ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS)

Μέγεθος: px
Εμφάνιση ξεκινά από τη σελίδα:

Download "ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS)"

Transcript

1 ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) Δρ. Χριστόφορος Χριστοφόρου Πανεπιστήμιο Κύπρου - Τμήμα Πληροφορικής Modulation Techniques (Τεχνικές Διαμόρφωσης)

2 Recall (Process and Elements of Radio Transmission) 1 Modulation Demodulation

3 Topics Discussed 2 Digital Modulation Bit rate, Baud rate Basic Digital Modulation Techniques (ASK, FSK, PSK, QAM) Constellation diagrams Factors that influence the choice of Digital Modulation Scheme Power Efficiency, Bandwidth Efficiency

4 Modulated Signals Modulation 3 Message Signal (Data to be transmitted) Carrier signal with frequency f c Controlling the Amplitude of the carrier signal (ASK) Controlling the Frequency of the carrier signal (FSK) Controlling the Phase of the carrier signal (PSK)

5 Analog and Digital Signals Αναλογικά και Ψηφιακά Σήματα 4 Means by which data are propagated over a medium (Οι τρόποι με τους οποίους τα δεδομένα διαδίδονται μέσω κάποιου μέσου). An Analog Signal is a continuously varying electromagnetic wave (ένα συνεχόμενο εναλλασσόμενο ηλεκτρομαγνητικό κύμα) that may be propagated over a variety of media: Wire, fiber optic, coaxial, space (wireless) A digital signal is a sequence of discrete voltage pulses (είναι μια αλληλουχία διακριτών παλμών τάσης) that can be transmitted over a wire medium: E.g., a constant positive level of voltage to represent bit 1 and a constant negative level to represent bit 0.

6 Modulation for Wireless Digital Modulation 5 Digital modulation is the process by which an analog carrier wave is modulated to include a discrete (digital) signal. (Ψηφιακή διαμόρφωση είναι η διαδικασία κατά την οποία ένας μεταφορέας αναλογικού σήματος διαμορφώνεται έτσι ώστε να συμπεριλάβει ένα διακριτό (ψηφιακό) σήμα (π.χ., 1 or 0)) Digital modulation methods can be considered as Digital-to- Analog conversion, and the corresponding Demodulation (e.g., at the Receiver) as Analog-to-Digital conversion.

7 Modulation for Wireless Digital Modulation 6 The modulation that will be applied on the (analog) carrier signal to include the data that will be carried (e.g., 1 or 0, etc.) are chosen from a finite number of M alternative symbols (or signal units or signal elements) based on the Digital Modulation Technique and the Modulation Alphabet that will be used. (Η διαμόρφωση που θα γίνει στον (αναλογικό) μεταφορέα σήματος για να συμπεριλάβουν την πληροφορία που θα μεταφερθεί (π.χ., 1 ή 0) επιλέγονται από ένα πεπερασμένο αριθμό από εναλλακτικά σύμβολα (σήματα) ανάλογα με την Τεχνική διαμόρφωσης και το Αλφάβητο Διαμόρφωσης που θα χρησιμοποιηθεί. Symbol Pattern 1 0 Symbol Pattern 2 1 This same Modulation Alphabet have to be used both from the Transmitter (for modulating the signal) and the Receiver (for demodulating the signal)

8 Modulation for Wireless Digital Modulation 7 The general form (pattern) of the modulated signal is (Η γενική μορφή ενός διαμορφωμένου σήματος): s(t) = A(t) sin(2π x (f c + f m (t)) t + (t)

9 Modulation for Wireless Digital Modulation 8 The three essential parameters that can be modulated (Οι τρείς βασικές παράμετροι που μπορούμε να διαμορφώσουμε) s(t ) = A sin(2π f t + ) Amplitude value (A) ASK (Amplitude Shift Keying) Frequency value (f) FSK (Frequency Shift Keying) Phase value (φ) PSK (Phase Shift Keying) Digital modulation: Amplitude (A), frequency (f) and Phase () are used to represent a digital state. (Στην Ψηφιακή διαμόρφωση το πλάτος, η συχνότητα, και η φάση του σήματος χρησιμοποιούνται για να αναπαραστήσουν μία ψηφιακή κατάσταση ή τιμή)

10 Basic Digital Modulation Techniques 9 Basic Digital Modulation Techniques work by varying the Amplitude, Frequency or Phase (or a combination of them) of a sinusoidal carrier wave depending on the information (data) that will be transmitted and the Modulation Alphabet that will be used. ASK: Amplitude Shift Keying s(t ) = A sin(2π f t + ) FSK: Frequency Shift Keying s(t ) = A sin(2π f t + ) PSK: Phase Shift Keying s(t ) = A sin(2π f t + ) Quadrature Amplitude Modulation (QAM) or Amplitude Phase Shift Keying (APSK) s(t ) = A sin(2π f t + )

11 Basic Digital Modulation Techniques 10 Types of Digital to Analog Modulation

12 Basic Digital Modulation Techniques Illustration 11 A(t).sin[2.π.f c.t] sin[2.π.(f c +f m (t)).t] sin[2.π.f c.t + θ(t)] A(t).sin[2.π.f c.t + θ(t)]

13 Bit Rate and Baud Rate 12 Bit Rate is the number of bits (data) that can be carried per second. Baud Rate is the number of signal units (or symbols) per second used for carrying the bits (and achieve the Bit Rate). Baud Rate can be less than or equal to the bit rate Note that each symbol can carry one or more bits! Baud Rate is important in Bandwidth efficiency. Baud rate determines the bandwidth required to send the message signal (Καθορίζει το εύρος ζώνης που απαιτείται για να σταλεί μήνυμα) Baud Rate = Bit Rate / Number of Βits per Symbol Thus, the lower the Baud Rate the less the bandwidth required The number of bits that can be carried by one Symbol, depends on the Modulation Technique used. The Baud Rate depends on the type of Modulation used.

14 Bit Rate and Baud Rate Examples 13 Example 1: A modulated signal carries 4 bits in each signal unit. If 1000 signal units are sent per second, find the Baud Rate and the Bit Rate Baud Rate = 1000 baud/s Bit Rate = 1000 x 4 = 4000 bps Example 2: The bit rate of a modulated signal is 3000 bps. If each signal unit carries 6 bits, what is the baud rate? Baud Rate = 3000/6 = 500 (baud/s) Example 3: A modulated signal has a bit rate of 8000 bps and a baud rate of 1000 baud. How many bits are carried by each signal element? Bits/Baud = 8000/1000 = 8

15 Amplitude Shift Keying (ASK) 14 s(t) = The strength of the carrier signal (Amplitude) is varied to represent digital data (1 and 0) - Binary ASK. Frequency and Phase remains the same while the amplitude changes. A 1 sin(2π f t + ) 1 A 2 sin(2π f t + ) 0 One bit per symbol! Baud Rate = Bit Rate Carrier Modulated Signal Two states used

16 Amplitude Shift Keying (ASK) 15 ASK is susceptible to noise and interference (ευάλωτο στο θόρυβο) as noise can change the amplitude of a signal. This can cause errors on the Receiver during demodulation. Noise refers to unintentional voltages introduced onto a line by various phenomena such as heat or electromagnetic induction created by other sources. s(t) = On/Off Keying A sin(2π f t + ) 1 0 0

17 Amplitude Shift Keying (ASK) M-ary ASK 16 Binary ASK has only two possible states representing only 0 and 1 M-ary ASK has more than 2 possible states. For example, if M = 4, the ASK refers to four different Amplitudes in which the carrier is send. As 4 states are possible, two bits can be encoded per symbol. In general if number of possible states M > 2, each symbol can carry log2(m) bits. This scheme is therefore more bandwidth efficient. Modulation Alphabet with 4 possible states s(t) = A 1 sin(2π f t + φ) A 2 sin(2π f t + φ) A 3 sin(2π f t + φ) A 4 sin(2π f t + φ) A 1 = 0 : 00 A 2 = 1: 01 A 3 = 2: 10 A 4 = 3: 11 Example: M = 4 (4 different states) log 2 (4) = 2 2 bits/symbol Baud Rate= N, Bid Rate= 2N

18 Frequency Shift Keying (FSK) 17 The frequency of the carrier signal (f c ) is varied to represent digital data (1 and 0) - Binary FSK (2 frequencies: f 1 and f 2 ) Both peak amplitude and phase remain constant. In this case the carrier switches between 2 values (two states; M = 2): A sin(2π (f 1 ) t + ) 0 s(t) = A sin(2π (f 2 ) t + ) 1 Baud Rate = Bit Rate

19 Frequency Shift Keying (FSK) 18 Binary FSK has only two possible states representing only 0 and 1 M-ary FSK has more than 2 possible states. For example, if M = 4, the FSK refers to four different frequencies in which the carrier is modulated and send. As 4 states are possible, two bits can be encoded per symbol. Baud Rate = Bit Rate/2 Reduces the Required Bandwidth to half Modulation Alphabet s(t) = A sin(2π (f 1 ) t + φ) 00 A sin(2π (f 2 ) t + φ) 01 A sin(2π (f 3 ) t + φ) 10 A sin(2π (f 4 ) t + φ) 11

20 Frequency Shift Keying (FSK) 19 FSK is not susceptible to noise interference as it avoids noise interference by looking at frequencies (change of a signal) and ignoring amplitudes. Because the Receiving device is looking for specific frequency changes over a given number of periods, it can ignore voltage spikes. (Ο Receiver κοιτάζει μόνο για συγκεκριμένες αλλαγές στη συχνότητα του μεταφορέα σήματος σε συγκεκριμένες περιόδους (περίοδος ενός signal unit)) και αγνοεί αλλαγές στην τάση (πλάτος) του σήματος.)

21 Phase Shift Keying (PSK) 20 The phase of the carrier signal is varied to represent digital data (binary 0 or 1), i.e., Binary PSK (BPSK) Both peak amplitude and frequency remain constant as the phase changes. Phases are separated by 180 degrees. If we start with a phase of 0 o to represent bit 0, then we can change the phase to 180 o to send bit 1 (or inversely). The Constellation or phase-state Diagram shows the relationship by illustrating only the phases. Baud Rate = Bit Rate s(t) = A sin(2π f t + 0 o ) 0 A sin(2π f t o ) 1

22 Phase Shift Keying (PSK) Phase Shifts Examples 21 Phase Shifts Example

23 Phase Shift Keying (PSK) 22 PSK is not susceptible to noise degradation that affects ASK, neither has the limitation of FSK that needs to repeatedly tune at different frequencies (i.e., no need for filtering the signal of different frequencies simpler demodulator needed). Simple to implement, and is used extensively in wireless communication.

24 Quadrature Phase Shift Keying (QPSK) 23 QPSK refers to PSK with 4 states. The Q - Quadrature in QPSK refers to four phases in which a carrier is modulated and send in QPSK. Also, called 4-PSK. Because QPSK has 4 possible states, QPSK can encode two bits per symbol. Because 2 bits are allocated to each symbol, QPSK can achieve twice the Data Rate of a comparable BPSK scheme for a given bandwidth.

25 Quadrature Phase Shift Keying (QPSK) 24 Two Modulation Alphabets s(t) = A sin(2π f t + φ 1 ) A sin(2π f t + φ 2 ) A sin(2π f t + φ 3 ) A sin(2π f t + φ 4 ) φ 1 = 0 ο φ 2 = 90 ο φ 3 = 180 ο φ 4 = 270 ο OR φ 1 = 45 ο 00 φ 2 = 135 ο 01 φ 3 = 225 ο 10 φ 4 = 315 ο 11

26 Constellation Diagrams Διαγράμματα Αστερισμού 25 It is a convenient way to represent the symbols (define the amplitude and phase) of the Modulation Alphabet that will be used for modulating signal carrier and transmitting the signal. (Είναι ένας εύκολος τρόπος για να αναπαραστήσουμε τα σύμβολα του Αλφαβήτου Διαμόρφωσης που θα χρησιμοποιηθούν για τη διαμόρφωση του μεταφορέα σήματος για την αποστολή του σήματος) Examples:

27 Constellation Diagrams Circular Constellation Diagrams 26 Examples: (a) Circular 4-QAM (b) Circular 8-QAM (c) Circular 16-QAM

28 Constellation Diagrams Rectangular Constellation Diagrams 27 Examples: I Rectangular 4-QAM Rectangular 8-QAM Rectangular 16-QAM: 1000

29 Higher Order Modulation: 8-PSK 28 s(t) = We can extend the Modulation Alphabet, by varying the signal by shifts of 45 ο (instead of 90 ο in QPSK). (Μπορούμε να επεκτείνουμε το Αλφάβητο Διαμόρφωσης με το μεταβάλλουμε το σήμα με μετατοπίσεις 45 ο παρά 90 o όπως το QPSK) With 8 (2 3 ) different phases, each phase (i.e., signal unit or symbol) can represent 3 bits. Baud Rate = Bit Rate/3 Reduces the Required Bandwidth to one third A sin(2π f t + φ 1 ) 000 φ 1 = 0 ο A sin(2π f t + φ 2 ) 001 φ 2 = 45 ο A sin(2π f t + φ 3 ) 010 φ 3 = 90 ο A sin(2π f t + φ 4 ) 011 φ 4 = 135 ο A sin(2π f t + φ 5 ) 100 A sin(2π f t + φ 6 ) 101 A sin(2π f t + φ 7 ) 110 A sin(2π f t + φ 8 ) 111 φ 5 = 180 ο φ 6 = 225 ο φ 7 = 270 ο φ 8 = 315 ο Using the Constellation Diagram we can easily produce the Modulation Alphabet

30 Higher Order Modulation: M-PSK 29 Obviously the bandwidth efficiency of a M-ary PSK scheme increases as M (the number of possible states) increases because more bits per symbol can be sent...however the distance between 2 points in the constellation is reduced and therefore the possibility for decoding the symbol incorrectly at the receiver increases I BPSK QPSK 8-PSK 16-PSK As M increases, the bandwidth efficiency increases but the waveform energy (i.e., the transmission power used to send the symbol) must be increased to keep the BER at a certain level

31 Quadrature Amplitude Modulation (QAM) Phase and Amplitude Modulation 30 PSK is limited by the ability of the equipment to distinguish between small differences in phases. Limits the potential data rate. (Περιορίζει το πιθανό data rate) The principle of Quadrature Amplitude Modulation (QAM) of Amplitude Phase Shift Keying (APSK) is to have X possible variations in Phase (X πιθανές διαφορετικές φάσεις) and Y possible variations of Amplitude (Υ πιθανά διαφορετικά πλάτη). X Y possible variations More different states that the carrier signal can be modulated, therefore more bits can be carried per symbol therefore greater Data Rates and Throughput. QAM (or APSK) is an application of ASK to PSK (Εφαρμογή του ASK πάνω στο PSK)

32 Quadrature Amplitude Modulation (QAM) Phase and Amplitude Modulation 31 Example: 8-QAM example Two (2) possible different Amplitudes (A1 = 1; A2 = 2) Four (4) possible different Phases (0 o, 90 o, 180 o, 270 o ) Total of 8 QAM symbols 3 bits per symbol Baud Rate = Bit Rate/3 Modulation Alphabet A = 1, Phase = 0 o : 000 A = 2, Phase = 0 o : 001 A = 1, Phase = 90 o : 010 A = 2, Phase = 90 o : 011 A = 1, Phase = 180 o : 100 A = 2, Phase = 180 o : 101 A = 1, Phase = 270 o : 110 A = 2, Phase = 270 o : 111

33 Quadrature Amplitude Modulation (QAM) of APSK 32 We can have numerous possible variations (Διάφορες πιθανές παραλλαγές) of Phase Shifts and Amplitude shifts However the Number of Phase Shifts should selected to be GREATER than Number of Amplitude shifts. (Why??) 16-QAM for example: There are sixteen QAM symbols 4 bits per symbol. A variety of constellations diagrams can be used

34 Quadrature Amplitude Modulation (QAM) 33 More higher order modulation 64-QAM (64-Quadrature Amplitude Modulation) Each symbol now carries 6 bits (i.e., log 2 (64)) Going higher: 256-QAM 8bits/symbol (log 2 (256)) 1024-QAM 10bits/symbol (log 2 (1024)).

35 Why Not Just Keep Going? 34 With Higher Order Modulation schemes Minor errors during modulation could create symbol errors in transmission Even a little noise in the transmission channel could create symbol errors Minor inaccuracies in the Receiver could create errors Signal-to-Noise requirements increases with higher order modulations (thus more power have to be used during transmission more interference caused in the cells)

36 Multipath Propagation Effect on Signal Demodulation at the Receiver 35 In the example illustrated below, we assume that the Receiver receives two copies of each signal, from two different paths (Direct Path, Reflected) each path having a different length --> Each signal copy will arrive to the Receiver in different times (delays) and with different amplitudes. Signal 1 Signal 2 Signal 3 Effect of Multipath Propagation

37 Multipath Propagation Effect on Signal Demodulation at the Receiver 36 The addition of the delayed contribution via the Reflected path has two consequences: The symbols have been extended and now have a tail due to the reflected contribution continuing to arrive for a short period after the direct symbol has ended. The Received Result has its effective Amplitude and Phase altered by an amount that depends on the time difference between the paths. If higher order modulation schemes are applied, even a minor alteration on the amplitude or phase of the signal will cause wrong signal interpretation at the Receiver Propagation Delay: Length of the path that the signal follows to reach the receiver (Z), divided by the Speed of Light (C)

38 Bid and Baud Rate Comparison 37 Assuming a Binary-FSK signal can send 1200 bps, it requires 1200 signal units (symbols) to send 1200 bits (each symbol represents one bit, Baud Rate = 1200 bauds/s) Assuming an 8-QAM (3 bits per symbol), using the same baud rate (1200 bauds/s), 3600 bits/s will be achieved (3 x Bit Rate).

39 Bid and Baud Rate Comparison Examples 38 A constellation diagram consists of eight equally spaced points on a circle. If the bit rate is 4800 bps, what is the baud rate? The constellation indicates an 8-PSK with the points 45 degrees apart. Since 2 3 = 8 (N = log 2 (8) N = 3) then 3 bits are transmitted with each signal unit (symbol). Therefore, the baud rate is 4800 / 3 = 1600 baud/s. What is the bit rate for a 1000 baud/s 16-QAM signal? A 16-QAM signal has 4 bits per signal unit (symbol) since log 2 16 = 4. Thus, (1000 x 4) = 4000 bps Compute the baud rate for a 72,000bps 64-QAM signal. A 64-QAM signal has 6 bits per signal unit (log 2 64 = 6). Therefore 72,000 / 6 = 12,000 baud/s

40 Factors that influence the choice of Digital Modulation Scheme 39 Some Performance factors considered (depending on the environment): Achieve Low Bit Error Rate (BER) at low SNR or SINR (Να επιτυγχάνει χαμηλό ποσοστό σφάλματος δεδομένων με χαμηλή ενέργεια σήματος) Efficient use of battery power in Mobile Device (Να κάνει αποδοτική χρήση της μπαταρίας στις κινητές συσκευές) Resistance to Interference and Noise (Ανοχή στις παρεμβολές και το θόρυβο)

41 Factors that influence the choice of Digital Modulation Scheme 40 Occupying a minimum amount of Bandwidth to send the data (Να δεσμεύει όσο το δυνατό πιο λίγο εύρος ζώνης για να στείλει τα δεδομένα) Easy and cheap to implement in a Mobile Device (Η τεχνική να είναι φτηνή και εύκολη να υλοποιηθεί στις κινητές συσκευές) No existing modulation scheme simultaneously satisfies all of these requirements well. Each one is better in some areas with tradeoffs of being worse in others.

42 Factors that influence the choice of Digital Modulation Scheme 41 The performance of a modulation scheme is often measured in terms of its: Power Efficiency: Refers to the ability to preserve the fidelity (no errors) of a digital message at low power levels (i.e., low SNIR) (Περιγράφει την ικανότητα διατήρησης της ακεραιότητα ενός μηνύματος (no errors) σε χαμηλά επίπεδα ισχύος του σήματος) Bandwidth (or Link Spectral) Efficiency: Refers to ability to squeeze as much data into the least amount of bandwidth available (Περιγράφει την ικανότητα συμπίεσης όσον περισσότερων δεδομένων στο ελάχιστο διαθέσιμο εύρος ζώνης)

43 Factors that influence the choice of Digital Modulation Scheme 42 Power Efficiency: In order to increase noise immunity, it is necessary to increase the signal power. (Για να αυξήσουμε την ανοσία ενός σήματος στο θόρυβο πρέπει να αυξήσουνε την ενέργεια (ισχύ) με την οποία θα το στείλουμε) The amount by which the signal power should be increased to maintain a certain BER depends on the modulation scheme. Higher Order Modulation Higher Signal Power. The Power Efficiency is expressed by the value of SNIR required at the Receiver to decode the signal correctly and guarantee a certain BER (The lower the SNIR required the higher the Power Efficiency).

44 Factors that influence the choice of Digital Modulation Scheme 43 Bandwidth (Link Spectral) Efficiency: Is typically used to analyse how efficiently the allocated bandwidth is used by the modulation technique (Χρησιμοποιείται για να αναλύσουμε πόσο αποδοτικά χρησιμοποιείται το διαθέσιμο εύρος ζώνης από την τεχνική διαμόρφωσης). It is defined as the average number of bits per unit of time (bits per second) that can be transmitted per unit of bandwidth (per Hertz).

45 Factors that influence the choice of Digital Modulation Scheme 44 Bandwidth (Link Spectral) Efficiency: Is the net data rate (useful information rate excluding error-correcting codes) or maximum throughput* divided by the available Bandwidth (in hertz) of a communication channel. It is measured in bits per second per Herz (bps/hz) * Throughput or network throughput is the rate of successful message delivery over a communication channel. A typical method of performing a measurement is to transfer a 'large' file from one system to another system and measure the time required to complete the transfer or copy of the file. The throughput is then calculated by dividing the file size by the time required to complete the transfer. Then the throughput can be measured in megabits, kilobits, or bits per second.

46 Factors that influence the choice of Digital Modulation Scheme 45 Bandwidth Efficiency Examples: Example 1: What is the bandwidth efficiency of the modulation technique when 2 Kilohertz of bandwidth is required to transmit 1000 bps? 1000bps/2000Hz = 0.5 bps/hz Example 2: What is the bandwidth efficiency of the modulation technique when 3 Kilohertz of bandwidth is required to transmit bps? 12000bps/3000Hz = 4bps/Hz

47 Factors that influence the choice of Digital Modulation Scheme 46 Very often there is a tradeoff: M-ary schemes increase the Bandwidth Efficiency but require Higher Transmission Power (than Binary modulation schemes) to keep the same Bit Error Rate Lower Power Efficiency. (Κάνουν την χρήση του εύρους ζώνης πιο αποδοτική άλλα χρειάζεται περισσότερη ισχύς κατά την αποστολή των δεδομένων για να είναι το σήμα πιο δυνατό και να μπορεί ο Receiver να το αναγνωρίσει και να το αποκωδικοποιήσει σωστά διατηρώντας έτσι το BER στα επίπεδα που πρέπει)

48 Factors that influence the choice of Digital Modulation Scheme 47 Very often there is a tradeoff: Power Efficiency can be increased by adding Error Control Coding in the packets transmitted but reduces the Bandwidth Efficiency as Redundancy is transmitted too. (Μπορούμε να αυξήσουμε το Power Efficiency με το να προσθέσουμε error control codes κατά την αποστολή των πακέτων αλλά αυτό μειώνει το Bandwidth Efficiency αφού στέλλουμε επιπλέον (μη χρήσιμη) πληροφορία) Error control (error detection and correction) are techniques that enable reliable delivery of digital data over unreliable communication channels. Many communication channels are subject to channel noise, and thus errors may be introduced during transmission from the source to a receiver. Error detection techniques allow detecting such errors, while error correction enables reconstruction of the original data in many cases.

49 48 Ερωτήσεις;

50 49 Additional Slides

51 Modulation 50 Modulation is the process of encoding information (the data that we want to transmit) from a message source in a manner suitable for transmission through a medium (i.e., the air) (Είναι η διαδικασία κωδικοποίησης της πληροφορίας (του πηγαίου μηνύματος) που θέλουμε να στείλουμε, σε μια μορφή η οποία είναι κατάλληλη για μετάδοση μέσω κάποιου μέσου (π.χ., στον αέρα)) Modulation is used to modify the parameters of a high frequency carrier signal (i.e., Amplitude, Frequency, Phase), so as to include a message signal (which contains the information) onto the carrier (i.e., the channel).

52 Why Modulate? 51 Ease of radiation (Ευκολία εκπομπής) Reduce antenna size: The size of an antenna is proportional to the signal wavelength. By modulating the baseband signal (i.e., the message) into higher frequency carrier, the wavelength decreases, and thus the size of the antenna decreases. The size of antenna λ/4 = c/4f. E.g.: 3 khz 25 Km antenna 3 GHz 2.5 cm antenna

53 Why Modulate? 52 Allows the message data to be encoded into a form (i.e., into a Carrier signal with higher frequencies) suitable for Traveling Long Distances over the air: E.g., If we wish to throw a piece of paper, it cannot go too far by itself. But by wrapping it around a stone (carrier signal), it can be thrown over a longer distance!

54 Why Modulate? 53 Bandwidth Efficiency (Αποδοτική χρήση του διαθέσιμου εύρου ζώνης) By modulation we can use a narrow bandwidth (χρήση μικρού εύρος ζώνης) to send a large amount of data Higher order modulation schemes (8-PSK: 3 bits/symbol, 16-QAM: 4 bits/symbol, 64-QAM: 5 bits/symbol) can be used depending on the environmental conditions. Effective use (Αποτελεσματική χρήση) of limited frequency resources A carrier alone conveys no information A carrier signal by itself is like a train wagon without letters Modulation makes the signal carrier usefull. Includes the information that will be transmitted.

55 Why Modulate? 54 Allows simultaneous transmission of several signals (Multiplexing; Πολυπλεξία Πολλοί χρήστες μπορούν να στείλουν τα δεδομένα τους την ίδια ώρα χωρίς να προκαλούνται παρεμβολές) By modulating different signals into different carriers (with different frequencies) several users can transmit their signals at the same time (avoid interference). The Received parties will just tune (συντονίζονται) to the correct Frequency Carrier to receive the signal. Good Security features (Ασφάλεια δεδομένων) Greater security (encryption - κρυπτογράφηση) on the data can be applied during modulation..

56 Multipath Propagation Effect on Signal Demodulation at the Receiver 55 The two paths are of lengths we can call Z (direct) and Z (indirect). This allows us to define the time delay (dt) between their relative arrivals to be dt = (Z Z)/C C is the speed of light The above shows why it is useful to have a Guard Interval (T G ), in between the Useful Symbol Periods (T s ). For this case, if we arrange for T G > dt then the delayed version of each symbol will have finished arriving before the next symbol in the sequence starts to arrive. This prevents the pattern transmitted for a given symbol from affecting what we see during the next symbol period. ISI makes it harder for the receiver to demodulate the symbols correctly. The larger the T G The lower the possibility for ISI The less the number of symbols that can be transmitted per second The lower the data rates achieved.

ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS)

ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) Δρ. Χριστόφορος Χριστοφόρου Πανεπιστήμιο Κύπρου - Τμήμα Πληροφορικής Modulation Techniques (Τεχνικές Διαμόρφωσης) Recall (Process and Elements of Radio

Διαβάστε περισσότερα

Information Theory Θεωρία της Πληροφορίας. Vasos Vassiliou

Information Theory Θεωρία της Πληροφορίας. Vasos Vassiliou Information Theory Θεωρία της Πληροφορίας Vasos Vassiliou Network/Link Design Factors Transmission media Signals are transmitted over transmission media Examples: telephone cables, fiber optics, twisted

Διαβάστε περισσότερα

Main source: "Discrete-time systems and computer control" by Α. ΣΚΟΔΡΑΣ ΨΗΦΙΑΚΟΣ ΕΛΕΓΧΟΣ ΔΙΑΛΕΞΗ 4 ΔΙΑΦΑΝΕΙΑ 1

Main source: Discrete-time systems and computer control by Α. ΣΚΟΔΡΑΣ ΨΗΦΙΑΚΟΣ ΕΛΕΓΧΟΣ ΔΙΑΛΕΞΗ 4 ΔΙΑΦΑΝΕΙΑ 1 Main source: "Discrete-time systems and computer control" by Α. ΣΚΟΔΡΑΣ ΨΗΦΙΑΚΟΣ ΕΛΕΓΧΟΣ ΔΙΑΛΕΞΗ 4 ΔΙΑΦΑΝΕΙΑ 1 A Brief History of Sampling Research 1915 - Edmund Taylor Whittaker (1873-1956) devised a

Διαβάστε περισσότερα

ΜΕΛΕΤΗ ΚΑΙ ΠΡΟΣΟΜΟΙΩΣΗ ΙΑΜΟΡΦΩΣΕΩΝ ΣΕ ΨΗΦΙΑΚΑ ΣΥΣΤΗΜΑΤΑ ΕΠΙΚΟΙΝΩΝΙΩΝ.

ΜΕΛΕΤΗ ΚΑΙ ΠΡΟΣΟΜΟΙΩΣΗ ΙΑΜΟΡΦΩΣΕΩΝ ΣΕ ΨΗΦΙΑΚΑ ΣΥΣΤΗΜΑΤΑ ΕΠΙΚΟΙΝΩΝΙΩΝ. Τµήµα Ηλεκτρονικής ΜΕΛΕΤΗ ΚΑΙ ΠΡΟΣΟΜΟΙΩΣΗ ΙΑΜΟΡΦΩΣΕΩΝ ΣΕ ΨΗΦΙΑΚΑ ΣΥΣΤΗΜΑΤΑ ΕΠΙΚΟΙΝΩΝΙΩΝ. Σπουδαστής: Γαρεφαλάκης Ιωσήφ Α.Μ. 3501 Επιβλέπων καθηγητής : Ασκορδαλάκης Παντελής. -Χανιά 2010- ΠΕΡΙΛΗΨΗ : Η παρούσα

Διαβάστε περισσότερα

[1] P Q. Fig. 3.1

[1] P Q. Fig. 3.1 1 (a) Define resistance....... [1] (b) The smallest conductor within a computer processing chip can be represented as a rectangular block that is one atom high, four atoms wide and twenty atoms long. One

Διαβάστε περισσότερα

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:

HOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch: HOMEWORK 4 Problem a For the fast loading case, we want to derive the relationship between P zz and λ z. We know that the nominal stress is expressed as: P zz = ψ λ z where λ z = λ λ z. Therefore, applying

Διαβάστε περισσότερα

Elements of Information Theory

Elements of Information Theory Elements of Information Theory Model of Digital Communications System A Logarithmic Measure for Information Mutual Information Units of Information Self-Information News... Example Information Measure

Διαβάστε περισσότερα

6.003: Signals and Systems. Modulation

6.003: Signals and Systems. Modulation 6.003: Signals and Systems Modulation May 6, 200 Communications Systems Signals are not always well matched to the media through which we wish to transmit them. signal audio video internet applications

Διαβάστε περισσότερα

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS

CHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS CHAPTER 5 SOLVING EQUATIONS BY ITERATIVE METHODS EXERCISE 104 Page 8 1. Find the positive root of the equation x + 3x 5 = 0, correct to 3 significant figures, using the method of bisection. Let f(x) =

Διαβάστε περισσότερα

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)

Phys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required) Phys460.nb 81 ψ n (t) is still the (same) eigenstate of H But for tdependent H. The answer is NO. 5.5.5. Solution for the tdependent Schrodinger s equation If we assume that at time t 0, the electron starts

Διαβάστε περισσότερα

2 Composition. Invertible Mappings

2 Composition. Invertible Mappings Arkansas Tech University MATH 4033: Elementary Modern Algebra Dr. Marcel B. Finan Composition. Invertible Mappings In this section we discuss two procedures for creating new mappings from old ones, namely,

Διαβάστε περισσότερα

Instruction Execution Times

Instruction Execution Times 1 C Execution Times InThisAppendix... Introduction DL330 Execution Times DL330P Execution Times DL340 Execution Times C-2 Execution Times Introduction Data Registers This appendix contains several tables

Διαβάστε περισσότερα

Capacitors - Capacitance, Charge and Potential Difference

Capacitors - Capacitance, Charge and Potential Difference Capacitors - Capacitance, Charge and Potential Difference Capacitors store electric charge. This ability to store electric charge is known as capacitance. A simple capacitor consists of 2 parallel metal

Διαβάστε περισσότερα

the total number of electrons passing through the lamp.

the total number of electrons passing through the lamp. 1. A 12 V 36 W lamp is lit to normal brightness using a 12 V car battery of negligible internal resistance. The lamp is switched on for one hour (3600 s). For the time of 1 hour, calculate (i) the energy

Διαβάστε περισσότερα

Δίκτυα Καθοριζόμενα από Λογισμικό

Δίκτυα Καθοριζόμενα από Λογισμικό ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ Δίκτυα Καθοριζόμενα από Λογισμικό Exercise Session 4: Familiarization with GNU Radio Τμήμα Επιστήμης Υπολογιστών SDR Assignment using GNU Radio Manolis Surligas

Διαβάστε περισσότερα

Section 8.3 Trigonometric Equations

Section 8.3 Trigonometric Equations 99 Section 8. Trigonometric Equations Objective 1: Solve Equations Involving One Trigonometric Function. In this section and the next, we will exple how to solving equations involving trigonometric functions.

Διαβάστε περισσότερα

EE512: Error Control Coding

EE512: Error Control Coding EE512: Error Control Coding Solution for Assignment on Finite Fields February 16, 2007 1. (a) Addition and Multiplication tables for GF (5) and GF (7) are shown in Tables 1 and 2. + 0 1 2 3 4 0 0 1 2 3

Διαβάστε περισσότερα

Calculating the propagation delay of coaxial cable

Calculating the propagation delay of coaxial cable Your source for quality GNSS Networking Solutions and Design Services! Page 1 of 5 Calculating the propagation delay of coaxial cable The delay of a cable or velocity factor is determined by the dielectric

Διαβάστε περισσότερα

(1) Describe the process by which mercury atoms become excited in a fluorescent tube (3)

(1) Describe the process by which mercury atoms become excited in a fluorescent tube (3) Q1. (a) A fluorescent tube is filled with mercury vapour at low pressure. In order to emit electromagnetic radiation the mercury atoms must first be excited. (i) What is meant by an excited atom? (1) (ii)

Διαβάστε περισσότερα

BandPass (4A) Young Won Lim 1/11/14

BandPass (4A) Young Won Lim 1/11/14 BandPass (4A) Copyright (c) 22 Young W. Lim. Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version.2 or any later version

Διαβάστε περισσότερα

Homework 3 Solutions

Homework 3 Solutions Homework 3 Solutions Igor Yanovsky (Math 151A TA) Problem 1: Compute the absolute error and relative error in approximations of p by p. (Use calculator!) a) p π, p 22/7; b) p π, p 3.141. Solution: For

Διαβάστε περισσότερα

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007 Οδηγίες: Να απαντηθούν όλες οι ερωτήσεις. Αν κάπου κάνετε κάποιες υποθέσεις να αναφερθούν στη σχετική ερώτηση. Όλα τα αρχεία που αναφέρονται στα προβλήματα βρίσκονται στον ίδιο φάκελο με το εκτελέσιμο

Διαβάστε περισσότερα

Block Ciphers Modes. Ramki Thurimella

Block Ciphers Modes. Ramki Thurimella Block Ciphers Modes Ramki Thurimella Only Encryption I.e. messages could be modified Should not assume that nonsensical messages do no harm Always must be combined with authentication 2 Padding Must be

Διαβάστε περισσότερα

Potential Dividers. 46 minutes. 46 marks. Page 1 of 11

Potential Dividers. 46 minutes. 46 marks. Page 1 of 11 Potential Dividers 46 minutes 46 marks Page 1 of 11 Q1. In the circuit shown in the figure below, the battery, of negligible internal resistance, has an emf of 30 V. The pd across the lamp is 6.0 V and

Διαβάστε περισσότερα

Approximation of distance between locations on earth given by latitude and longitude

Approximation of distance between locations on earth given by latitude and longitude Approximation of distance between locations on earth given by latitude and longitude Jan Behrens 2012-12-31 In this paper we shall provide a method to approximate distances between two points on earth

Διαβάστε περισσότερα

ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS)

ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) Δρ. Χριστόφορος Χριστοφόρου Πανεπιστήμιο Κύπρου - Τμήμα Πληροφορικής Επανάληψη Definitions Components of a Communication System 1 Basic components of

Διαβάστε περισσότερα

ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS)

ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) ΕΠΛ 476: ΚΙΝΗΤΑ ΔΙΚΤΥΑ ΥΠΟΛΟΓΙΣΤΩΝ (MOBILE NETWORKS) Δρ. Χριστόφορος Χριστοφόρου Πανεπιστήμιο Κύπρου - Τμήμα Πληροφορικής Επανάληψη Definitions Components of a Communication System 1 Basic components of

Διαβάστε περισσότερα

Concrete Mathematics Exercises from 30 September 2016

Concrete Mathematics Exercises from 30 September 2016 Concrete Mathematics Exercises from 30 September 2016 Silvio Capobianco Exercise 1.7 Let H(n) = J(n + 1) J(n). Equation (1.8) tells us that H(2n) = 2, and H(2n+1) = J(2n+2) J(2n+1) = (2J(n+1) 1) (2J(n)+1)

Διαβάστε περισσότερα

derivation of the Laplacian from rectangular to spherical coordinates

derivation of the Laplacian from rectangular to spherical coordinates derivation of the Laplacian from rectangular to spherical coordinates swapnizzle 03-03- :5:43 We begin by recognizing the familiar conversion from rectangular to spherical coordinates (note that φ is used

Διαβάστε περισσότερα

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β

3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β 3.4 SUM AND DIFFERENCE FORMULAS Page Theorem cos(αβ cos α cos β -sin α cos(α-β cos α cos β sin α NOTE: cos(αβ cos α cos β cos(α-β cos α -cos β Proof of cos(α-β cos α cos β sin α Let s use a unit circle

Διαβάστε περισσότερα

TMA4115 Matematikk 3

TMA4115 Matematikk 3 TMA4115 Matematikk 3 Andrew Stacey Norges Teknisk-Naturvitenskapelige Universitet Trondheim Spring 2010 Lecture 12: Mathematics Marvellous Matrices Andrew Stacey Norges Teknisk-Naturvitenskapelige Universitet

Διαβάστε περισσότερα

(C) 2010 Pearson Education, Inc. All rights reserved.

(C) 2010 Pearson Education, Inc. All rights reserved. Connectionless transmission with datagrams. Connection-oriented transmission is like the telephone system You dial and are given a connection to the telephone of fthe person with whom you wish to communicate.

Διαβάστε περισσότερα

Strain gauge and rosettes

Strain gauge and rosettes Strain gauge and rosettes Introduction A strain gauge is a device which is used to measure strain (deformation) on an object subjected to forces. Strain can be measured using various types of devices classified

Διαβάστε περισσότερα

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 6/5/2006

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 6/5/2006 Οδηγίες: Να απαντηθούν όλες οι ερωτήσεις. Ολοι οι αριθμοί που αναφέρονται σε όλα τα ερωτήματα είναι μικρότεροι το 1000 εκτός αν ορίζεται διαφορετικά στη διατύπωση του προβλήματος. Διάρκεια: 3,5 ώρες Καλή

Διαβάστε περισσότερα

ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ. Ψηφιακή Οικονομία. Διάλεξη 7η: Consumer Behavior Mαρίνα Μπιτσάκη Τμήμα Επιστήμης Υπολογιστών

ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ. Ψηφιακή Οικονομία. Διάλεξη 7η: Consumer Behavior Mαρίνα Μπιτσάκη Τμήμα Επιστήμης Υπολογιστών ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ Ψηφιακή Οικονομία Διάλεξη 7η: Consumer Behavior Mαρίνα Μπιτσάκη Τμήμα Επιστήμης Υπολογιστών Τέλος Ενότητας Χρηματοδότηση Το παρόν εκπαιδευτικό υλικό έχει αναπτυχθεί

Διαβάστε περισσότερα

ΕΙΣΑΓΩΓΗ ΣΤΗ ΣΤΑΤΙΣΤΙΚΗ ΑΝΑΛΥΣΗ

ΕΙΣΑΓΩΓΗ ΣΤΗ ΣΤΑΤΙΣΤΙΚΗ ΑΝΑΛΥΣΗ ΕΙΣΑΓΩΓΗ ΣΤΗ ΣΤΑΤΙΣΤΙΚΗ ΑΝΑΛΥΣΗ ΕΛΕΝΑ ΦΛΟΚΑ Επίκουρος Καθηγήτρια Τµήµα Φυσικής, Τοµέας Φυσικής Περιβάλλοντος- Μετεωρολογίας ΓΕΝΙΚΟΙ ΟΡΙΣΜΟΙ Πληθυσµός Σύνολο ατόµων ή αντικειµένων στα οποία αναφέρονται

Διαβάστε περισσότερα

Other Test Constructions: Likelihood Ratio & Bayes Tests

Other Test Constructions: Likelihood Ratio & Bayes Tests Other Test Constructions: Likelihood Ratio & Bayes Tests Side-Note: So far we have seen a few approaches for creating tests such as Neyman-Pearson Lemma ( most powerful tests of H 0 : θ = θ 0 vs H 1 :

Διαβάστε περισσότερα

4.6 Autoregressive Moving Average Model ARMA(1,1)

4.6 Autoregressive Moving Average Model ARMA(1,1) 84 CHAPTER 4. STATIONARY TS MODELS 4.6 Autoregressive Moving Average Model ARMA(,) This section is an introduction to a wide class of models ARMA(p,q) which we will consider in more detail later in this

Διαβάστε περισσότερα

PARTIAL NOTES for 6.1 Trigonometric Identities

PARTIAL NOTES for 6.1 Trigonometric Identities PARTIAL NOTES for 6.1 Trigonometric Identities tanθ = sinθ cosθ cotθ = cosθ sinθ BASIC IDENTITIES cscθ = 1 sinθ secθ = 1 cosθ cotθ = 1 tanθ PYTHAGOREAN IDENTITIES sin θ + cos θ =1 tan θ +1= sec θ 1 + cot

Διαβάστε περισσότερα

Math 6 SL Probability Distributions Practice Test Mark Scheme

Math 6 SL Probability Distributions Practice Test Mark Scheme Math 6 SL Probability Distributions Practice Test Mark Scheme. (a) Note: Award A for vertical line to right of mean, A for shading to right of their vertical line. AA N (b) evidence of recognizing symmetry

Διαβάστε περισσότερα

Statistical Inference I Locally most powerful tests

Statistical Inference I Locally most powerful tests Statistical Inference I Locally most powerful tests Shirsendu Mukherjee Department of Statistics, Asutosh College, Kolkata, India. shirsendu st@yahoo.co.in So far we have treated the testing of one-sided

Διαβάστε περισσότερα

6.1. Dirac Equation. Hamiltonian. Dirac Eq.

6.1. Dirac Equation. Hamiltonian. Dirac Eq. 6.1. Dirac Equation Ref: M.Kaku, Quantum Field Theory, Oxford Univ Press (1993) η μν = η μν = diag(1, -1, -1, -1) p 0 = p 0 p = p i = -p i p μ p μ = p 0 p 0 + p i p i = E c 2 - p 2 = (m c) 2 H = c p 2

Διαβάστε περισσότερα

Modbus basic setup notes for IO-Link AL1xxx Master Block

Modbus basic setup notes for IO-Link AL1xxx Master Block n Modbus has four tables/registers where data is stored along with their associated addresses. We will be using the holding registers from address 40001 to 49999 that are R/W 16 bit/word. Two tables that

Διαβάστε περισσότερα

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ.

Απόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ. Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο The time integral of a force is referred to as impulse, is determined by and is obtained from: Newton s 2 nd Law of motion states that the action

Διαβάστε περισσότερα

Every set of first-order formulas is equivalent to an independent set

Every set of first-order formulas is equivalent to an independent set Every set of first-order formulas is equivalent to an independent set May 6, 2008 Abstract A set of first-order formulas, whatever the cardinality of the set of symbols, is equivalent to an independent

Διαβάστε περισσότερα

Finite Field Problems: Solutions

Finite Field Problems: Solutions Finite Field Problems: Solutions 1. Let f = x 2 +1 Z 11 [x] and let F = Z 11 [x]/(f), a field. Let Solution: F =11 2 = 121, so F = 121 1 = 120. The possible orders are the divisors of 120. Solution: The

Διαβάστε περισσότερα

ST5224: Advanced Statistical Theory II

ST5224: Advanced Statistical Theory II ST5224: Advanced Statistical Theory II 2014/2015: Semester II Tutorial 7 1. Let X be a sample from a population P and consider testing hypotheses H 0 : P = P 0 versus H 1 : P = P 1, where P j is a known

Διαβάστε περισσότερα

Mean bond enthalpy Standard enthalpy of formation Bond N H N N N N H O O O

Mean bond enthalpy Standard enthalpy of formation Bond N H N N N N H O O O Q1. (a) Explain the meaning of the terms mean bond enthalpy and standard enthalpy of formation. Mean bond enthalpy... Standard enthalpy of formation... (5) (b) Some mean bond enthalpies are given below.

Διαβάστε περισσότερα

Bayesian statistics. DS GA 1002 Probability and Statistics for Data Science.

Bayesian statistics. DS GA 1002 Probability and Statistics for Data Science. Bayesian statistics DS GA 1002 Probability and Statistics for Data Science http://www.cims.nyu.edu/~cfgranda/pages/dsga1002_fall17 Carlos Fernandez-Granda Frequentist vs Bayesian statistics In frequentist

Διαβάστε περισσότερα

Μηχανική Μάθηση Hypothesis Testing

Μηχανική Μάθηση Hypothesis Testing ΕΛΛΗΝΙΚΗ ΔΗΜΟΚΡΑΤΙΑ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΡΗΤΗΣ Μηχανική Μάθηση Hypothesis Testing Γιώργος Μπορμπουδάκης Τμήμα Επιστήμης Υπολογιστών Procedure 1. Form the null (H 0 ) and alternative (H 1 ) hypothesis 2. Consider

Διαβάστε περισσότερα

Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3

Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3 Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3 1 State vector space and the dual space Space of wavefunctions The space of wavefunctions is the set of all

Διαβάστε περισσότερα

Areas and Lengths in Polar Coordinates

Areas and Lengths in Polar Coordinates Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the

Διαβάστε περισσότερα

Partial Differential Equations in Biology The boundary element method. March 26, 2013

Partial Differential Equations in Biology The boundary element method. March 26, 2013 The boundary element method March 26, 203 Introduction and notation The problem: u = f in D R d u = ϕ in Γ D u n = g on Γ N, where D = Γ D Γ N, Γ D Γ N = (possibly, Γ D = [Neumann problem] or Γ N = [Dirichlet

Διαβάστε περισσότερα

Second Order RLC Filters

Second Order RLC Filters ECEN 60 Circuits/Electronics Spring 007-0-07 P. Mathys Second Order RLC Filters RLC Lowpass Filter A passive RLC lowpass filter (LPF) circuit is shown in the following schematic. R L C v O (t) Using phasor

Διαβάστε περισσότερα

Τηλεπικοινωνιακά Συστήματα ΙΙ

Τηλεπικοινωνιακά Συστήματα ΙΙ Τηλεπικοινωνιακά Συστήματα ΙΙ Διάλεξη 3: Εισαγωγή στην Έννοια της Διαμόρφωσης Δρ. Μιχάλης Παρασκευάς Επίκουρος Καθηγητής 1 Ατζέντα 1. Η ανάγκη για διαμόρφωση 2. Είδη διαμόρφωσης 3. Διαμόρφωση με ημιτονοειδές

Διαβάστε περισσότερα

C.S. 430 Assignment 6, Sample Solutions

C.S. 430 Assignment 6, Sample Solutions C.S. 430 Assignment 6, Sample Solutions Paul Liu November 15, 2007 Note that these are sample solutions only; in many cases there were many acceptable answers. 1 Reynolds Problem 10.1 1.1 Normal-order

Διαβάστε περισσότερα

ΚΥΠΡΙΑΚΟΣ ΣΥΝΔΕΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY 21 ος ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ Δεύτερος Γύρος - 30 Μαρτίου 2011

ΚΥΠΡΙΑΚΟΣ ΣΥΝΔΕΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY 21 ος ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ Δεύτερος Γύρος - 30 Μαρτίου 2011 Διάρκεια Διαγωνισμού: 3 ώρες Απαντήστε όλες τις ερωτήσεις Μέγιστο Βάρος (20 Μονάδες) Δίνεται ένα σύνολο από N σφαιρίδια τα οποία δεν έχουν όλα το ίδιο βάρος μεταξύ τους και ένα κουτί που αντέχει μέχρι

Διαβάστε περισσότερα

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1

Practice Exam 2. Conceptual Questions. 1. State a Basic identity and then verify it. (a) Identity: Solution: One identity is csc(θ) = 1 Conceptual Questions. State a Basic identity and then verify it. a) Identity: Solution: One identity is cscθ) = sinθ) Practice Exam b) Verification: Solution: Given the point of intersection x, y) of the

Διαβάστε περισσότερα

ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΤΜΗΜΑ ΝΟΣΗΛΕΥΤΙΚΗΣ

ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΤΜΗΜΑ ΝΟΣΗΛΕΥΤΙΚΗΣ ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΤΜΗΜΑ ΝΟΣΗΛΕΥΤΙΚΗΣ ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ ΨΥΧΟΛΟΓΙΚΕΣ ΕΠΙΠΤΩΣΕΙΣ ΣΕ ΓΥΝΑΙΚΕΣ ΜΕΤΑ ΑΠΟ ΜΑΣΤΕΚΤΟΜΗ ΓΕΩΡΓΙΑ ΤΡΙΣΟΚΚΑ Λευκωσία 2012 ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΣΧΟΛΗ ΕΠΙΣΤΗΜΩΝ

Διαβάστε περισσότερα

Physical DB Design. B-Trees Index files can become quite large for large main files Indices on index files are possible.

Physical DB Design. B-Trees Index files can become quite large for large main files Indices on index files are possible. B-Trees Index files can become quite large for large main files Indices on index files are possible 3 rd -level index 2 nd -level index 1 st -level index Main file 1 The 1 st -level index consists of pairs

Διαβάστε περισσότερα

Εργαστήριο Ανάπτυξης Εφαρμογών Βάσεων Δεδομένων. Εξάμηνο 7 ο

Εργαστήριο Ανάπτυξης Εφαρμογών Βάσεων Δεδομένων. Εξάμηνο 7 ο Εργαστήριο Ανάπτυξης Εφαρμογών Βάσεων Δεδομένων Εξάμηνο 7 ο Procedures and Functions Stored procedures and functions are named blocks of code that enable you to group and organize a series of SQL and PL/SQL

Διαβάστε περισσότερα

EPL 603 TOPICS IN SOFTWARE ENGINEERING. Lab 5: Component Adaptation Environment (COPE)

EPL 603 TOPICS IN SOFTWARE ENGINEERING. Lab 5: Component Adaptation Environment (COPE) EPL 603 TOPICS IN SOFTWARE ENGINEERING Lab 5: Component Adaptation Environment (COPE) Performing Static Analysis 1 Class Name: The fully qualified name of the specific class Type: The type of the class

Διαβάστε περισσότερα

Example of the Baum-Welch Algorithm

Example of the Baum-Welch Algorithm Example of the Baum-Welch Algorithm Larry Moss Q520, Spring 2008 1 Our corpus c We start with a very simple corpus. We take the set Y of unanalyzed words to be {ABBA, BAB}, and c to be given by c(abba)

Διαβάστε περισσότερα

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 11/3/2006

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 11/3/2006 ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 11/3/26 Οδηγίες: Να απαντηθούν όλες οι ερωτήσεις. Ολοι οι αριθμοί που αναφέρονται σε όλα τα ερωτήματα μικρότεροι το 1 εκτός αν ορίζεται διαφορετικά στη διατύπωση

Διαβάστε περισσότερα

Πρόβλημα 1: Αναζήτηση Ελάχιστης/Μέγιστης Τιμής

Πρόβλημα 1: Αναζήτηση Ελάχιστης/Μέγιστης Τιμής Πρόβλημα 1: Αναζήτηση Ελάχιστης/Μέγιστης Τιμής Να γραφεί πρόγραμμα το οποίο δέχεται ως είσοδο μια ακολουθία S από n (n 40) ακέραιους αριθμούς και επιστρέφει ως έξοδο δύο ακολουθίες από θετικούς ακέραιους

Διαβάστε περισσότερα

EPL324: Tutorials* on Communications and Networks Tutorial 2: Chapter 1 Review Questions

EPL324: Tutorials* on Communications and Networks Tutorial 2: Chapter 1 Review Questions EPL324: Tutorials* on Communications and Networks Tutorial 2: Chapter 1 Review Questions Pavlos Antoniou University of Cyprus Department of Computer Science * The material is taken from J.F. Kurose & K.W.

Διαβάστε περισσότερα

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013

Jesse Maassen and Mark Lundstrom Purdue University November 25, 2013 Notes on Average Scattering imes and Hall Factors Jesse Maassen and Mar Lundstrom Purdue University November 5, 13 I. Introduction 1 II. Solution of the BE 1 III. Exercises: Woring out average scattering

Διαβάστε περισσότερα

ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ. «ΜΕΛΕΤΗ ΚΑΙ ΕΡΓΑΣΤΗΡΙΑΚΕΣ ΜΕΤΡΗΣΕΙΣ BER ΓΙΑ ΣΗΜΑΤΑ QPSK, π/8 PSK, 16QAM, 64- QAM ΜΕ ΧΡΗΣΗ ΓΕΝΝΗΤΡΙΑΣ ΣΗΜΑΤΟΣ ΚΑΙ ΑΝΑΛΥΤΗ ΣΗΜΑΤΟΣ»

ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ. «ΜΕΛΕΤΗ ΚΑΙ ΕΡΓΑΣΤΗΡΙΑΚΕΣ ΜΕΤΡΗΣΕΙΣ BER ΓΙΑ ΣΗΜΑΤΑ QPSK, π/8 PSK, 16QAM, 64- QAM ΜΕ ΧΡΗΣΗ ΓΕΝΝΗΤΡΙΑΣ ΣΗΜΑΤΟΣ ΚΑΙ ΑΝΑΛΥΤΗ ΣΗΜΑΤΟΣ» ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ «ΜΕΛΕΤΗ ΚΑΙ ΕΡΓΑΣΤΗΡΙΑΚΕΣ ΜΕΤΡΗΣΕΙΣ BER ΓΙΑ ΣΗΜΑΤΑ QPSK, π/8 PSK, 16QAM, 64- QAM ΜΕ ΧΡΗΣΗ ΓΕΝΝΗΤΡΙΑΣ ΣΗΜΑΤΟΣ ΚΑΙ ΑΝΑΛΥΤΗ ΣΗΜΑΤΟΣ» ΟΛΓΑ ΛΑΔΑ Α.Ε.Μ. 2572 ΑΘΑΝΑΣΙΑ ΧΡΟΝΗ Α.Ε.Μ 1802 ΕΠΙΒΛΕΠΩΝ

Διαβάστε περισσότερα

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +

k A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R + Chapter 3. Fuzzy Arithmetic 3- Fuzzy arithmetic: ~Addition(+) and subtraction (-): Let A = [a and B = [b, b in R If x [a and y [b, b than x+y [a +b +b Symbolically,we write A(+)B = [a (+)[b, b = [a +b

Διαβάστε περισσότερα

5.4 The Poisson Distribution.

5.4 The Poisson Distribution. The worst thing you can do about a situation is nothing. Sr. O Shea Jackson 5.4 The Poisson Distribution. Description of the Poisson Distribution Discrete probability distribution. The random variable

Διαβάστε περισσότερα

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =?

ANSWERSHEET (TOPIC = DIFFERENTIAL CALCULUS) COLLECTION #2. h 0 h h 0 h h 0 ( ) g k = g 0 + g 1 + g g 2009 =? Teko Classes IITJEE/AIEEE Maths by SUHAAG SIR, Bhopal, Ph (0755) 3 00 000 www.tekoclasses.com ANSWERSHEET (TOPIC DIFFERENTIAL CALCULUS) COLLECTION # Question Type A.Single Correct Type Q. (A) Sol least

Διαβάστε περισσότερα

Notes on the Open Economy

Notes on the Open Economy Notes on the Open Econom Ben J. Heijdra Universit of Groningen April 24 Introduction In this note we stud the two-countr model of Table.4 in more detail. restated here for convenience. The model is Table.4.

Διαβάστε περισσότερα

Δίκτυα Απευθείας Ζεύξης

Δίκτυα Απευθείας Ζεύξης Δίκτυα Απευθείας Ζεύξης Επικοινωνία μεταξύ δύο υπολογιστώνοιοποίοιείναι απευθείας συνδεδεμένοι Φυσικό Επίπεδο. Περίληψη Ζεύξεις σημείου προς σημείο (point-to-point links) Ανάλυση σημάτων Μέγιστη χωρητικότητα

Διαβάστε περισσότερα

Inverse trigonometric functions & General Solution of Trigonometric Equations. ------------------ ----------------------------- -----------------

Inverse trigonometric functions & General Solution of Trigonometric Equations. ------------------ ----------------------------- ----------------- Inverse trigonometric functions & General Solution of Trigonometric Equations. 1. Sin ( ) = a) b) c) d) Ans b. Solution : Method 1. Ans a: 17 > 1 a) is rejected. w.k.t Sin ( sin ) = d is rejected. If sin

Διαβάστε περισσότερα

Matrices and Determinants

Matrices and Determinants Matrices and Determinants SUBJECTIVE PROBLEMS: Q 1. For what value of k do the following system of equations possess a non-trivial (i.e., not all zero) solution over the set of rationals Q? x + ky + 3z

Διαβάστε περισσότερα

UNIVERSITY OF CALIFORNIA. EECS 150 Fall ) You are implementing an 4:1 Multiplexer that has the following specifications:

UNIVERSITY OF CALIFORNIA. EECS 150 Fall ) You are implementing an 4:1 Multiplexer that has the following specifications: UNIVERSITY OF CALIFORNIA Department of Electrical Engineering and Computer Sciences EECS 150 Fall 2001 Prof. Subramanian Midterm II 1) You are implementing an 4:1 Multiplexer that has the following specifications:

Διαβάστε περισσότερα

ΤΕΙ ΚΑΒΑΛΑΣ ΣΧΟΛΗ ΤΕΧΝΟΛΟΓΙΚΩΝ ΕΦΑΡΜΟΓΩΝ ΤΜΗΜΑ ΗΛΕΚΤΡΟΛΟΓΙΑΣ ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ

ΤΕΙ ΚΑΒΑΛΑΣ ΣΧΟΛΗ ΤΕΧΝΟΛΟΓΙΚΩΝ ΕΦΑΡΜΟΓΩΝ ΤΜΗΜΑ ΗΛΕΚΤΡΟΛΟΓΙΑΣ ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ ΤΕΙ ΚΑΒΑΛΑΣ ΣΧΟΛΗ ΤΕΧΝΟΛΟΓΙΚΩΝ ΕΦΑΡΜΟΓΩΝ ΤΜΗΜΑ ΗΛΕΚΤΡΟΛΟΓΙΑΣ ΠΤΥΧΙΑΚΗ ΕΡΓΑΣΙΑ ΜΕΛΕΤΗ ΦΩΤΟΒΟΛΤΑΙΚΟΥ ΠΑΡΚΟΥ ΜΕ ΟΙΚΙΣΚΟΥΣ ΓΙΑ ΠΑΡΑΓΩΓΗ ΗΛΕΚΤΡΙΚΗΣ ΕΝΕΡΓΕΙΑΣ ΜΕΣΗΣ ΤΑΣΗΣ STUDY PHOTOVOLTAIC PARK WITH SUBSTATIONS

Διαβάστε περισσότερα

Δίκτυα Δακτυλίου. Token Ring - Polling

Δίκτυα Δακτυλίου. Token Ring - Polling Δίκτυα Δακτυλίου Token Ring - Polling Όλοι οι κόμβοι είναι τοποθετημένοι σε ένα δακτύλιο. Εκπέμπει μόνο ο κόμβος ο οποίος έχει τη σκυτάλη (token). The token consists of a number of octets in a specific

Διαβάστε περισσότερα

ΑΝΙΧΝΕΥΣΗ ΓΕΓΟΝΟΤΩΝ ΒΗΜΑΤΙΣΜΟΥ ΜΕ ΧΡΗΣΗ ΕΠΙΤΑΧΥΝΣΙΟΜΕΤΡΩΝ ΔΙΠΛΩΜΑΤΙΚΗ ΕΡΓΑΣΙΑ

ΑΝΙΧΝΕΥΣΗ ΓΕΓΟΝΟΤΩΝ ΒΗΜΑΤΙΣΜΟΥ ΜΕ ΧΡΗΣΗ ΕΠΙΤΑΧΥΝΣΙΟΜΕΤΡΩΝ ΔΙΠΛΩΜΑΤΙΚΗ ΕΡΓΑΣΙΑ ΕΘΝΙΚΟ ΜΕΤΣΟΒΙΟ ΠΟΛΥΤΕΧΝΕΙΟ ΣΧΟΛΗ ΗΛΕΚΤΡΟΛΟΓΩΝ ΜΗΧΑΝΙΚΩΝ ΚΑΙ ΜΗΧΑΝΙΚΩΝ ΥΠΟΛΟΓΙΣΤΩΝ ΤΟΜΕΑΣ ΕΠΙΚΟΙΝΩΝΙΩΝ ΗΛΕΚΤΡΟΝΙΚΗΣ ΚΑΙ ΣΥΣΤΗΜΑΤΩΝ ΠΛΗΡΟΦΟΡΙΚΗΣ ΑΝΙΧΝΕΥΣΗ ΓΕΓΟΝΟΤΩΝ ΒΗΜΑΤΙΣΜΟΥ ΜΕ ΧΡΗΣΗ ΕΠΙΤΑΧΥΝΣΙΟΜΕΤΡΩΝ

Διαβάστε περισσότερα

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 24/3/2007

ΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 24/3/2007 Οδηγίες: Να απαντηθούν όλες οι ερωτήσεις. Όλοι οι αριθμοί που αναφέρονται σε όλα τα ερωτήματα μικρότεροι του 10000 εκτός αν ορίζεται διαφορετικά στη διατύπωση του προβλήματος. Αν κάπου κάνετε κάποιες υποθέσεις

Διαβάστε περισσότερα

Lecture 34 Bootstrap confidence intervals

Lecture 34 Bootstrap confidence intervals Lecture 34 Bootstrap confidence intervals Confidence Intervals θ: an unknown parameter of interest We want to find limits θ and θ such that Gt = P nˆθ θ t If G 1 1 α is known, then P θ θ = P θ θ = 1 α

Διαβάστε περισσότερα

Review Test 3. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Review Test 3. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Review Test MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Find the exact value of the expression. 1) sin - 11π 1 1) + - + - - ) sin 11π 1 ) ( -

Διαβάστε περισσότερα

is like multiplying by the conversion factor of. Dividing by 2π gives you the

is like multiplying by the conversion factor of. Dividing by 2π gives you the Chapter Graphs of Trigonometric Functions Answer Ke. Radian Measure Answers. π. π. π. π. 7π. π 7. 70 8. 9. 0 0. 0. 00. 80. Multipling b π π is like multipling b the conversion factor of. Dividing b 0 gives

Διαβάστε περισσότερα

Assalamu `alaikum wr. wb.

Assalamu `alaikum wr. wb. LUMP SUM Assalamu `alaikum wr. wb. LUMP SUM Wassalamu alaikum wr. wb. Assalamu `alaikum wr. wb. LUMP SUM Wassalamu alaikum wr. wb. LUMP SUM Lump sum lump sum lump sum. lump sum fixed price lump sum lump

Διαβάστε περισσότερα

CMOS Technology for Computer Architects

CMOS Technology for Computer Architects CMOS Technology for Computer Architects Iakovos Mavroidis Giorgos Passas Manolis Katevenis Lecture 13: On chip SRAM Technology FORTH ICS / EURECCA & UoC GREECE ABC A A E F A BCDAECF A AB C DE ABCDAECF

Διαβάστε περισσότερα

Εγκατάσταση λογισμικού και αναβάθμιση συσκευής Device software installation and software upgrade

Εγκατάσταση λογισμικού και αναβάθμιση συσκευής Device software installation and software upgrade Για να ελέγξετε το λογισμικό που έχει τώρα η συσκευή κάντε κλικ Menu > Options > Device > About Device Versions. Στο πιο κάτω παράδειγμα η συσκευή έχει έκδοση λογισμικού 6.0.0.546 με πλατφόρμα 6.6.0.207.

Διαβάστε περισσότερα

The challenges of non-stable predicates

The challenges of non-stable predicates The challenges of non-stable predicates Consider a non-stable predicate Φ encoding, say, a safety property. We want to determine whether Φ holds for our program. The challenges of non-stable predicates

Διαβάστε περισσότερα

Υλοποίηση Δικτυακών Υποδομών και Υπηρεσιών: OSPF Cost

Υλοποίηση Δικτυακών Υποδομών και Υπηρεσιών: OSPF Cost Υλοποίηση Δικτυακών Υποδομών και Υπηρεσιών: OSPF Cost Πανεπιστήμιο Πελοποννήσου Τμήμα Επιστήμης & Τεχνολογίας Τηλεπικοινωνιών Ευάγγελος Α. Κοσμάτος Basic OSPF Configuration Υλοποίηση Δικτυακών Υποδομών

Διαβάστε περισσότερα

EE101: Resonance in RLC circuits

EE101: Resonance in RLC circuits EE11: Resonance in RLC circuits M. B. Patil mbatil@ee.iitb.ac.in www.ee.iitb.ac.in/~sequel Deartment of Electrical Engineering Indian Institute of Technology Bombay I V R V L V C I = I m = R + jωl + 1/jωC

Διαβάστε περισσότερα

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0.

DESIGN OF MACHINERY SOLUTION MANUAL h in h 4 0. DESIGN OF MACHINERY SOLUTION MANUAL -7-1! PROBLEM -7 Statement: Design a double-dwell cam to move a follower from to 25 6, dwell for 12, fall 25 and dwell for the remader The total cycle must take 4 sec

Διαβάστε περισσότερα

6.4 Superposition of Linear Plane Progressive Waves

6.4 Superposition of Linear Plane Progressive Waves .0 - Marine Hydrodynamics, Spring 005 Lecture.0 - Marine Hydrodynamics Lecture 6.4 Superposition of Linear Plane Progressive Waves. Oblique Plane Waves z v k k k z v k = ( k, k z ) θ (Looking up the y-ais

Διαβάστε περισσότερα

Written Examination. Antennas and Propagation (AA ) April 26, 2017.

Written Examination. Antennas and Propagation (AA ) April 26, 2017. Written Examination Antennas and Propagation (AA. 6-7) April 6, 7. Problem ( points) Let us consider a wire antenna as in Fig. characterized by a z-oriented linear filamentary current I(z) = I cos(kz)ẑ

Διαβάστε περισσότερα

The Simply Typed Lambda Calculus

The Simply Typed Lambda Calculus Type Inference Instead of writing type annotations, can we use an algorithm to infer what the type annotations should be? That depends on the type system. For simple type systems the answer is yes, and

Διαβάστε περισσότερα

ΠΕΡΙΕΧΟΜΕΝΑ. Κεφάλαιο 1: Κεφάλαιο 2: Κεφάλαιο 3:

ΠΕΡΙΕΧΟΜΕΝΑ. Κεφάλαιο 1: Κεφάλαιο 2: Κεφάλαιο 3: 4 Πρόλογος Η παρούσα διπλωµατική εργασία µε τίτλο «ιερεύνηση χωρικής κατανοµής µετεωρολογικών µεταβλητών. Εφαρµογή στον ελληνικό χώρο», ανατέθηκε από το ιεπιστηµονικό ιατµηµατικό Πρόγραµµα Μεταπτυχιακών

Διαβάστε περισσότερα

D Alembert s Solution to the Wave Equation

D Alembert s Solution to the Wave Equation D Alembert s Solution to the Wave Equation MATH 467 Partial Differential Equations J. Robert Buchanan Department of Mathematics Fall 2018 Objectives In this lesson we will learn: a change of variable technique

Διαβάστε περισσότερα

Homework 8 Model Solution Section

Homework 8 Model Solution Section MATH 004 Homework Solution Homework 8 Model Solution Section 14.5 14.6. 14.5. Use the Chain Rule to find dz where z cosx + 4y), x 5t 4, y 1 t. dz dx + dy y sinx + 4y)0t + 4) sinx + 4y) 1t ) 0t + 4t ) sinx

Διαβάστε περισσότερα

ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΣΧΟΛΗ ΓΕΩΤΕΧΝΙΚΩΝ ΕΠΙΣΤΗΜΩΝ ΚΑΙ ΔΙΑΧΕΙΡΙΣΗΣ ΠΕΡΙΒΑΛΛΟΝΤΟΣ. Πτυχιακή εργασία

ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΣΧΟΛΗ ΓΕΩΤΕΧΝΙΚΩΝ ΕΠΙΣΤΗΜΩΝ ΚΑΙ ΔΙΑΧΕΙΡΙΣΗΣ ΠΕΡΙΒΑΛΛΟΝΤΟΣ. Πτυχιακή εργασία ΤΕΧΝΟΛΟΓΙΚΟ ΠΑΝΕΠΙΣΤΗΜΙΟ ΚΥΠΡΟΥ ΣΧΟΛΗ ΓΕΩΤΕΧΝΙΚΩΝ ΕΠΙΣΤΗΜΩΝ ΚΑΙ ΔΙΑΧΕΙΡΙΣΗΣ ΠΕΡΙΒΑΛΛΟΝΤΟΣ Πτυχιακή εργασία ΑΝΑΛΥΣΗ ΚΟΣΤΟΥΣ-ΟΦΕΛΟΥΣ ΓΙΑ ΤΗ ΔΙΕΙΣΔΥΣΗ ΤΩΝ ΑΝΑΝΕΩΣΙΜΩΝ ΠΗΓΩΝ ΕΝΕΡΓΕΙΑΣ ΣΤΗΝ ΚΥΠΡΟ ΜΕΧΡΙ ΤΟ 2030

Διαβάστε περισσότερα

Numerical Analysis FMN011

Numerical Analysis FMN011 Numerical Analysis FMN011 Carmen Arévalo Lund University carmen@maths.lth.se Lecture 12 Periodic data A function g has period P if g(x + P ) = g(x) Model: Trigonometric polynomial of order M T M (x) =

Διαβάστε περισσότερα

Section 9.2 Polar Equations and Graphs

Section 9.2 Polar Equations and Graphs 180 Section 9. Polar Equations and Graphs In this section, we will be graphing polar equations on a polar grid. In the first few examples, we will write the polar equation in rectangular form to help identify

Διαβάστε περισσότερα