x a posiio x is give by x x τ τ π A x A x τ (5) (6) A 3 A A A A 3 A x This resul implies ha he harmoic oscillaor speds mos of is ime ear x ±A, which is obviously rue. O he oher had, we obai a sigulariy for τ a x ±A. This occurs because a hese pois x, ad () is o valid k m m x x x Suppose he coordiaes of m ad m are x ad x ad he legh of he sprig a equilibrium is. The he equaios of moio for m ad m are mx k x x + () mx k x x + ()
7 OSCILLATIONS 85 From (), we have Subsiuig his expressio io (), we fid from which Therefore, x d d oscillaes wih he frequecy We obai he same resul for x ( m x + kx k ) k mmx + ( m + m) kx m + m (4) x kx (5) mm m + m k mm (6). If we oice ha he reduced mass of he sysem is defied as x we ca rewrie (6) as µ m + m (7) k (8) µ k µ This meas he sysem oscillaes i he same way as a sysem cosisig of a sigle mass µ. Iserig he give values, we obai µ 66.7 g ad.74 rad s A h s h b Le A be he cross-secioal area of he floaig body, h is heigh, h he heigh of is submerged par; ad le ρ ad ρ deoe he mass desiies of he body ad he fluid, respecively. The volume of displaced fluid is herefore V Ahs. The mass of he body is M ρahb. b s
8 86 CHAPTER 3 There are wo forces acig o he body: ha due o graviy (Mg), ad ha due o he fluid, pushig he body up ( ρgv ρghsa ). The equilibrium siuaio occurs whe he oal force vaishes: which gives he relaio bewee h ad h : s Mg ρ gv b ρgah ρ gh A () b s hs h ρ b ρ For a small displaceme abou he equilibrium posiio ( h Upo subsiuio of () io, we have or, () b b s Thus, he moio is oscillaory, wih a agular frequecy s h +x), () becomes Mx ρah x ρgah ρ g h + x A b s ρah x ρ gxa (4) ρ x + g x (5) ρh b b g ρ g ga (6) ρ h h V where use has bee made of (), ad i he las sep we have muliplied ad divided by A. The period of he oscillaios is, herefore, Subsiuig he give values, τ 8. s. s π V τ π (7) ga 3-8. y O l m s The force resposible for he moio of he pedulum bob is he compoe of he graviaioal force o m ha acs perpedicular o he sraigh porio of he suspesio srig. This compoe is see, from he figure (a) below, o be a a x F ma mv mg cos α ()
9 OSCILLATIONS 87 where α is he agle bewee he verical ad he age o he cycloidal pah a he posiio of m. The cosie of α is expressed i erms of he differeials show i he figure (b) as where dy cos α () ds ds dx + dy m mg α F α dy ds dx S (a) (b) The differeials, dx ad dy, ca be compued from he defiig equaios for x(φ) ad y(φ) above: ( cosφ) dx a dφ dy asi φ dφ (4) Therefore, ds dx + dy ( cos ) si ( cos ) a φ φ dφ a φ dφ + φ 4a si d φ (5) so ha Thus, The velociy of he pedulum bob is φ ds a si d φ (6) dy a si φ dφ ds φ asi d φ φ cos cos α (7)
10 88 CHAPTER 3 ds φ dφ v asi d d d φ 4a cos d (8) from which d φ v a d 4 cos (9) φ Leig z cos be he ew variable, ad subsiuig (7) ad (9) io (), we have 4maz mgz () or, g z+ z () 4a which is he sadard equaio for simple harmoic moio, If we ideify z+ () z g where we have used he fac ha 4a. Thus, he moio is exacly isochroous, idepede of he ampliude of he oscillaios. This fac was discovered by Chrisia Huygee (673) The equaio of moio for is while for, he equaio is I is coveie o defie which rasforms () ad () io mx k x x + F kx + F + kx () mx k x x kx + kx () ξ x x m ξ kξ+ F ; m ξ kξ ; (4)
11 OSCILLATIONS 89 The homogeeous soluios for boh ad (4) are of familiar form ξ Ae Be i i +, where km. A paricular soluio for is ξ F k. The he geeral soluios for ad (4) are F Ae i Be i ξ k + + ; (5) ξ Ce De i + i ; (6) + To deermie he cosas, we use he iiial codiios: The codiios give wo equaios for A ad B: ξ ( ) ξ ( ) x x ad x( ). Thus, (7) F + A + B k i ( A B) (8) The ad, from (5), we have Sice for ay physical moio, x ad are he iiial codiios for ξ The equaios i () ca be rewrie as: A B F k F ξ x x ( cos ) k ; (9) x mus be coiuous, he values of ξ ( ) ad ξ + which are eeded o deermie C ad D: F ξ+ ( ) ( cos) Ce + De k i i F ξ+ ( ) si i Ce De k F + k i i ( cos ) i i Ce De if k i i Ce De si The, by addig ad subracig oe from he oher, we obai ( ) F C e e k i i ( ) F D e e k i i () () ()
12 9 CHAPTER 3 Subsiuio of () io (6) yields F ξ+ e e + e e k i i i i Thus, F i( ) i ( e e e ) + e k i i F cos ( ) cos k x F x cos ( ) cos ; k (4) 3-. The ampliude of a damped oscillaor is expressed by β cos( δ ) Sice he ampliude decreases o e afer periods, we have x Ae + () βt β π () Subsiuig his relaio io he equaio coecig ad (he frequecy of udamped oscillaios), β, we have Therefore, so ha + + π 4π 4 + π 8 π (4) 3-. The oal eergy of a damped oscillaor is where E mx kx () () + () β cos( δ ) x Ae () β Ae cos( ) si ( ) x β δ δ ()
13 OSCILLATIONS 9 β, Subsiuig () ad io (), we have k m A E e m k m β () ( β + ) cos ( δ) + si ( δ) Rewriig (4), we fid he expressio for E(): ( ) mβ si δ cos δ + (4) ma e β δ β β δ + β () cos( ) + si E (5) Takig he derivaive of (5), we fid he expressio for de d : de ma e β 3 ( β 4β ) cos( δ ) d (6) 4β β si( δ) β The above formulas for E ad de d reproduce he curves show i Figure 3-7 of he ex. To fid he average rae of eergy loss for a lighly damped oscillaor, le us ake β. This meas ha he oscillaor has ime o complee some umber of periods before is ampliude decreases cosiderably, i.e. he erm e β does o chage much i he ime i akes o complee oe period. The cosie ad sie erms will average o early zero compared o he cosa erm i de d, ad we obai i his limi de β mβ A e (7) d 3-. θ l mg si θ mg The equaio of moio is m θ mgsi θ () g θ si θ If θ is sufficiely small, we ca approximae si θ θ, ad () becomes ()
14 9 CHAPTER 3 which has he oscillaory soluio g θ θ ( ) cos θ θ (4) where g ad where θ is he ampliude. If here is he reardig force m equaio of moio becomes or seig si θ θ ad rewriig, we have g θ, he m θ mgsi θ + m g θ (5) θ + θ + θ (6) Comparig his equaio wih he sadard equaio for damped moio [Eq. (3.35)], x + βx + x (7) we ideify β. This is jus he case of criical dampig, so he soluio for θ() is [see Eq. (3.43)] For he iiial codiios θ θ θ ( A B) e ad θ(), we fid + (8) () ( + ) e θ θ 3-3. For he case of criical dampig, β. Therefore, he equaio of moio becomes If we assume a soluio of he form we have x + βx + β x () x ye β () β β x ye βye β β β x ye βye + β ye Subsiuig io (), we fid β β β β β β ye βye + β ye + βye β ye + β ye (4) or, Therefore, y (5) y A+ B (6)
15 OSCILLATIONS 93 ad which is jus Eq. (3.43). () x A+ Be β (7) 3-4. For he case of overdamped oscillaios, x() ad x are expressed by β x e Ae Ae + () () e ( Ae Ae ) ( A e β ++ + Ae ) x β where β. Hyperbolic fucios are defied as () or, y y y y e + e e e cosh y, sih y e e y y cosh y+ sih y cosh y sih y (4) Usig (4) o rewrie () ad (), we have () ( ) ( + ) + ( ) x cosh β sih β A A cosh A A sih (5) ad () ( cosh β sih β ) ( β)( cosh + sih ) ( Aβ A)( cosh sih ) x A A + (6) 3-5. We are asked o simply plo he followig equaios from Example 3.: β Ae cos( ) x δ () v () Ae β cos δ + si δ β () wih he values A cm, rad s, β. s, ad δ π rad. The posiio goes hrough x a oal of 5 imes before droppig o. of is iiial ampliude. A exploded (or zoomed) view of figure (b), show here as figure (B), is he bes for deermiig his umber, as is easily show.
16 94 CHAPTER 3 (b) x() (cm) v() (cm/s) (s) (c).5 v (cm/s) x (cm) (B). x (cm) (s) 3-6. If he dampig resisace b is egaive, he equaio of moio is x βx + x () where β b m> because b <. The geeral soluio is jus Eq. (3.4) wih β chaged o β: β () e Aexp( β ) + Aexp( β ) x () From his equaio, we see ha he moio is o bouded, irrespecive of he relaive values of β ad. The hree cases disiguished i Secio 3.5 ow become: a) If > β, he moio cosiss of a oscillaory soluio of frequecy β, muliplied by a ever-icreasig expoeial:
17 OSCILLATIONS 95 b) If β, he soluio is which agai is ever-icreasig. β i i x e Ae Ae + x ( A+ Be ) β (4) c) If < β, he soluio is: where β x e Ae Ae + (5) β β (6) This soluio also icreases coiuously wih ime. The ree cases describe moios i which he paricle is eiher always movig away from is iiial posiio, as i cases b) or c), or i is oscillaig aroud is iiial posiio, bu wih a ampliude ha grows wih he ime, as i a). Because b <, he medium i which he paricle moves coiually gives eergy o he paricle ad he moio grows wihou boud For a damped, drive oscillaor, he equaio of moio is ad he average kieic eergy is expressed as T x βx + x Acos () ma β ( ) Le he frequecy ocaves above be labeled ad le he frequecy ocaves below be labeled ; ha is () The average kieic eergy for each case is T T ma 4 + (4) β ma 4 + (4) β (4) (5) Muliplyig he umeraor ad deomiaor of (5) by 4, we have
18 96 CHAPTER 3 Hece, we fid T ma 4 + (4) β T T (6) ad he proposiio is prove Sice we are ear resoace ad here is oly ligh dampig, we have R, where is he drivig frequecy. This gives Q β. To obai he oal eergy, we use he soluio o he drive oscillaor, eglecig he rasies: We he have cos( δ ) x D () md E mx + kx si ( δ) + cos ( δ) m D () The eergy los over oe period is where T π. Sice, we have which proves he asserio. T ( m β x) ( xd) π m β D E Q eergy los over oe period 4πβ π (4) 3-9. The ampliude of a damped oscillaor is [Eq. (3.59)] D A + β 4 () A he resoace frequecy, β, D becomes R D R A β β Le us fid he frequecy,, a which he ampliude is ( ) D R : A A DR β β + 4 β () Solvig his equaio for, we fid
19 OSCILLATIONS 97 β β ± β (4) For a lighly damped oscillaor, β is small ad he erms i β ca be egleced. Therefore, or, ± β (5) which gives β ± + β β β (7) We also ca approximae R for a lighly damped oscillaor: β (8) R Therefore, Q for a lighly damped oscillaor becomes Q β (9) (6) 3-. From Eq. (3.66), A () x si( δ ) ( ) + 4 β Therfore, he absolue value of he velociy ampliude v is give by v A 4 + β The value of for v a maximum, which is labeled v, is obaied from ad he value is v. v v Sice he Q of he oscillaor is equal o 6, we ca use Eqs. (3.63) ad (3.64) o express β i erms of : We eed o fid wo frequecies, ad, for which v vmax We fid β (4) 46, where v v ( ). max ()
20 98 CHAPTER 3 vmax A A β + 4 β ( ) (5) Subsiuig for β i erms of from (4), ad by squarig ad rearragig erms i (5), we obai from which (6) 73 ( ) (,, ) Solvig for, we obai, ±, ±, (7) 73 6 ± ±, I is sufficie for our purposes o cosider, posiive: he (8) so ha A graph of v vs. for Q 6 is show. + ; + (9) 6 () A v max β A β v We wa o plo Equaio (3.43), ad is derivaive: x A+ Be β () [ ] β where A ad B ca be foud i erms of he iiial codiios v B A+ B e β () A x B v βx + (4)
21 OSCILLATIONS 99 The iiial codiios used o produce figure (a) were ( x v ),,, (, 4), (4, ), (, 4), 4 (, 4), ad (, 4 ), where we ake all x o be i cm, all v i cm s, ad β s. Figure (b) is a magified view of figure (a). The dashed lie is he pah ha all pahs go o asympoically as. This ca be foud by akig he limis. so ha i his limi, v βx, as required. (a) 4 3 lim v βbe β (5) lim x Be β (6) v (cm/s) 3 (b) x (cm).4. v (cm/s) x (cm) 3-. For overdamped moio, he posiio is give by Equaio (3.44) x Ae + Ae β β ()
22 CHAPTER 3 The ime derivaive of he above equaio is, of course, he velociy: a) A : The iiial codiios A. b) Whe A, we have v β x have e β β β β v A e Aβ e x A + A v Aβ Aβ (4) x ad v ca ow be used o solve for he iegraio cosas A ad ad v β x x v β A β as sice β < β. quie easily. For A, however, we () 3-3. Firsly, we oe ha all he δ π soluios are jus he egaive of he δ soluios. The δ π soluios do make i all he way up o he iiial ampliude, A, due o he reardig force. Higher β meas more dampig, as oe migh expec. Whe dampig is high, less oscillaio is observable. I paricular, β 9. would be much beer for a kiche door ha a smaller β, e.g. he door closig (δ ), or he closed door beig bumped by someoe who he chages his/her mid ad does o go hrough he door ( δ π ).
23 OSCILLATIONS β., δ β.5, δ β.9, δ.5.5 β., δ π/ β.5, δ π/ β.9, δ π/.5.5 β., δ π β.5, δ π β.9, δ π As requesed, we use Equaios (3.4), (3.57), ad (3.6) wih he give values o evaluae he complemeary ad paricular soluios o he drive oscillaor. The ampliude of he complemeary fucio is cosa as we vary, bu he ampliude of he paricular soluio becomes larger as goes hrough he resoace ear 96. rad s, ad decreases as is icreased furher. The plo closes o resoace here has., which shows he leas disorio due o rasies. These figures are show i figure (a). I figure (b), he 6 plo from figure (a) is reproduced alog wih a ew plo wih A p m s.
24 CHAPTER 3 / /9 / /3 /. 3 / / 6.5 (s) (s).5 3 (s) Leged: xc xp x (a) A p A p (b) 3-5. This problem is early ideical o he previous problem, wih he excepio ha ow Equaio (3.43) is used isead of (3.4) as he complemeary soluio. The disorio due o he rasie icreases as icreases, mosly because he complemeary soluio has a fixed ampliude whereas he ampliude due o he paricular soluio oly decreases as icreases. The laer fac is because here is o resoace i his case.
25 OSCILLATIONS 3 / /9 / /3 / / 3 5 / 6 5 / 6, A p Leged: xc xp x 3-6. The equaios of moio of his sysem are mx kx b x x + Fcos mx bx b( x x ) The elecrical aalog of his sysem ca be cosruced if we subsiue i () he followig equivale quaiies: m L ; m L ; F ε k ; b R ; x q C ; b R The he equaios of he equivale elecrical circui are give by Lq + R( q q ) + qεcos C Lq + Rq + R( q q ) () () Usig he mahemaical device of wriig exp(i) isead of cos i (), wih he udersadig ha i he resuls oly he real par is o be cosidered, ad differeiaig wih respec o ime, we have
26 4 CHAPTER 3 I i LI + R I I + iεe C LI + R( I ) + R( I I ) The, he equivale elecrical circui is as show i he figure: L The impedace of he sysem Z is I () ε cos C I () R R L Z il i + Z (4) C where Z is give by The, ad subsiuig (6) io (4), we obai Z + + Z R R il R R R + R + L + il R R + R + L R R ( R + R ) + L + i RL + L ( R + R ) + L C Z R R L + + (5) (6) (7) 3-7. From Eq. (3.89), We wrie F () a + ( a cos + b si ) () () F () a + c cos ( φ ) which ca also be wrie usig rigoomeric relaios as F() a + c cos cos φ + si si φ Comparig wih (), we oice ha if here exiss a se of coefficies c such ha
27 OSCILLATIONS 5 c c cos φ a si φ b (4) he () is equivale o (). I fac, from (4), c a + b b a φ a (5) wih a ad b as give by Eqs. (3.9) Sice F() is a odd fucio, F( ) F(), accordig o Eq. (3.9) all he coefficies vaish ideically, ad he b are give by a π b π F( ) si d π π π si d si d π + cos + cos π π cos cos π ( π ) π Thus, 4 for odd π () for eve b ( + ) b ( ) 4 ( + ) π,,, () The, we have F () si + si 3+ si 5+ π 3π 5π
28 6 CHAPTER 3 π F() π π π Terms +.99 π π Terms π π Terms I order o Fourier aalyze a fucio of arbirary period, say τ P isead of π, proporioal chage of scale is ecessary. Aalyically, such a chage of scale ca be represeed by he subsiuio for whe, he x, ad whe Thus, whe he subsiuio fucio π x or P τ P, he x π. Px () π Px π is made i a fucio F() of period P, we obai he Px F f x π ad his, as a fucio of x, has a period of π. Now, f(x) ca, of course, be expaded accordig o he sadard formula, Eq. (3.9): where f ( x) a + ( a cos x+ b si x) ()
29 OSCILLATIONS 7 π a f ( x ) cos x d π x π b f ( x ) si x dx π If, i he above expressios, we make he iverse subsiuios he expasio becomes π π x ad dx d (5) P P π P π a π π f F F() a cos b si P π P + + P P (6) ad he coefficies i (4) become (4) P π a F( ) cos P d P P π b F( ) si d P P (7) For he case correspodig o his problem, he period of F() is 4π, so ha P π. The, subsiuig io (7) ad replacig he iegral limis ad τ by he limis obai τ ad τ +, we ad subsiuig io (6), he expasio for F() is a b π π F( ) cos π d π π F( ) si d π (8) a F () + a cos b si + (9) Subsiuig F() io (8) yields Evaluaio of he iegrals gives a b π si cos π d π si si d π ()
30 8 CHAPTER 3 ad he resulig Fourier expasio is b ; b for eve a a a ( ) 4 odd π ( 4) () F () si + cos cos cos cos + () 3π 5π π 45π 3-3. The oupu of a full-wave recifier is a periodic fucio F() of he form π si ; < F () π si ; < < The coefficies i he Fourier represeaio are give by π a π ( si ) cos d si cos π + d π b π ( si ) si d + si si d π Performig he iegraios, we obai a b 4 ; if eve ( or ) π ( ) ; if odd for all () () The expasio for F() is 4 4 F () cos cos 4 (4) π 3π 5π The exac fucio ad he sum of he firs hree erms of (4) are show below.
31 OSCILLATIONS 9 Sum of firs hree erms F().5 si π π π π 3-3. We ca rewrie he forcig fucio so ha i cosiss of wo forcig fucios for > τ: () F m < ( τ ) a a ( τ) ( τ ) a > τ τ < < τ () Durig he ierval < < τ, he differeial equaio which describes he moio is The paricular soluio is xp a x + βx + x () τ C+D, ad subsiuig his io (), we fid from which Therefore, we have which gives a βc+ C+ D τ βc + D (4) a C τ βa a D, C τ τ 4 a βa xp 4 τ τ (5) (6) Thus, he geeral soluio for < < τ is ad he, a β a τ (7) β () e A cos + Bsi + 4 τ x
32 CHAPTER 3 β β a () β cos + si + si + cos + x e A B e A B (8) τ The iiial codiios, x(), x, implies Therefore, he respose fucio is βa A 4 τ a β B τ (9) () x β a β β e β β e cos + si + () τ ( τ ) a For he forcig fucio i (), we have a respose similar o (). Thus, we add hese τ wo equaios o obai he oal respose fucio: β a β β β e β x () e ( cos e cos ( τ) ) + τ β si + e si τ + τ () Whe τ, we ca approximae e βτ as + βτ, ad also si τ τ, cos τ. The, β a β β e β x () e cos ( βτ)( cos τ si ) τ τ si + βτ si τ cos + τ 3 a β β β β β e cos e + si () If we use β, he coefficie of e β si becomes β. Therefore, a β β β x () e cos e si τ This is jus he respose for a sep fucio a) Respose o a Sep Fucio: From Eq. (3.) H ( ) is defied as
33 OSCILLATIONS H Wih iiial codiios x ( ) ad x ( ), < a, > moio of a damped liear oscillaor) is give by Eq. (3.5):, he geeral soluio o Eq. (3.) (equaio of β( ) a β( ) βe x () cos e ( ) si ( ) for > x () for < () () where β. For he case of overdampig, < β, ad cosequely β is a pure imagiary umber. Hece, cos ( ) ad ( ) i si are o loger oscillaory fucios; isead, hey are rasformed io hyperbolic fucios. Thus, if we wrie β (where is real), The respose is give by [see Eq. (3.5)] ( ) i ( ) ( ) cos cos cosh si ( ) si i( ) isih ( ) β( ) a β( ) βe x () cosh e ( ) sih ( ) for > x () for < (4) For simpliciy, we choose, ad he soluio becomes β H () β βe x e cosh sih (5) This respose is show i (a) below for he case β 5. b) Respose o a Impulse Fucio (i he limi τ ): From Eq. (3.) he impulse fucio (, ) I is defied as < I (, ) a < < > For τ i such a way ha aτ is cosa b, he respose fucio is give by Eq. (3.): (6)
34 CHAPTER 3 x b e (7) β( ) () si for > Agai akig he spike o be a for simpliciy, we have b β x () e si () for > (8) For i i β (overdamped oscillaor), he soluio is This respose is show i (b) below for he case β 5. b β x () e sih ; > (9) (a) x H (b) x b a) I order o fid he maximum ampliude of he respose fucio show i Fig. 3-, we look for such ha x give by Eq. (3.5) is maximum; ha is, ( x ()) () From Eq. (3.6) we have ( x ) H β β e si + ()
35 OSCILLATIONS 3 For β., β.98. Evidely, π makes () vaish. (This is he absolue maximum, as ca be see from Fig. 3-.) The, subsiuig io Eq. (3.5), he maximum ampliude is give by or, a x x max e βπ () + x.53 a (4) b) I he same way we fid he maximum ampliude of he respose fucio show i Fig. 3-4 by usig x() give i Eq. (3.); he, ( x ()) β( ) β be cos ( ) si ( ) (5) If (5) is o vaish, is give by.37 β a a 4.9 Subsiuig (6) io Eq. (3.), we obai (for β. ) (6) or, β.37 b x () x e si(.37) (7) max.98 x.76 a τ (8) The respose fucio of a udamped (β ) liear oscillaor for a impulse fucio π I(,τ), wih τ, ca be obaied from Eqs. (3.5) ad (3.8) if we make he followig subsiuios: β ; π () ; τ (For coveiece we have assumed ha he impulse forcig fucio is applied a.) Hece, afer subsiuig we have
36 4 CHAPTER 3 x < a π x () cos < < a π x () cos ( w π) cosw τ > This respose fucio is show below. Sice he oscillaor is udamped, ad sice he impulse lass exacly oe period of he oscillaor, he oscillaor is reured o is equilibrium codiio a he ermiaio of he impulse. a () a π π The equaio for a drive liear oscillaor is x+ βx + w x f where f() is he siusoid show i he diagram. f() a I II III Regio I: x () Regio II: x+ βx + x asi () The soluio of () is i which Regio III: x+ βx + x ( si cos ) β x e A B x P + + (4) x Da (5) P si ( δ ) where D ( ) + 4 β (6)
37 OSCILLATIONS 5 Thus, The iiial codiio x() gives ad x δ β a ( Asi Bcos ) Dasi ( ) β x e + + δ (8) B adsi δ (9) (7) or, The soluio of is βb+ A+ Da cos δ ad A ( β si δ cos δ) () We require ha x ad x π π x gives II III β si x e A + B cos () x for regios II ad III mach a π. The codiio ha βπ ( si + Bcos ) + Dasi ( ) e ( A si + B cos φ ) βπ e A φ φ π δ φ where φ π or, ad si δ βπ A + B co φ A+ Bcoφ+ e () si φ The codiio ha x π π II xiii gives or, or, βπ ( si cos ) cos ( cos si φ) βπ βe A φ+ B φ + ad π δ + e A φ B βπ ( si cos ) ( cos si ) βπ βe A φ+ B φ + e A φ B φ ( cos φ β si φ) B ( si φ+ β cos φ) A ( ) ( ) A β si φ+ cos φ B si φ+ β cos φ e βπ ad cos δ si φ+ β cos φ si φ+ β cos φ Da cos δ cosφ β si φ cos φ β si φ cos φ β si φ A B A B e βπ
38 6 CHAPTER 3 Subsiuig io from (), we have B ( ) + ( + ) ( cos φ β si φ) si φ cos φ β si φ cos φ si φ β cos φ si φ from which (4) ( cos φ β si φ) cos φ+ ( si φ+ β cos φ) si φ si δ cos δ + ade ( cos si ) βπ + φ β φ si φ si φ cos φ β si φ Usig (), we ca fid A : a B adsi δ + De βπ si δ ( cos φ βsi φ) + cos δsi φ (5) βπ ad si δe A A+ Bco φ + B co φ (6) si φ Subsiuig for A, B, ad B from (), (9), ad (5), we have β βπ β ad cos δ βπ A adsi δ + e cos φ si φ ( e cos ) + + φ (7) Thus, we obaied all cosas givig us he respose fucios explicily Wih he iiial codiios, x x ad > give by Eq. (3.3) yields a x βx + A x ; A x x, he soluio for a sep fucio for Therefore, he respose o H ( ) for he iiial codiios above ca be expressed as βa x βx x e x β( ) () cos ( ) + + si ( ) a β( ) β β( ) + cos e ( ) e si ( ) for > The respose o a impulse fucio I (, ) H give by () for < < ad by a superposiio of soluios for H ( ) ad for, for he above iiial codiios will he be H ake idividually for >. We mus be careful, however, because he soluio for > mus be equal ha give by () for. This ca be isured by usig as a soluio for H ( ) Eq. (3.3) wih iiial codiios x, x, ad usig isead of i he expressio. The soluio for > is he () ()
39 OSCILLATIONS 7 where β( ) x βx x () e x cos + + si + x() β( ) ae βτ x() e cos ( τ) cos ( ) + βτ βe β + si ( τ) si ( ) for > βe βτ (4) We ow allow a as τ i such a way ha aτ b cosa; expadig for his paricular case, we obai β( ) x βx b x () e x cos si > (5) which is aalogous o Eq. (3.9) bu for iiial codiios give above Ay fucio F m ca be expaded i erms of sep fucios, as show i he figure below where he curve is he sum of he various (posiive ad egaive) sep fucios. I geeral, we have x + βx + x F m H () () where H () a > τ < τ The, sice () is a liear equaio, he soluio o a superposiio of fucios of he form give by () is he superposiio of he soluios for each of hose fucios. Accordig o Eq. (3.5), he soluio for H for > is () he, for β( ) a β( ) βe x() e cos ( ) si ( ) F m () H (4) he soluio is
40 8 CHAPTER 3 β( ) β( ) βe x () H() e cos( ) si () () () () mh G F G (5) where G () or, comparig wih β( ) β( ) βe cos e ( ) si ( ) ; m < G (), x ma < Therefore, he Gree s fucio is he respose o he ui sep. (6) (7) () F m H () The soluio for x() accordig o Gree s mehod is () (, ) x F G d F m γ β( ) e si e si ( ) d () Usig he rigoomeric ideiy, si si ( ) cos ( + ) cos ( ) + () we have
41 OSCILLATIONS 9 β Fe β γ β γ x () de cos ( ) de cos ( ) m + + z + Makig he chage of variable, for he secod iegral, we fid, for he firs iegral ad ( β γ) ( β γ) β + ( β γ) z ( β γ) y + dze cos z dye cos y y + Fe e e x () m + (4) Afer evaluaig he iegrals ad rearragig erms, we obai F x () m ( β γ) + ( + ) ( β γ) + ( ) γ si e ( γ β) cos+ [ β γ ] + β si + e ( β γ) cos+ [ β γ ] + (5) si < < π F () π < < π From Equaios 3.89, 3.9, ad 3.9, we have F a a b () + ( cos + si ) τ a F( ) cos τ d τ b F( ) si τ d π a si cos d π a π si d π π π a si cos d π
42 CHAPTER 3 ( ) ( ) π cos cos + a ( ) si cos d π π + Upo evaluaig ad simplifyig, he resul is π a eve π ( ) odd,,, b by ispecio b π π si d ( ) ( ) π si si + b ( ) si si d π π + π So or, leig F + + () si π π,4,6, ( ),, cos F () + si + cos π π 4 ( ) The followig plo shows how well he firs four erms i he series approximae he fucio.. Sum of firs four erms The equaio describig he car s moio is π π dy m k y asi d where y is he verical displaceme of he car from is equilibrium posiio o a fla road, a is he ampliude of sie-curve road, ad k elasic coefficie dm g N/m dy.
43 OSCILLATIONS πv λ The soluio of he moio equaio ca be cas i he form 74 rad/s wih v ad λ beig he car s speed ad wavelegh of sie-curve road. a y B + β + si cos wih k 9.9 rad/s m We see ha he oscillaio wih agular frequecy has ampliude a A.6 mm The mius sig jus implies ha he sprig is compressed a) The geeral soluio of he give differeial equaio is (see Equaio (3.37)) ad exp ( β ) exp β + exp β x A A β ( β ) ( β ) ( β ) v () x exp Aexp + A exp a, x () x, v () v ( β) β A ( β ) A ( β ) + exp exp exp A x + v + βx β ad A v + βx x β () b) i) Uderdamped, β I his case, isead of usig above parameerizaio, i is more coveie o work wih he followig parameerizaio ( β ) ( β δ) x () Aexp cos () ( β ) β ( β δ) β ( β δ) v () Aexp cos + si Usig iiial codiios of x() ad v(), we fid x v A + β β x + β ad a ( δ) v x + β β
44 CHAPTER 3 I he case β, ad usig (6) below we have so fially a δ v 3 x x v v A + + x 3 3 x x δ 3 3 () exp cos 3 3 x x + (4) ii) Criically damped, β, usig he same parameerizaio as i i) we have from () ad : ad v () x() xexp( v x x () Aexp x exp (5) β (6) iii) Overdamped, β, reurig o he origial parameerizaio () we have (always usig relaio (6)), exp( β ) exp( β ) + exp( β ) x A A ( x ) + ( ) 3 + x 3 exp 3 exp 3 + (7) 3 3 Below we show skeches for equaios (4), (5), (7) x Uderdamped Criically damped Overdamped 3-4. a) The mos geeral soluio is ( ) where he las erm is a paricular soluio. mx + x Fsi () x asi + bcos + Asi
45 OSCILLATIONS 3 To fid A we pu his paricular soluio (he las erm) io () ad fid F A m A, x, so we fid b, ad he we have ( ) x () asi + Asi v () a cos + A cos A, v A a F m x () si si + b) I he limi oe ca see ha 3 F x () 6m The skech of his fucio is show below. x a) Poeial eergy is he elasic eergy: Ur () kr ( a), where m is movig i a ceral force field. The he effecive poeial is (see for example, Chaper ad Equaio (8.4)): l l Ueff () r U() r + k( r a) + mr mr where l mvr m r is he agular momeum of m ad is a coserved quaiy i his problem. The solid lie below is U () r ; a low values of r, he dashed lie represes Ur () kr a, ad he solid lie is domiaed by l mr Ueff () r U() r k( r a). eff. A large values of r,
46 4 CHAPTER 3 Poeial eergy l mr Ur () kr ( a) b) I equilibrium circular moio of radius r, we have kr a m r U ( a) kr mr r r eff () c) For give (ad fixed) agular momeum l, V(r) is miimal a r, because V () r, so we make a Taylor expasio of V(r) abou r ; r r where 3 m ( r r) K( r r) Vr Vr ( ) + ( r r) V ( r) + ( r r) V ( r) +... K 3m, so he frequecy of oscillaio is K 3 m 3( kr a) mr This oscillaio mus be uderdamped oscillaio (oherwise o period is prese). From Equaio (3.4) we have so he iiial ampliude (a ) is A. 8π Now a 4T ( β ) ( δ) x () Aexp cos 8π x(4 T) Aexp β cos (8 π δ) The ampliude ow is 8π A exp β, so we have
47 OSCILLATIONS 5 ad because β, we fially fid 8π A exp β A e 8π π Eergy of a simple pedulum is For a slighly damped oscillaio θ θexp( β). mgl θ where θ is he ampliude. Iiial eergy of pedulum is mgl θ. Eergy of pedulum afer oe period, T π So eergy los i oe period is So eergy los afer 7 days is l g, is mgl mgl θ T θ βt exp( ) mgl mgl θ ( exp( βt) ) θ βt mglθ β T (7 days) mglθβt mglθβ(7 days) T This eergy mus be compesaed by poeial eergy of he mass M as i falls h meers: Mh Mgh mglθβ(7 days) β. s mlθ (7 days) Kowig β we ca easily fid he coefficie Q (see Equaio (3.64)) g β β R Q l 78 β β β
48 6 CHAPTER 3
Fourier Series. Fourier Series
ECE 37 Z. Aliyazicioglu Elecrical & Compuer Egieerig Dep. Cal Poly Pomoa Periodic sigal is a fucio ha repeas iself every secods. x() x( ± ) : period of a fucio, : ieger,,3, x() 3 x() x() Periodic sigal
Διαβάστε περισσότερα) 2. δ δ. β β. β β β β. r k k. tll. m n Λ + +
Techical Appedix o Hamig eposis ad Helpig Bowes: The ispaae Impac of Ba Cosolidaio (o o be published bu o be made available upo eques. eails of Poofs of Poposiios 1 ad To deive Poposiio 1 s exac ad sufficie
Διαβάστε περισσότερα8. The Normalized Least-Squares Estimator with Exponential Forgetting
Lecure 5 8. he Normalized Leas-Squares Esimaor wih Expoeial Forgeig his secio is devoed o he mehod of Leas-Squares wih expoeial forgeig ad ormalizaio. Expoeial forgeig of daa is a very useful echique i
Διαβάστε περισσότεραAPPENDIX A DERIVATION OF JOINT FAILURE DENSITIES
APPENDIX A DERIVAION OF JOIN FAILRE DENSIIES I his Appedi we prese he derivaio o he eample ailre models as show i Chaper 3. Assme ha he ime ad se o ailre are relaed by he cio g ad he sochasic are o his
Διαβάστε περισσότερα1. For each of the following power series, find the interval of convergence and the radius of convergence:
Math 6 Practice Problems Solutios Power Series ad Taylor Series 1. For each of the followig power series, fid the iterval of covergece ad the radius of covergece: (a ( 1 x Notice that = ( 1 +1 ( x +1.
Διαβάστε περισσότεραCHAPTER 103 EVEN AND ODD FUNCTIONS AND HALF-RANGE FOURIER SERIES
CHAPTER 3 EVEN AND ODD FUNCTIONS AND HALF-RANGE FOURIER SERIES EXERCISE 364 Page 76. Determie the Fourier series for the fuctio defied by: f(x), x, x, x which is periodic outside of this rage of period.
Διαβάστε περισσότεραOSCILLATION CRITERIA FOR SECOND ORDER HALF-LINEAR DIFFERENTIAL EQUATIONS WITH DAMPING TERM
DIFFERENIAL EQUAIONS AND CONROL PROCESSES 4, 8 Elecroic Joural, reg. P375 a 7.3.97 ISSN 87-7 hp://www.ewa.ru/joural hp://www.mah.spbu.ru/user/diffjoural e-mail: jodiff@mail.ru Oscillaio, Secod order, Half-liear
Διαβάστε περισσότεραHomework for 1/27 Due 2/5
Name: ID: Homework for /7 Due /5. [ 8-3] I Example D of Sectio 8.4, the pdf of the populatio distributio is + αx x f(x α) =, α, otherwise ad the method of momets estimate was foud to be ˆα = 3X (where
Διαβάστε περισσότεραIntrinsic Geometry of the NLS Equation and Heat System in 3-Dimensional Minkowski Space
Adv. Sudies Theor. Phys., Vol. 4, 2010, o. 11, 557-564 Irisic Geomery of he NLS Equaio ad Hea Sysem i 3-Dimesioal Mikowski Space Nevi Gürüz Osmagazi Uiversiy, Mahemaics Deparme 26480 Eskişehir, Turkey
Διαβάστε περισσότεραL.K.Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 4677 + {JEE Mai 04} Sept 0 Name: Batch (Day) Phoe No. IT IS NOT ENOUGH TO HAVE A GOOD MIND, THE MAIN THING IS TO USE IT WELL Marks:
Διαβάστε περισσότεραIIT JEE (2013) (Trigonomtery 1) Solutions
L.K. Gupta (Mathematic Classes) www.pioeermathematics.com MOBILE: 985577, 677 (+) PAPER B IIT JEE (0) (Trigoomtery ) Solutios TOWARDS IIT JEE IS NOT A JOURNEY, IT S A BATTLE, ONLY THE TOUGHEST WILL SURVIVE
Διαβάστε περισσότεραErrata (Includes critical corrections only for the 1 st & 2 nd reprint)
Wedesday, May 5, 3 Erraa (Icludes criical correcios oly for he s & d repri) Advaced Egieerig Mahemaics, 7e Peer V O eil ISB: 978474 Page # Descripio 38 ie 4: chage "w v a v " "w v a v " 46 ie : chage "y
Διαβάστε περισσότεραn r f ( n-r ) () x g () r () x (1.1) = Σ g() x = Σ n f < -n+ r> g () r -n + r dx r dx n + ( -n,m) dx -n n+1 1 -n -1 + ( -n,n+1)
8 Higher Derivative of the Product of Two Fuctios 8. Leibiz Rule about the Higher Order Differetiatio Theorem 8.. (Leibiz) Whe fuctios f ad g f g are times differetiable, the followig epressio holds. r
Διαβάστε περισσότερα2 Composition. Invertible Mappings
Arkansas Tech University MATH 4033: Elementary Modern Algebra Dr. Marcel B. Finan Composition. Invertible Mappings In this section we discuss two procedures for creating new mappings from old ones, namely,
Διαβάστε περισσότεραDegenerate Perturbation Theory
R.G. Griffi BioNMR School page 1 Degeerate Perturbatio Theory 1.1 Geeral Whe cosiderig the CROSS EFFECT it is ecessary to deal with degeerate eergy levels ad therefore degeerate perturbatio theory. The
Διαβάστε περισσότεραSUPERPOSITION, MEASUREMENT, NORMALIZATION, EXPECTATION VALUES. Reading: QM course packet Ch 5 up to 5.6
SUPERPOSITION, MEASUREMENT, NORMALIZATION, EXPECTATION VALUES Readig: QM course packet Ch 5 up to 5. 1 ϕ (x) = E = π m( a) =1,,3,4,5 for xa (x) = πx si L L * = πx L si L.5 ϕ' -.5 z 1 (x) = L si
Διαβάστε περισσότεραCHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS
CHAPTER 5 SOLVING EQUATIONS BY ITERATIVE METHODS EXERCISE 104 Page 8 1. Find the positive root of the equation x + 3x 5 = 0, correct to 3 significant figures, using the method of bisection. Let f(x) =
Διαβάστε περισσότεραMath221: HW# 1 solutions
Math: HW# solutions Andy Royston October, 5 7.5.7, 3 rd Ed. We have a n = b n = a = fxdx = xdx =, x cos nxdx = x sin nx n sin nxdx n = cos nx n = n n, x sin nxdx = x cos nx n + cos nxdx n cos n = + sin
Διαβάστε περισσότεραRG Tutorial xlc3.doc 1/10. To apply the R-G method, the differential equation must be represented in the form:
G Tuorial xlc3.oc / iear roblem i e C i e C ( ie ( Differeial equaio for C (3 Thi fir orer iffereial equaio ca eaily be ole bu he uroe of hi uorial i o how how o ue he iz-galerki meho o fi ou he oluio.
Διαβάστε περισσότεραThe Heisenberg Uncertainty Principle
Chemistry 460 Sprig 015 Dr. Jea M. Stadard March, 015 The Heiseberg Ucertaity Priciple A policema pulls Werer Heiseberg over o the Autobah for speedig. Policema: Sir, do you kow how fast you were goig?
Διαβάστε περισσότεραVidyalankar. Vidyalankar S.E. Sem. III [BIOM] Applied Mathematics - III Prelim Question Paper Solution. 1 e = 1 1. f(t) =
. (a). (b). (c) f() L L e i e Vidyalakar S.E. Sem. III [BIOM] Applied Mahemaic - III Prelim Queio Paper Soluio L el e () i ( ) H( ) u e co y + 3 3y u e co y + 6 uy e i y 6y uyy e co y 6 u + u yy e co y
Διαβάστε περισσότεραω = radians per sec, t = 3 sec
Secion. Linear and Angular Speed 7. From exercise, =. A= r A = ( 00 ) (. ) = 7,00 in 7. Since 7 is in quadran IV, he reference 7 8 7 angle is = =. In quadran IV, he cosine is posiive. Thus, 7 cos = cos
Διαβάστε περισσότεραExample Sheet 3 Solutions
Example Sheet 3 Solutions. i Regular Sturm-Liouville. ii Singular Sturm-Liouville mixed boundary conditions. iii Not Sturm-Liouville ODE is not in Sturm-Liouville form. iv Regular Sturm-Liouville note
Διαβάστε περισσότεραTime Series Analysis Final Examination
Dr. Sevap Kesel Time Series Aalysis Fial Examiaio Quesio ( pois): Assume you have a sample of ime series wih observaios yields followig values for sample auocorrelaio Lag (m) ˆ( ρ m) -0. 0.09 0. Par a.
Διαβάστε περισσότερα4.6 Autoregressive Moving Average Model ARMA(1,1)
84 CHAPTER 4. STATIONARY TS MODELS 4.6 Autoregressive Moving Average Model ARMA(,) This section is an introduction to a wide class of models ARMA(p,q) which we will consider in more detail later in this
Διαβάστε περισσότεραLast Lecture. Biostatistics Statistical Inference Lecture 19 Likelihood Ratio Test. Example of Hypothesis Testing.
Last Lecture Biostatistics 602 - Statistical Iferece Lecture 19 Likelihood Ratio Test Hyu Mi Kag March 26th, 2013 Describe the followig cocepts i your ow words Hypothesis Null Hypothesis Alterative Hypothesis
Διαβάστε περισσότεραUniversity of Washington Department of Chemistry Chemistry 553 Spring Quarter 2010 Homework Assignment 3 Due 04/26/10
Universiy of Washingon Deparmen of Chemisry Chemisry 553 Spring Quarer 1 Homework Assignmen 3 Due 4/6/1 v e v e A s ds: a) Show ha for large 1 and, (i.e. 1 >> and >>) he velociy auocorrelaion funcion 1)
Διαβάστε περισσότεραThe Estimates of the Upper Bounds of Hausdorff Dimensions for the Global Attractor for a Class of Nonlinear
Advaces i Pure Mahemaics 8 8 - hp://wwwscirporg/oural/apm ISSN Olie: 6-384 ISSN Pri: 6-368 The Esimaes of he Upper Bouds of Hausdorff Dimesios for he Global Aracor for a Class of Noliear Coupled Kirchhoff-Type
Διαβάστε περισσότεραHOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:
HOMEWORK 4 Problem a For the fast loading case, we want to derive the relationship between P zz and λ z. We know that the nominal stress is expressed as: P zz = ψ λ z where λ z = λ λ z. Therefore, applying
Διαβάστε περισσότεραh(t) δ(t+3) ( ) h(t)*δ(t)
f()* δ ( ) = f( ) x () = δ ( + 3) = 3 h () = u () u ( ) h()* δ ( + 3) = h ( + 3) = u ( + 3) u ( + 1) 1 h() * -3 δ(+3) ( ) h()*δ() 1-3 -1 MY : Σήματα και Συστήματα Ι ΔΙΑΛΕΞΗ #6 Μοντέλα διαφορικών εξισώσεων
Διαβάστε περισσότεραAppendix. The solution begins with Eq. (2.15) from the text, which we repeat here for 1, (A.1)
Aenix Aenix A: The equaion o he sock rice. The soluion egins wih Eq..5 rom he ex, which we reea here or convenience as Eq.A.: [ [ E E X, A. c α where X u ε, α γ, an c α y AR. Take execaions o Eq. A. as
Διαβάστε περισσότερα16. 17. r t te 2t i t 1. 18 19 Find the derivative of the vector function. 19. r t e t cos t i e t sin t j ln t k. 31 33 Evaluate the integral.
SECTION.7 VECTOR FUNCTIONS AND SPACE CURVES.7 VECTOR FUNCTIONS AND SPACE CURVES A Click here for answers. S Click here for soluions. Copyrigh Cengage Learning. All righs reserved.. Find he domain of he
Διαβάστε περισσότεραHomework 4.1 Solutions Math 5110/6830
Homework 4. Solutios Math 5/683. a) For p + = αp γ α)p γ α)p + γ b) Let Equilibria poits satisfy: p = p = OR = γ α)p ) γ α)p + γ = α γ α)p ) γ α)p + γ α = p ) p + = p ) = The, we have equilibria poits
Διαβάστε περισσότεραα β
6. Eerg, Mometum coefficiets for differet velocit distributios Rehbock obtaied ) For Liear Velocit Distributio α + ε Vmax { } Vmax ε β +, i which ε v V o Give: α + ε > ε ( α ) Liear velocit distributio
Διαβάστε περισσότεραSolve the difference equation
Solve the differece equatio Solutio: y + 3 3y + + y 0 give tat y 0 4, y 0 ad y 8. Let Z{y()} F() Taig Z-trasform o both sides i (), we get y + 3 3y + + y 0 () Z y + 3 3y + + y Z 0 Z y + 3 3Z y + + Z y
Διαβάστε περισσότεραBessel function for complex variable
Besse fuctio for compex variabe Kauhito Miuyama May 4, 7 Besse fuctio The Besse fuctio Z ν () is the fuctio wich satisfies + ) ( + ν Z ν () =. () Three kids of the soutios of this equatio are give by {
Διαβάστε περισσότεραConcrete Mathematics Exercises from 30 September 2016
Concrete Mathematics Exercises from 30 September 2016 Silvio Capobianco Exercise 1.7 Let H(n) = J(n + 1) J(n). Equation (1.8) tells us that H(2n) = 2, and H(2n+1) = J(2n+2) J(2n+1) = (2J(n+1) 1) (2J(n)+1)
Διαβάστε περισσότεραPresentation of complex number in Cartesian and polar coordinate system
1 a + bi, aεr, bεr i = 1 z = a + bi a = Re(z), b = Im(z) give z = a + bi & w = c + di, a + bi = c + di a = c & b = d The complex cojugate of z = a + bi is z = a bi The sum of complex cojugates is real:
Διαβάστε περισσότεραAreas and Lengths in Polar Coordinates
Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the
Διαβάστε περισσότεραAreas and Lengths in Polar Coordinates
Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the
Διαβάστε περισσότεραFourier Series. constant. The ;east value of T>0 is called the period of f(x). f(x) is well defined and single valued periodic function
Fourier Series Periodic uctio A uctio is sid to hve period T i, T where T is ve costt. The ;est vlue o T> is clled the period o. Eg:- Cosider we kow tht, si si si si si... Etc > si hs the periods,,6,..
Διαβάστε περισσότεραMatrices and Determinants
Matrices and Determinants SUBJECTIVE PROBLEMS: Q 1. For what value of k do the following system of equations possess a non-trivial (i.e., not all zero) solution over the set of rationals Q? x + ky + 3z
Διαβάστε περισσότεραDESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0.
DESIGN OF MACHINERY SOLUTION MANUAL -7-1! PROBLEM -7 Statement: Design a double-dwell cam to move a follower from to 25 6, dwell for 12, fall 25 and dwell for the remader The total cycle must take 4 sec
Διαβάστε περισσότεραFREE VIBRATION OF A SINGLE-DEGREE-OF-FREEDOM SYSTEM Revision B
FREE VIBRATION OF A SINGLE-DEGREE-OF-FREEDOM SYSTEM Revisio B By Tom Irvie Email: tomirvie@aol.com February, 005 Derivatio of the Equatio of Motio Cosier a sigle-egree-of-freeom system. m x k c where m
Διαβάστε περισσότεραHomework 3 Solutions
Homework 3 Solutions Igor Yanovsky (Math 151A TA) Problem 1: Compute the absolute error and relative error in approximations of p by p. (Use calculator!) a) p π, p 22/7; b) p π, p 3.141. Solution: For
Διαβάστε περισσότεραIntroduction of Numerical Analysis #03 TAGAMI, Daisuke (IMI, Kyushu University)
Itroductio of Numerical Aalysis #03 TAGAMI, Daisuke (IMI, Kyushu Uiversity) web page of the lecture: http://www2.imi.kyushu-u.ac.jp/~tagami/lec/ Strategy of Numerical Simulatios Pheomea Error modelize
Διαβάστε περισσότεραSecond Order Partial Differential Equations
Chapter 7 Second Order Partial Differential Equations 7.1 Introduction A second order linear PDE in two independent variables (x, y Ω can be written as A(x, y u x + B(x, y u xy + C(x, y u u u + D(x, y
Διαβάστε περισσότερα( ) ( ) ( ) Fourier series. ; m is an integer. r(t) is periodic (T>0), r(t+t) = r(t), t Fundamental period T 0 = smallest T. Fundamental frequency ω
Fourier series e jm when m d when m ; m is an ineger. jm jm jm jm e d e e e jm jm jm jm r( is periodi (>, r(+ r(, Fundamenal period smalles Fundamenal frequeny r ( + r ( is periodi hen M M e j M, e j,
Διαβάστε περισσότεραCHAPTER 101 FOURIER SERIES FOR PERIODIC FUNCTIONS OF PERIOD
CHAPTER FOURIER SERIES FOR PERIODIC FUNCTIONS OF PERIOD EXERCISE 36 Page 66. Determine the Fourier series for the periodic function: f(x), when x +, when x which is periodic outside this rge of period.
Διαβάστε περισσότεραSection 8.3 Trigonometric Equations
99 Section 8. Trigonometric Equations Objective 1: Solve Equations Involving One Trigonometric Function. In this section and the next, we will exple how to solving equations involving trigonometric functions.
Διαβάστε περισσότεραHMY 220: Σήματα και Συστήματα Ι
HMY 0: Σήματα και Συστήματα Ι ΔΙΑΛΕΞΗ #7 Μοντέλα διαφορικών εξισώσεων για ΓΧΑ Συστήματα Επίλυση Διαφορικών Εξισώσεων Η γραμμική διαφορική εξίσωση δεύτερης τάξης Παραδείγματα Μοντέλα διαφορικών εξισώσεων
Διαβάστε περισσότεραThe Euler Equations! λ 1. λ 2. λ 3. ρ ρu. E = e + u 2 /2. E + p ρ. = de /dt. = dh / dt; h = h( T ); c p. / c v. ; γ = c p. p = ( γ 1)ρe. c v.
hp://www.nd.ed/~gryggva/cfd-corse/ The Eler Eqaions The Eler Eqaions The Eler eqaions for D flow: + + p = x E E + p where Define E = e + / H = h + /; h = e + p/ Gréar Tryggvason Spring 3 Ideal Gas: p =
Διαβάστε περισσότεραα ]0,1[ of Trigonometric Fourier Series and its Conjugate
aqartvelo mecierebata erovuli aademii moambe 3 # 9 BULLETIN OF THE GEORGIN NTIONL CDEMY OF SCIENCES vol 3 o 9 Mahemaic Some pproimae Properie o he Cezàro Mea o Order ][ o Trigoomeric Fourier Serie ad i
Διαβάστε περισσότερα3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β
3.4 SUM AND DIFFERENCE FORMULAS Page Theorem cos(αβ cos α cos β -sin α cos(α-β cos α cos β sin α NOTE: cos(αβ cos α cos β cos(α-β cos α -cos β Proof of cos(α-β cos α cos β sin α Let s use a unit circle
Διαβάστε περισσότερα1. Functions and Operators (1.1) (1.2) (1.3) (1.4) (1.5) (1.6) 2. Trigonometric Identities (2.1) (2.2) (2.3) (2.4) (2.5) (2.6) (2.7) (2.8) (2.
ECE 3 Mh le Sprig, 997. Fucio d Operor, (. ic( i( π (. ( β,, π (.3 Im, Re (.4 δ(, ; δ( d, < (.5 u( 5., (.6 rec u( + 5. u( 5., > rc( β /, π + rc( β /,
Διαβάστε περισσότερα6.003: Signals and Systems
6.3: Signals and Sysems Modulaion December 6, 2 Communicaions Sysems Signals are no always well mached o he media hrough which we wish o ransmi hem. signal audio video inerne applicaions elephone, radio,
Διαβάστε περισσότεραDamage Constitutive Model of Mudstone Creep Based on the Theory of Fractional Calculus
Advaces i Peroleum Exploraio ad Developme Vol. 1, No. 2, 215, pp. 83-87 DOI:1.3968/773 ISSN 1925-542X [Pri] ISSN 1925-5438 [Olie] www.cscaada.e www.cscaada.org Damage Cosiuive Model of Mudsoe Creep Based
Διαβάστε περισσότεραSecond Order RLC Filters
ECEN 60 Circuits/Electronics Spring 007-0-07 P. Mathys Second Order RLC Filters RLC Lowpass Filter A passive RLC lowpass filter (LPF) circuit is shown in the following schematic. R L C v O (t) Using phasor
Διαβάστε περισσότερα1 String with massive end-points
1 String with massive end-points Πρόβλημα 5.11:Θεωρείστε μια χορδή μήκους, τάσης T, με δύο σημειακά σωματίδια στα άκρα της, το ένα μάζας m, και το άλλο μάζας m. α) Μελετώντας την κίνηση των άκρων βρείτε
Διαβάστε περισσότεραLecture 12 Modulation and Sampling
EE 2 spring 2-22 Handou #25 Lecure 2 Modulaion and Sampling The Fourier ransform of he produc of wo signals Modulaion of a signal wih a sinusoid Sampling wih an impulse rain The sampling heorem 2 Convoluion
Διαβάστε περισσότεραEN40: Dynamics and Vibrations
EN40: Dyamics a Vibratios School of Egieerig Brow Uiversity Solutios to Differetial Equatios of Motio for Vibratig Systems Here, we summarize the solutios to the most importat ifferetial equatios of motio
Διαβάστε περισσότεραΨηφιακή Επεξεργασία Εικόνας
ΠΑΝΕΠΙΣΤΗΜΙΟ ΙΩΑΝΝΙΝΩΝ ΑΝΟΙΚΤΑ ΑΚΑΔΗΜΑΪΚΑ ΜΑΘΗΜΑΤΑ Ψηφιακή Επεξεργασία Εικόνας Φιλτράρισμα στο πεδίο των συχνοτήτων Διδάσκων : Αναπληρωτής Καθηγητής Νίκου Χριστόφορος Άδειες Χρήσης Το παρόν εκπαιδευτικό
Διαβάστε περισσότεραHomework 8 Model Solution Section
MATH 004 Homework Solution Homework 8 Model Solution Section 14.5 14.6. 14.5. Use the Chain Rule to find dz where z cosx + 4y), x 5t 4, y 1 t. dz dx + dy y sinx + 4y)0t + 4) sinx + 4y) 1t ) 0t + 4t ) sinx
Διαβάστε περισσότεραSolutions to Exercise Sheet 5
Solutions to Eercise Sheet 5 jacques@ucsd.edu. Let X and Y be random variables with joint pdf f(, y) = 3y( + y) where and y. Determine each of the following probabilities. Solutions. a. P (X ). b. P (X
Διαβάστε περισσότεραSolutions: Homework 3
Solutios: Homework 3 Suppose that the radom variables Y,, Y satisfy Y i = βx i + ε i : i,, where x,, x R are fixed values ad ε,, ε Normal0, σ ) with σ R + kow Fid ˆβ = MLEβ) IND Solutio: Observe that Y
Διαβάστε περισσότεραEE101: Resonance in RLC circuits
EE11: Resonance in RLC circuits M. B. Patil mbatil@ee.iitb.ac.in www.ee.iitb.ac.in/~sequel Deartment of Electrical Engineering Indian Institute of Technology Bombay I V R V L V C I = I m = R + jωl + 1/jωC
Διαβάστε περισσότεραarxiv: v1 [math.ap] 5 Apr 2018
Large-ime Behavior ad Far Field Asympoics of Soluios o he Navier-Sokes Equaios Masakazu Yamamoo 1 arxiv:184.1746v1 [mah.ap] 5 Apr 218 Absrac. Asympoic expasios of global soluios o he icompressible Navier-Sokes
Διαβάστε περισσότεραderivation of the Laplacian from rectangular to spherical coordinates
derivation of the Laplacian from rectangular to spherical coordinates swapnizzle 03-03- :5:43 We begin by recognizing the familiar conversion from rectangular to spherical coordinates (note that φ is used
Διαβάστε περισσότεραLifting Entry (continued)
ifting Entry (continued) Basic planar dynamics of motion, again Yet another equilibrium glide Hypersonic phugoid motion Planar state equations MARYAN 1 01 avid. Akin - All rights reserved http://spacecraft.ssl.umd.edu
Διαβάστε περισσότεραb. Use the parametrization from (a) to compute the area of S a as S a ds. Be sure to substitute for ds!
MTH U341 urface Integrals, tokes theorem, the divergence theorem To be turned in Wed., Dec. 1. 1. Let be the sphere of radius a, x 2 + y 2 + z 2 a 2. a. Use spherical coordinates (with ρ a) to parametrize.
Διαβάστε περισσότεραC.S. 430 Assignment 6, Sample Solutions
C.S. 430 Assignment 6, Sample Solutions Paul Liu November 15, 2007 Note that these are sample solutions only; in many cases there were many acceptable answers. 1 Reynolds Problem 10.1 1.1 Normal-order
Διαβάστε περισσότεραGeorge S. A. Shaker ECE477 Understanding Reflections in Media. Reflection in Media
Geoge S. A. Shake C477 Udesadg Reflecos Meda Refleco Meda Ths hadou ages a smplfed appoach o udesad eflecos meda. As a sude C477, you ae o equed o kow hese seps by hea. I s jus o make you udesad how some
Διαβάστε περισσότεραΠεριεχόμενα διάλεξης
5η Διάλεξη Οπτικές ίνες Γ. Έλληνας, Διάλεξη 3, σελ. Περιεχόμενα διάλεξης Ιδιότητες οπτικών ινών Διασπορά (Dispersio) Τρόπων (Iermodal Dispersio) Χρωματική (Iramodal (Chromaic) Dispersio) Πόλωσης (Polarizaio
Διαβάστε περισσότεραPhys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)
Phys460.nb 81 ψ n (t) is still the (same) eigenstate of H But for tdependent H. The answer is NO. 5.5.5. Solution for the tdependent Schrodinger s equation If we assume that at time t 0, the electron starts
Διαβάστε περισσότεραTired Waiting in Queues? Then get in line now to learn more about Queuing!
Tired Waitig i Queues? The get i lie ow to lear more about Queuig! Some Begiig Notatio Let = the umber of objects i the system s = the umber of servers = mea arrival rate (arrivals per uit of time with
Διαβάστε περισσότεραJesse Maassen and Mark Lundstrom Purdue University November 25, 2013
Notes on Average Scattering imes and Hall Factors Jesse Maassen and Mar Lundstrom Purdue University November 5, 13 I. Introduction 1 II. Solution of the BE 1 III. Exercises: Woring out average scattering
Διαβάστε περισσότερα( ) 2 and compare to M.
Problems and Solutions for Section 4.2 4.9 through 4.33) 4.9 Calculate the square root of the matrix 3!0 M!0 8 Hint: Let M / 2 a!b ; calculate M / 2!b c ) 2 and compare to M. Solution: Given: 3!0 M!0 8
Διαβάστε περισσότεραPartial Differential Equations in Biology The boundary element method. March 26, 2013
The boundary element method March 26, 203 Introduction and notation The problem: u = f in D R d u = ϕ in Γ D u n = g on Γ N, where D = Γ D Γ N, Γ D Γ N = (possibly, Γ D = [Neumann problem] or Γ N = [Dirichlet
Διαβάστε περισσότεραSolution Series 9. i=1 x i and i=1 x i.
Lecturer: Prof. Dr. Mete SONER Coordinator: Yilin WANG Solution Series 9 Q1. Let α, β >, the p.d.f. of a beta distribution with parameters α and β is { Γ(α+β) Γ(α)Γ(β) f(x α, β) xα 1 (1 x) β 1 for < x
Διαβάστε περισσότερα6.003: Signals and Systems. Modulation
6.3: Signals and Sysems Modulaion December 6, 2 Subjec Evaluaions Your feedback is imporan o us! Please give feedback o he saff and fuure 6.3 sudens: hp://web.mi.edu/subjecevaluaion Evaluaions are open
Διαβάστε περισσότεραThe Simply Typed Lambda Calculus
Type Inference Instead of writing type annotations, can we use an algorithm to infer what the type annotations should be? That depends on the type system. For simple type systems the answer is yes, and
Διαβάστε περισσότεραFourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics
Fourier Series MATH 211, Calculus II J. Robert Buchanan Department of Mathematics Spring 2018 Introduction Not all functions can be represented by Taylor series. f (k) (c) A Taylor series f (x) = (x c)
Διαβάστε περισσότεραBiorthogonal Wavelets and Filter Banks via PFFS. Multiresolution Analysis (MRA) subspaces V j, and wavelet subspaces W j. f X n f, τ n φ τ n φ.
Chapter 3. Biorthogoal Wavelets ad Filter Baks via PFFS 3.0 PFFS applied to shift-ivariat subspaces Defiitio: X is a shift-ivariat subspace if h X h( ) τ h X. Ex: Multiresolutio Aalysis (MRA) subspaces
Διαβάστε περισσότεραOther Test Constructions: Likelihood Ratio & Bayes Tests
Other Test Constructions: Likelihood Ratio & Bayes Tests Side-Note: So far we have seen a few approaches for creating tests such as Neyman-Pearson Lemma ( most powerful tests of H 0 : θ = θ 0 vs H 1 :
Διαβάστε περισσότερα6.1. Dirac Equation. Hamiltonian. Dirac Eq.
6.1. Dirac Equation Ref: M.Kaku, Quantum Field Theory, Oxford Univ Press (1993) η μν = η μν = diag(1, -1, -1, -1) p 0 = p 0 p = p i = -p i p μ p μ = p 0 p 0 + p i p i = E c 2 - p 2 = (m c) 2 H = c p 2
Διαβάστε περισσότεραOutline. Detection Theory. Background. Background (Cont.)
Outlie etectio heory Chapter7. etermiistic Sigals with Ukow Parameters afiseh S. Mazloum ov. 3th Backgroud Importace of sigal iformatio Ukow amplitude Ukow arrival time Siusoidal detectio Classical liear
Διαβάστε περισσότεραGradient Estimates for a Nonlinear Parabolic Equation with Diffusion on Complete Noncompact Manifolds
Chi. A. Mah. 36B(, 05, 57 66 DOI: 0.007/s40-04-0876- Chiese Aals of Mahemaics, Series B c The Ediorial Office of CAM ad Spriger-Verlag Berli Heidelberg 05 Gradie Esimaes for a Noliear Parabolic Equaio
Διαβάστε περισσότεραEcon 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1
Eon : Fall 8 Suggested Solutions to Problem Set 8 Email questions or omments to Dan Fetter Problem. Let X be a salar with density f(x, θ) (θx + θ) [ x ] with θ. (a) Find the most powerful level α test
Διαβάστε περισσότεραSrednicki Chapter 55
Srednicki Chapter 55 QFT Problems & Solutions A. George August 3, 03 Srednicki 55.. Use equations 55.3-55.0 and A i, A j ] = Π i, Π j ] = 0 (at equal times) to verify equations 55.-55.3. This is our third
Διαβάστε περισσότεραStatistical Inference I Locally most powerful tests
Statistical Inference I Locally most powerful tests Shirsendu Mukherjee Department of Statistics, Asutosh College, Kolkata, India. shirsendu st@yahoo.co.in So far we have treated the testing of one-sided
Διαβάστε περισσότερα( ) ( t) ( 0) ( ) dw w. = = β. Then the solution of (1.1) is easily found to. wt = t+ t. We generalize this to the following nonlinear differential
Periodic oluion of van der Pol differenial equaion. by A. Arimoo Deparmen of Mahemaic Muahi Iniue of Technology Tokyo Japan in Seminar a Kiami Iniue of Technology January 8 9. Inroducion Le u conider a
Διαβάστε περισσότεραMATH 38061/MATH48061/MATH68061: MULTIVARIATE STATISTICS Solutions to Problems on Matrix Algebra
MATH 38061/MATH48061/MATH68061: MULTIVARIATE STATISTICS Solutios to Poblems o Matix Algeba 1 Let A be a squae diagoal matix takig the fom a 11 0 0 0 a 22 0 A 0 0 a pp The ad So, log det A t log A t log
Διαβάστε περισσότερα5.4 The Poisson Distribution.
The worst thing you can do about a situation is nothing. Sr. O Shea Jackson 5.4 The Poisson Distribution. Description of the Poisson Distribution Discrete probability distribution. The random variable
Διαβάστε περισσότεραOn Quasi - f -Power Increasing Sequences
Ieaioal Maheaical Fou Vol 8 203 o 8 377-386 Quasi - f -owe Iceasig Sequeces Maheda Misa G Deae of Maheaics NC College (Auooous) Jaju disha Mahedaisa2007@gailco B adhy Rolad Isiue of echoy Golahaa-76008
Διαβάστε περισσότεραCRASH COURSE IN PRECALCULUS
CRASH COURSE IN PRECALCULUS Shiah-Sen Wang The graphs are prepared by Chien-Lun Lai Based on : Precalculus: Mathematics for Calculus by J. Stuwart, L. Redin & S. Watson, 6th edition, 01, Brooks/Cole Chapter
Διαβάστε περισσότεραForced Pendulum Numerical approach
Numerical approach UiO April 8, 2014 Physical problem and equation We have a pendulum of length l, with mass m. The pendulum is subject to gravitation as well as both a forcing and linear resistance force.
Διαβάστε περισσότεραTrigonometric Formula Sheet
Trigonometric Formula Sheet Definition of the Trig Functions Right Triangle Definition Assume that: 0 < θ < or 0 < θ < 90 Unit Circle Definition Assume θ can be any angle. y x, y hypotenuse opposite θ
Διαβάστε περισσότεραANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?
Teko Classes IITJEE/AIEEE Maths by SUHAAG SIR, Bhopal, Ph (0755) 3 00 000 www.tekoclasses.com ANSWERSHEET (TOPIC DIFFERENTIAL CALCULUS) COLLECTION # Question Type A.Single Correct Type Q. (A) Sol least
Διαβάστε περισσότεραProblem Set 9 Solutions. θ + 1. θ 2 + cotθ ( ) sinθ e iφ is an eigenfunction of the ˆ L 2 operator. / θ 2. φ 2. sin 2 θ φ 2. ( ) = e iφ. = e iφ cosθ.
Chemistry 362 Dr Jean M Standard Problem Set 9 Solutions The ˆ L 2 operator is defined as Verify that the angular wavefunction Y θ,φ) Also verify that the eigenvalue is given by 2! 2 & L ˆ 2! 2 2 θ 2 +
Διαβάστε περισσότεραSpherical shell model
Nilsso Model Spherical Shell Model Deformed Shell Model Aisotropic Harmoic Oscillator Nilsso Model o Nilsso Hamiltoia o Choice of Basis o Matrix Elemets ad Diagoaliatio o Examples. Nilsso diagrams Spherical
Διαβάστε περισσότερα