CFT approach to the q-painlevé VI equation
|
|
- Θεοφιλά Βλαχόπουλος
- 5 χρόνια πριν
- Προβολές:
Transcript
1 Journal of Integrable Systems 07 7 doi: 0.093/integr/xyx009 CFT approach to the q-painlevé VI equation M. Jimbo Department of Mathematics Rikkyo University Toshima-ku Tokyo Japan H. Nagoya School of Mathematics and Physics Kanazawa University Kanazawa Ishikawa 90-9 Japan Corresponding author. nagoya@se.kanazawa-u.ac.jp and H. Sakai Graduate School of Mathematical Sciences University of Tokyo Meguro-ku Tokyo Japan Communicated by: Masatoshi Noumi Received on 6 June 07; editorial decision on 8 August 07; accepted on 30 August 07] Iorgov Lisovyy and Teschner established a connection between isomonodromic deformation of linear differential equations and Liouville conformal field theory at c =. In this article we present a q analogue of their construction. We show that the general solution of the q-painlevé VI equation is a ratio of four tau functions each of which is given by a combinatorial series arising in the AGT correspondence. We also propose conjectural bilinear equations for the tau functions. Keywords: isomonodromy deformation; q Painleve equation; conformal field theory. Dedicated to Professor Kazuo Okamoto on the occasion of his seventieth birthday. Introduction Theory of isomonodromic deformation and Painlevé equations has long been a subject of intensive study with many applications both in mathematics and in physics. Recent discovery of the isomonodromy/cft correspondence 3] opened up a new perspective to this domain. In a nutshell it states that the Painlevé tau functions are Fourier transform of conformal blocks at c =. The AGT relation allows one to write a combinatorial formula for the latter thereby giving an explicit series representation for generic Painlevé tau functions. The initial conjectures of 3] concern the sixth Painlevé PVI equation and at present three different proofs are known. In the first approach 4] one constructs solutions to the linear problem out of conformal blocks with the insertion of a degenerate primary field. The second approach 5] also makes use of CFT ideas but leads directly to bilinear differential equations for tau functions. The third approach 6] is based on the Riemann Hilbert problem. It is shown that Fredholm determinant representation for tau functions reproduces the combinatorial series expansion without recourse to conformal blocks or The authors 07. Published by Oxford University Press. This is an Open Access article distributed under the terms of the Creative Commons Attribution Non-Commercial License which permits non-commercial re-use distribution and reproduction in any medium provided the original work is properly cited. For commercial re-use please contact journals.permissions@oup.com Downloaded from on 0 July 08
2 M. JIMBO ET AL. the AGT relation. Painlevé equations of other types are also studied by confluence ] in the framework of irregular conformal blocks 7 8] through the AGT correspondence 9] and using Fredholm determinants 0]. It is natural to ask whether a similar picture holds for the q difference analogue of Painlevé equations. This has been studied in ] for the qpiiid 8 equation. The aim of the present article is to give a q analogue of the construction of 4]. Our method is based on the work ] where the five-dimensional AGT correspondence was studied in the light of the quantum toroidal gl algebra also known as the Ding Iohara Miki algebra. Having the central charge c = corresponds to choosing t = q where t q are the parameters of the algebra. This is a sort of classical limit in the sense that the quantum algebra reduces to the enveloping algebra of a Lie algebra see Section.. We use the trivalent vertex operators of ] to introduce a q analogue of primary fields and conformal blocks. As in the continuous case a key property is the braiding relation in the presence of the degenerate field. Following the scheme of 4] we then write the solution Yx of the Riemann problem as Fourier transform of appropriate conformal block functions. For the sake of concreteness we restrict our discussion to the setting relevant to the qpvi equation. Also we do not discuss the issue of convergence of these series. The above construction allows us to relate the unknown functions y z of qpvi to tau functions. More specifically we express y z in terms of four tau functions which arise from the expansions at x = 0or x = ; see below. On the other hand in view of the work 3 4] we expect that there are four more tau functions which naturally enter the picture; these are the ones related to the singular points other than x = 0. However for the lack of the notion of fusion it is not clear to us how to related them to y z. The absence of fusion is the main obstacle in the q analogue of isomonodromy theory. We present conjectural bilinear relations satisfied by these eight tau functions see Assuming the conjecture we give the final expression for y z in 3.4. The plan of the article is as follows. In Section we give a brief account of the results of ] restricting to the special case t = q. We introduce a q analogue of primary fields conformal blocks degenerate fields and their braiding. In Section 3 we apply them to the q analogue of the Riemann problem focusing attention to the setting of the qpvi equation. We derive a formula expressing the unknowns y z in terms of four tau functions. We then propose conjectural bilinear difference equations for eight tau functions. In appendix we give a direct combinatorial proof of the braiding relation used in the text. Notation. Throughout the article we fix q C such that q <. We set u] = q u / q a; q N = N j=0 aqj a... a k ; q = k j= a j; q and a; q q = jk=0 aqj+k. We use the q Gamma function q Barnes function and the theta function Ɣ q u = q; q q u G q u q u = qu ; q q q; q u ; q q; q q q u u / ϑu = q uu / q q u q x = x q/x q; q which satisfy Ɣ q = G q = and Ɣ q u + =u]ɣ q u G q u + = Ɣ q ug q u ϑu + = ϑu = ϑ u. Downloaded from on 0 July 08
3 CFT APPROACH TO Q-PVI 3 A partition is a finite sequence of positive integers λ = λ... λ l such that λ λ l > 0. We set lλ = l. The conjugate partition λ = λ... λ l is defined by λ j = {i λ i j} l = λ. We denote by the set of all partitions. We regard a partition λ also as the subset {i j Z j λ i i } of Z and denote its cardinality by λ.for = i j Z >0 we set a λ = λ i j and l λ = λ j i. In the last formulas we set λ i = 0ifi > lλ resp. λ j = 0ifj > lλ.. q Analogue of conformal blocks In this section we collect background materials from ]. We shall restrict ourselves to the special case t = q where formulas of ] simplify considerably. We then introduce a q analogue of primary fields conformal blocks and the braiding relation for the degenerate fields analogue of operators.. Toroidal Lie algebra Let Z D be non-commuting variables satisfying ZD = qdz. The ring of Laurent polynomials C Z ± D ± in Z D is a Lie algebra with the Lie bracket given by the commutator. We consider its two-dimensional central extension which we denote by L. As a vector space L has C-basis Z k D l k l Z \{0 0} and central elements c c. The Lie bracket is defined by We set Z k D l Z k D l ]=q l k q l k Z k +k D l +l + δ k +k 0δ l +l 0q k l k c + l c. a r = Z r x + n = DZn x n = Zn D b r = D r y + n = ZD n y n = D n Z and introduce the generating series x ± z = n Z x± n z n y ± z = n Z y± n z n. We have two Heisenberg subalgebras of L a = r =0 Ca r Cc and b = r =0 Cb r Cc : a r a s ]=rδ r+s0 c b r b s ]= rδ r+s0 c. We say that an L-module has level l l if c acts as l id and c acts as l id. The Lie algebra L has automorphisms S T given by S : Z D D Z c c c c T : Z Z D DZ c c c c + c. They satisfy S 4 = ST 6 = id so that the group SL Z acts on L by automorphisms. We have Sb r = a r Sy ± z = x ± z.. Fock representations The most basic representations of L are the Fock representations of levels 0 and 0. Following ] we denote them by F u 0 and F u 0 u C respectively. The Fock representation F u 0 is irreducible under the Heisenberg subalgebra a. As a vector space we have F u 0 = Ca a...] vac where vac is a cyclic vector such that a r vac =0r > 0. The Downloaded from on 0 July 08
4 4 M. JIMBO ET AL. action of the generators x ± n is given by vertex operators x ± z q u± exp r q r a r z r exp ± r r q r a r z. r r The Fock representation F u 0 is the pullback of F u 0 by the automorphism S. It is irreducible with respect to the Heisenberg subalgebra b and y ± z act as vertex operators. On the other hand the action of a on F 0 u a basis of F 0 u is commutative. The joint eigenvectors { λ } λ of a are labelled by all partitions and constitute. In particular for the vector we have ur a r = q r x z = 0 x + z = δu/z where δx = n Z xn. Formulas for the action of a r and x ± z on a general λ can also be written explicitly. Since we do not use them in this article we refer the reader to 5]. Tensor products of N copies of F u 0 are closely related to representations of the W N algebra see e.g. 6 7]. We briefly explain this point in the case N =. Consider the tensor product of two Fock representations and its decomposition with respect to the Heisenberg subalgebra a F 0 u F 0 u = H u u where H is the Fock space of a and u u is the multiplicity space. The operators x ± z act on F 0 u F 0 u as a sum of two vertex operators. We can factor it into a product of two commuting operators q x ± z g ± z u u ±/ Tz; u /u ±/. The first factor represents the action of a on H g ± z =: exp ± r =0 q r a r + a r z r r where a r = a r id a r = id a r. The second factor acts on u u Tz; u = u + z + u z ± z =: exp ± q r a r a r z r. r r =0 and gives a free field realization of the deformed Virasoro algebra 8]. The space u u is a q analogue of the Virasoro Verma module with central charge c = and highest weight = where q = u /u. Downloaded from on 0 July 08
5 CFT APPROACH TO Q-PVI 5.3 Trivalent vertex operators For N Z we denote by F w N the pullback of F w 0 by the automorphism T N. The following intertwiners of L-modules are called trivalent vertex operators. ] N + wx = 0 w; N x = N x; 0 w N + wx : F 0 w ] : F N+ wx F N x F N+ wx F N x F 0 w. Such non-trivial intertwiners exist and are unique up to a scalar multiple ]. We introduce their components λ w 0 λ w relative to the basis { λ } of F w as follows. λ α = ˆtλ x w N λ wα α = λ ˆt λ x w N λ wα λ α F N x N+ α F wx. The numerical factors in front are ˆtλ x w N = qnλ c λ x λ f N λ w N ˆt λ x w N = qnλ f N λ c λ qw N λ x where nλ = l λ nλ = a λ λ λ f λ = λ q nλ nλ c λ = λ q l λ +a λ +. We normalize w w so that w vac = vac + w vac = vac +. Proposition. ] The operators λ w λ w are given by λ w =: + wη+ λ w λ w =: wη λ w lλ λ η ± λ w =: i η ± q j i i= j= where ± w =: exp q n n q a nw n n n =0 η ± w =: exp q n a n w n. n n =0 Downloaded from on 0 July 08
6 6 M. JIMBO ET AL. Of particular importance is their normal ordering rule. For a pair of partitions λ μ we introduce the Nekrasov factor by N λμ w = λ q l λ aμ w μ q a λ +lμ + w. Proposition. ] Let X Y be either or. Then the following normal ordering rule holds. { X λ zy μ w =: X λ zy μ w : Ĝq qw/zn μλ w/z for X = Y Ĝ q qw/zn μλ w/z for X = Y. where Ĝ q z = z; q q. It is useful to note the relations N λμ w = N μλ w w λ + μ f λ f μ. q nλ = f λq λ N λλ..3 c λ.4 Chiral primary field In what follows we set V w := F 0 q w F 0 q w. We fix its basis λ = λ + λ labelled by a pair λ = λ + λ of partitions. Consider the compositions of trivalent vertex operators : F 0 F F 0 F F 0 F 0 q /x q 3 /xw q 3 w /xw q 3 w q 3 w : F 0 F 0 F 0 F F 0 F q w q w /xw q w q /xw /x. By composing them we obtain an intertwiner of L-modules V w F 0 id V q w F V id /x /xw 3 q w F 0 /x V 3 q w..4 Taking further the vacuum-to-vacuum matrix coefficient of.4 we obtain a map V 3 ; w x : V w V 3 q w..5 Downloaded from on 0 July 08
7 CFT APPROACH TO Q-PVI 7 The matrix coefficients of.5 are given by μ V ; w x λ 3 = C qnλ + c λ+ q nλ c λ q nμ + c μ+ q nμ c μ f λ f μ + f μ q λ μ μ x μ λ vac λ+ q w λ q w μ + q 3 w μ q 3 w vac.6 where we set λ = λ + + λ for λ = λ + λ and C is a scalar factor independent of λ μ. We choose the normalization V q 3 x 3 N 3 3 ; w x = N 3 = ɛɛ =± G q + ɛ 3 ɛ..7 G q + 3 G q Here and after stands for the matrix coefficient. We regard.5asaq analogue of the chiral primary field of conformal dimension =..5 Conformal block function The m + point conformal block function is the expectation value of a product of chiral primary fields see Fig. m m F ; x m... x m+ σ m σ m σ 0 m m = V ; w m x m V ; w m x m V ; w x σ m σ m σ 0 m+ σ m where w p = q p w. The right-hand side is actually independent of w. Using formula.6 applying the normal ordering rule. and further using..3 for simplification we obtain the following explicit expression. m m F ; x m... x m+ σ m σ m σ 0 = m N p= p σ p σ p λ...λ m p= q pσ p x p+ m p= x σ p p σ p p m q p λ p m x p= p m p= ɛɛ =± N λ p ɛ λ p q ɛσp p ɛ σp ɛ..8 ɛɛ =± N λ p ɛ λ p q ɛσp ɛ σp ɛ We have set σ 0 = 0 σ m = m+ λ 0 = λ m = and the sum is taken over all λ p = λ p + λ p p =... m. Downloaded from on 0 July 08
8 8 M. JIMBO ET AL. Fig.. q-conformal block function. Formula.8 is the q version of the AGT formula for conformal blocks 9] specialized to the case t = q. The derivation given above from the quantum algebra viewpoint is due to ]..6 Degenerate field and braiding The normalization factor.7 has a zero when = / and 3 =±/. In this case we redefine the primary field by N = lim ± ε 0 G q ε N ε ± V ; w x = lim ± ε 0 G q ε V ε ; w x. ± We consider the conformal block function when one of the primary fields is V. We keep using the same letter F to denote them. By choosing m = and specializing parameters in.8 the four point conformal blocks can be evaluated in terms of Heine s basic hypergeometric series α β F γ ; x = Ɣ qαɣ q β Ɣ q γ q α q β φ ; q x q γ as follows. Here we have set F ; x + ε x = N q q x 0 x F ε +/4 + ε ε 0 + ε ; qx qx F ; x 0 + ε x = N q 0 0 F x ε0 +/4 + + ε 0 + ε 0 + ε 0 ; qx x N = q x /4 x 0 x. μμ =± G q + μ + μ 0. G q + G q 0 The following braiding relation holds. Downloaded from on 0 July 08
9 CFT APPROACH TO Q-PVI 9 Theorem.3 We have V ; x + ε V ; x + ε 0 = V ; x ε=± 0 + ε V ; x 0 + ε 0 B εε ] x q / x.9 0 x x where the braiding matrix is given by B εε ] x = ε ϑ 0 + ε + ε 0 ϑ 0 ϑ + ε + + ε 0 + u ϑ + u.0 with x = q u. For the vacuum matrix element the relation.9 is a consequence of the known connection formula for basic hypergeometric functions. At this writing it is not clear to us whether the general case can be deduced from this and the intertwining relation. In Appendix we give a direct combinatorial proof of the braiding relation.9. The braiding matrix.0 has the following properties. B εε ] qx ] = B εε x. 0 0 B 0 x ] ] = B q x. 0 ] x det B = ϑ ϑ u 0 ϑ 0 ϑ u + ] B x is -periodic in q-painlevé VI equation 3. Riemann problem This article deals with a non-linear non-autonomous q-difference equation called q-painlevé VIqPVI equation. It is derived from deformation theory of linear q-difference equations as a discrete analogue of isomonodromic deformation 0]. A remark is in order concerning the name of the equation. Discrete Painlevé equations are classified by rational surface theory and sometimes called by the name of the surface ]. From that viewpoint qpvi is an equation corresponding to the surface of type A 3. Besides this surface has symmetry by the Weyl group D 5. Accordingly qpvi is also referred to as the q-painlevé equation of type A 3 or the q-painlevé equation with D 5 -symmetry. Regarding discrete Painlevé equations pioneering researches by Ramani Grammaticos and their coworkers are well-known. The qpvi equation in the special case when an extra symmetry condition is fulfilled has been studied earlier by them under the name of discrete Painlevé III equation ]. Downloaded from on 0 July 08
10 0 M. JIMBO ET AL. In this section we review the content of 0] concerning the generalized Riemann problem associated with the qpvi equation. Let 0 t C.Weset R = max q tq tq t R = min q q tq tq t and assume that R < R. Fix also σ C and s C. Suppose we are given matrices Y x t Y 0t x t Y 0 x t with the following properties. i These matrices are holomorphic in the domains Y x t : R < x Y 0t x t : R < x < R Y 0 x t : x < R. 3. ii They are related to each other by Y x t = Y 0t x tb x Y 0t x t = Y 0 x tb x 3. ] B x = B + q x ] t B σ x = B q σ + t t 0 s x 0 iii At x or x 0 they have the behaviour Y x t = I + Y tx + Ox x 0 x x x Y x t = GtI + Ox 0 x x t x It follows that Yx t = Y x t is a solution of linear q-difference equations of the form We have Yqx t = Ax tyx t Ax t = A x + A tx + A 0 t x q x tq 3.6 Yx qt = Bx tyx t Bx t = xi + B 0t x tq. 3.7 t A = diagq q A 0 t = tq 3 t Gt diagq 0 q 0 Gt det Ax t = x q x tq t. x q x tq Though the argument is quite standard we outline the derivation for completeness. Downloaded from on 0 July 08
11 CFT APPROACH TO Q-PVI We take the determinant of the relations and rewrite them as /x tq /x; q q /x tq t /x; q det Y x t = ϑ q + x q t/x; q q + x det Y 0t x t ϑσ qx tq t /x; q = s ϑ q + x q t+ + x/t; q q t +t+ + q x ϑ 0 qx q + x/t; q t t x det Y 0 x t. Both sides of this expression are single valued and holomorphic on C. In view of the behaviour we conclude that det Y x t = q /x tq t /x; q /x tq /x; q. In particular the matrices Y x t Y 0t x t and Y 0 x t are generically invertible. Rewriting and using the periodicity of the braiding matrices we obtain Ax t := Y qx ty x t = Y 0t qx ty 0t x t = Y 0 qx ty 0 x t. A similar argument shows that Ax t is a rational function of x with the only poles at x = q q t. Using once again we find that Ax t has the form stated above. The derivation of 3.7 is quite similar. Introduce y = yt z = zt and w = wt by Ax t + = q wx y x q x tq Ay t ++ = y tq t qzy q where we use ± to indicate components of a matrix. Notation being as above the compatibility Ax qtbx t = Bqx tax t 3.8 of 3.6 and 3.7 leads to the qpvi equation. Here and after we write f t = f qt f t = f q t. Proposition 3. 0] The functions y z solve the qpvi system with the parameters yy = z tb z tb a 3 a 4 z b 3 z b 4 zz = y ta y ta b 3 b 4 y a 3 y a 4 a = q a = q t a 3 = q a 4 = q b = q 0 t b = q 0 t b 3 = q b 4 = q. Downloaded from on 0 July 08
12 M. JIMBO ET AL. Remark 3. From the compatibility condition 3.8 we obtain the expression of the matrix Bx t in terms of y and z etc. In particular the + element of the matrix B 0 q t is written as B 0 q t + = q+ zw q z CFT construction We are now in a position to construct solutions of the generalized Riemann problem in terms of conformal block functions. Following the method of 4] we consider the following sums of 5 point conformal blocks Y εε x t = k ε Y 0t εε x t = x k 0t ε = x k 0t ε Y 0 εε x t = x t k 0 ε s n t F ; q t+x q t t 3.0 n Z ε ε ε σ + n 0 s n t F ; q t q t+x t 3. n Z ε σ + n + ε σ + n 0 n+ ε t s F ; q t q t+x t n Z ε σ + n + σ + n + ε 0 s n t F ; q t t q t+x 3. n Z ε σ + n ε 0 where k ε = q ε/ ε t+ N ε ˆτ k 0t ε = k εq + / k 0 ε = k 0t εq t +t/+ t t t and ˆτ = n Z s n F t ; q t t. σ + n 0 We assume that these series converge in the domains 3.. The asymptotic behaviour are simple consequences of the expansion.8 of conformal blocks. The crucial point is the validity of the connection formulas due to the periodicity property.3 of the braiding matrix. Therefore formulas solve the generalized Riemann problem. Define the tau function by ] τ t s σ t = q t+ +t Gq + G q 0 ˆτ. 0 Downloaded from on 0 July 08
13 CFT APPROACH TO Q-PVI 3 Explicitly it has the AGT series representation ] τ t s σ t = ] ] s n t σ +n t 0 C t σ + n Z t σ + n t n Z with the definition ] C t σ εε = =± G q + ε + ε σg q + εσ t + ε 0 0 G q + σg q σ ] Z t σ t = t λ εε =± N λ ε q ε ε σ N λ ε q εσ t ε 0 0 λ=λ + λ εε =± N. λελ ε q ε ε σ Comparing the asymptotic expansion at x = 0 and x = we can express the + element of the matrix Ax t and Bx t in terms of tau functions. Theorem 3.3 The following expressions hold for y z and w in terms of tau functions: y =q t τ3τ 4 τ τ 3.4 τ τ τ τ z = q τ τ q τ τ 3.5 w =q Ɣ q q Ɣ q τ. τ Here we put ] ] τ = τ t s σ t τ = τ t s σ t 0 0 ] ] τ 3 = τ t 0 + s σ + t τ 4 = τ t 0 s σ t. Proof. From the explicit expression of the 5-point conformal block function.8 we have F 3 ; x 3 x x = N 4 σ σ 0 σ 0 = N 3 4 σ q σ σ x 0 3 F q 3 4 x 4 3 σ 3 F ; x 3 x 4 σ σ ; x x σ σ 0 + Ox + O. x 3 Downloaded from on 0 July 08
14 4 M. JIMBO ET AL. By using this expression we calculate the asymptotic behaviour of Y x t Y 0 x t and get ] t τ Gt εε = q C Ɣ t t q ε ε s σ t ε Y Ɣ q + ε t + = Ɣ q 0 τ Ɣ q τ τ where C = 0 + t + ε + t + + ε see for Gt and Y t. We can write down the exponents of matrices Ax t and Bx t in these terms. In particular the expressions A 0 t + = q 3 t q 0 q 0 Gt ++Gt + A t + = q q Y t + det Gt give the formula for w and y. The expression of z is obtained from B 0 q t + = Y t + Y q t + and the relation 3.9. In 3] Mano constructed two parametric local solutions of the qpvi equation near the critical points t = 0. The above formula for y extends Mano s asymptotic expansion to all orders. We expect that the formula 3.5 for z can be simplified see 3.4 below. 3.3 Bilinear equations In 4] Tsuda and Masuda formulated the tau function of the qpvi equation to be a function on the weight lattice of D 5 with symmetries under the affine Weyl group. Motivated by 4] we consider the set of eight tau functions defined by the AGT series 3.3: ] ] τ = τ t s σ t + τ = τ t s σ t 0 0 ] ] τ 3 = τ t 0 + s σ + t τ 4 = τ t 0 s σ t ] τ 5 = τ t s + ] σ t τ 6 = τ t s σ t 0 0 τ 7 = τ t ] s σ + t τ 8 = τ 0 t + ] s σ t. 0 For convenience we shift the parameter in the previous section to + /. Downloaded from on 0 July 08
15 CFT APPROACH TO Q-PVI 5 On the basis of a computer run we put forward: Conjecture 3.4 For the eight tau functions defined above the following bilinear equations hold. τ τ q t τ 3 τ 4 q tτ 5 τ 6 = τ τ t τ 3 τ 4 q t tτ 5 τ 6 = τ τ τ 3 τ 4 + q tq t τ 7 τ 8 = τ τ q t τ 3 τ 4 + q t tq t τ 7 τ 8 = τ 5 τ 6 + q +t / t τ 7 τ 8 τ τ = τ 5 τ 6 + q + +t / t τ 7 τ 8 τ τ = 0 3. τ 5 τ 6 + q 0 +t τ 7 τ 8 q t τ 3 τ 4 = 0 3. τ 5 τ 6 + q 0 +t τ 7 τ 8 q t τ 3 τ 4 = The solution y z of qpvi are expressed as y = q t τ3τ 4 τ τ z = q t t τ7τ 8 τ 5 τ The bilinear equations were originally proved in 3] in the special case when the tau functions are given by Casorati determinants of basic hypergeometric functions. It would be interesting if one can prove them in the general case by a proper extension of the methods of 5] or6]. Remark 3.5 Formula 3.5 for z is obtained from the asymptotic expansion at x =. The expansion at x = 0 gives an alternative formula for the same quantity. Comparing these and shifting to + / we arrive at the following bilinear relation: τ τ τ τ = q/+ q / q t τ q 0 q 3 τ 4 τ 3 τ 4. 0 This is consistent with the conjectured relations Acknowledgments The authors would like to thank Kazuki Hiroe Oleg Lisovyy Toshiyuki Mano Yousuke Ohyama Yusuke Ohkubo Teruhisa Tsuda Yasuhiko Yamada and Shintaro Yanagida for discussions. Funding JSPS KAKENHI JP6K0583 to M.J. in part; JSPS KAKENHI JP5K7560 to H.N. in part; JSPS KAKENHI JP5K04894 to H.S. in part. Downloaded from on 0 July 08
16 6 M. JIMBO ET AL. Appendix A. Braiding relation In this appendix we give a direct proof of Theorem.3. We rewrite the braiding relation.9 into the form of matrix elements α β λ μ for any partitions λ μ α β. The matrix element α β V ; x + ε V + ε σ ; x λ μ can be read off from the coefficient of t λ + μ x α β 3 in the 6 point conformal block t F ; x 3 + ε 3 x x t. σ 0 Formula.8 tells that it is a sum over a pair of partitions. By using N λμ = δ λμ N λλ the sum can be reduced further to one over a single partition. We thus find that Theorem.3 is equivalent to the following proposition. Proposition A. For any partitions λ μ α and β wehave where q q ε +/4 x ε =± Ɣ q + ε + ε σ X ε Ɣ q + ε λμαβ σ ; x x x = ε=± B εε q σ qx x X + λμαβ σ ; x x εσ+/4 x σ x ε =± Ɣ q + ε + εσ Y ε λμαβ Ɣ q + εσ σ ; x x ] q / x A. x = N αβ q N βλ q / σ N βμ q / +σ λ + μ q η + β x qx α + β N αηq N ηλ q +/ σ N ημ q +/ +σ x η x N ηβ q + N ηη X λμαβ σ ; x x = X + λμβα σ ; x x Y + λμαβ σ ; x x = N λμ q σ N αλ q σ / N βλ q σ / λ + μ λ + η qx q x α + β N ημq N αη q +σ +/ N βη q +σ +/ x η x N λη q σ + N ηη Y λμαβ σ ; x x = Y + μλαβ σ ; x x. Downloaded from on 0 July 08
17 CFT APPROACH TO Q-PVI 7 In the following we show that the identity A. is reduced to the connection formula of basic hypergeometric functions. First we prepare several lemmas. Lemma A. For any λ μ we have N λ μ u = N μλu. Proof. Since a λ j i = l λ i j for all i j Z >0 wehave N λ μ u = q aλij lμij u q aμij+lλij+ u. ij λ Therefore to prove the Lemma it suffices to show that the identity q aλij lμij u = q aμij+lλij+ u A. ij λij/ μ ij μ ij λij/ μ holds for all λ μ. Note that the product consists of all entries i j such that λ i >μ i and μ i + j λ i.weshowa. by induction with respect to the length of λ. Consider a sub-sequence λ n+ λ n+... λ n+s in λ such that λ n μ n λ i >μ i i = n +... n + s λ n+s+ μ n+s+. Put λ = λ n+... λ n+s and μ = μ n+... μ n+s. Then we have for i =... s and μ i + j λ i l μ n + i j = l μ i j l λ n + i j = l λi j because λ n μ n and λ n+s+ μ n+s+. We further divide a partition λ into sub-sequences λ m+... λ m+r such that λ m+ μ m λ i > μ i i = m +... m + r λ m+r+ μ n+r. Put ˆλ = λ m+... λ m+r and ˆμ = μ m+... μ m+r. Then we have again for i =... r and ˆμ i + j ˆλ i l μ m + i j = l ˆμ i j l λm + i j = lˆλi j because λ m+ μ m and λ m+r+ μ m+r. Replacing λ μ by ˆλ ˆμ we may assume without loss of generality that λ >μ λ i >μ i i =... lλ. A.3 If lλ = it is easy to check A.. Suppose A. is true for lλ = l. Let λ satisfy lλ = l. Assuming A.3 we choose the number k such that μ l k+ >λ l μ l k. Downloaded from on 0 July 08
18 8 M. JIMBO ET AL. Writing λ = ν λ l we compare A. for λ and for ν. In the left hand side of A. the factors for i <lremain the same as for ν. The product of factors for i = l is expressed as λl μ l +k j=0 q k j u k j= q λ l +μ l j +j u. A.4 In the right hand side of A. the factors for j >λ l remain the same as for ν. The product of factors for i = l is equal to λ l μ l q j u. j=0 The products of factors for i = l k... l and j λ l are equal to λ l μ i q l i m u m= before adding the l-th row and after they become λ l μ i q l i m u. m=0 Namely we lose the factor l i=l k q λ l +μi+l i u and gain the factor k m= qm u. Therefore the outcome can be written as A.4. We introduce the following operations on partitions λ : λ =λ... λ lλ A.5 r n λ =λ +... λ n + λ n+... n Z 0. A.6 Here we identify a partition λ with a sequence λ... λ lλ Lemma A.3 Let λ η be partitions. Then N ηλ q = 0 if and only if η = r n λ for some n 0. Proof. It is easy to show the if part. To show the only if part assume that η satisfies N ηλ q = 0. Then we have l η i j + a λ i j + = 0 i j η A.7 l λ i j + a η i j = 0 i j λ. A.8 Downloaded from on 0 July 08
19 CFT APPROACH TO Q-PVI 9 Using them we show i If lλ < i lη then η i =. ii If i minlλ lη then η i λ i + iii If i minlλ lη and η i λ i then i < lλ and η i λ i+. iv If i minlλ lη then η i λ i+. To see i suppose there exists such an i that lλ < i lη and η i. Then η η l ηη = 0 and a λ η = in contradiction with A.7. Since η i > 0 for i lη we must have η i =. To see ii suppose there exists such an i minlλ lη that η i >λ i +. Take the largest such i and let j = λ i +. Then i j η l η i j = 0 and a λ i j = which contradicts A.7. Under the assumption of iii we have i η i λ and a η i η i = 0. Further if i = lλ or else i < lλ and λ i+ <η i then we have l λ i η i = 0 which contradicts A.8. To show iv first assume i lλ and η i <λ i+ η i+ = λ i+ hold. Then i η i + λ a η i η i + = and l λ i η i + = which contradicts A.8. Similarly if i = lλ and η lλ <λ lλ then the same conclusion takes place. Now we prove the Lemma. If η i = λ i + for all i lλ then together with i we have η = r lη λ. Otherwise from ii iii and iv there exists an n such that η i = λ i + i n and η i = λ i+ for all n < i lλ. Moreover if lη lλ then η lλ η lλ = λ lλ which contradicts iii. Therefore lη = lλ and η = r n λ. Lemma A.4 Let λ μ and n Z 0. Using the notation A.5 and A.6 we set Then we have N ηλ q N ηη l = lλ k = lμ η = r n λ γ = r n μ { η = η n l λ n l+ n l. = N η λq N η η q η λ j= A.9 μ l N μη u = N μ η q q j u l u q l i+aμi u A.0 q lμlj+j u N μλ u = N μ λq u μ l+ j= i= q j u q lμl+j+j u l q l i+aμi+ u A. i= N μλ u N μη qu = N μ λq u u A. N μ η u N μλ u N μη qu = N μλqu N μη q u q η λ + k u A.3 qu Downloaded from on 0 July 08
20 0 M. JIMBO ET AL. μ l N γ λ u = N γ λq u q l+ γ μ q j u l u q l i+aμi u. A.4 q lμlj+j u Proof. By the definition we have j= a λi j = a λ i j + i =... l j Z >0 l λi j = l λ i j + i j λ a η i j = a η i j + i =... minl η l j Z >0 { l η i j = l η i j + i j η n l orn l and j n + i i > 0 j = n l. Using these relations we show below A.9 A.4. Proof of A.9. First we consider the case n l. We have N ηλ q N η λq = = ij η ij η λl j= q lηij a λ ij q lηij+ a λ ij+ q l λ lj+ j l l q l+i λ i q l i+η i i= i= ij λ ij λi<l i= q l λ ij+aηij q l λ ij++aηij+ and N η η N ηη = = l i= ij η ij η q lηij+ aηij+ q lηij aηij ij η q l+i+ η i q l i+η i. ij η q lηij++aηij++ q lηij+aηij+ Since η = λ +... λ n + λ n+... λ l and η λ = l + n + λ n+ we obtain A.9 for n l. Second we consider the case n l.wehave N ηλ q n N η λq = i= q n i λ i l i= q l i λ i q i l i+λ l i= q n+ i λ i n+ i=l+ q n+ i λ i q l+i λ i q l i+λ i = l i= q n l Downloaded from on 0 July 08
21 CFT APPROACH TO Q-PVI and N η η N ηη = q n l q n l+ l i=. q l+i λ i q l i+λ i Since η λ =n + l we obtain A.9 for n l. Proof of A.0. First we consider the case n l. Then by l η l we obtain N μη u N μ η q u = = ij μi l μ l j= q lμij+j u l q l i+aμi+ u q lμij+j u q j u l q lμlj+j u i= i= q l i+aμi u. Second we consider the case n l. Then we have a η i + j = a η i j if l<i n and l η i = l η i + for i Z >0. Hence we obtain lμ μi N μη u N μ η q u = i=l+ j=μ i+ + q aηij u l i= ql i+aμi u μl+ j= q lμl+j+j 3 u q aμn+ u = = μl μ l j= j=μ n+ + qj u μ n+ j= qj u μl j= q lμl+j+j 3 u q j u l q lμlj+j u i= q l i+aμi u. l i= ql i+aμi u q μ q μ n+ l u u Proof of A.. A.. Proof of A.. Proof of A.3. In A.0 choose n = l then rename l by l + and λ i by λ i. We obtain This follows from A. and A.0. Using the relation. and A. we have N μλ un μη q u N μλ qun μη qu = q η λ k N λμ u N η μ q u N λ μ qu N ημ qu = q η λ k k i= λ k+ j= q j u η k+ q lηk+j+j 3 u q l λk+j+j u q j u j= q k i+a λi+ u q k i+aηi u. Downloaded from on 0 July 08
22 M. JIMBO ET AL. First we consider the case n l. By definition we have for k + n l λ k + j j =... λ n+ l η k + j = n k + j = λ n+ + l λ k + j j = λ n λ + and for k + n + l η k + j = l λ k + j j =... η k+. Hence we obtain for k + n N μλ un μη q λ u N μλ qun μη qu = k+ q η λ k j= q j u q l λk+j+j u λ n+ q k+ n+λ n+ u λk++ = q η λ k qk n+λ n+ u q u. j= j=λ n+ + λk+ + j= q l λ k+j+j u q l λ k+j +j 3 u q j u We also obtain for k + n + N μλ un μη q λ u N μλ qun μη qu = k+ q j u λ k+ q lλk+j+j u q η λ k q l λk+j+j u q j u j= j= k i=n+ q k i+a λi+ u q k i+a λi+ u = q η λ k qk n+λ n+ u q u. Since η λ =n λ n+ we obtain A.3 for n l. Second we consider the case n l. By the definition we have l η i j = l λ i j i j η j l η i = n i i Z >0. Downloaded from on 0 July 08
23 CFT APPROACH TO Q-PVI 3 Hence we obtain N μλ un μη q u N μλ qun μη qu = q η λ k k i=n+ λ k+ j= q j u η k+ q lλk+j +j 3 u qn+k u q l λk+j+j u q j u q u j= q k i u q k i u = q η λ k q n+k u q u. Since η λ =n we obtain A.3 for n l. Proof of A.4. By A. we have γ l+ N γ λ u = N γ λq q j u u q lγ l+j+j u j= l q l i+aγ i+ u. Recall that γ = s n μ. First we consider the case n μ. By the definition we have l γ i j = a γ i j = Hence for l + μ n+ we have N γ λ u = N γ λq u i= { l μ i j + i j γ j n l μ i j + i j γ j n + a μ i j i =... μ n+ j Z >0 n j i = μ n+ + j Z >0 a μ i j i j γ i μ n+ + j Z >0. n j= l q l i+aμi u i= μl+ j= q j u q lμl+j+j 3 u μ l+ j=n+ μ l = N γ λq q j u u q lμlj+j u q μ q μ l u j= l q l i+aμi u q μ l u. i= q lμl+j++j u n+ +l+n u Downloaded from on 0 July 08
24 4 M. JIMBO ET AL. Similarly for l + = μ n+ + wehave N γ λ u = N γ λq u n j= μ l = N γ λq u j= q j u q lμl+j+j 3 u q j u q lμlj+j u l q l i+aμi u q μ l u i= q n u l q μ l u i= q l i+aμi u q μ l u. Here we use the inequality μ l+ n. For l + μ n+ + wehave μ l N γ λ u = N γ λq u l i=μ n+ + j= q j u q lμlj+j u q l i +aμi u j= μ n+ i= μ l = N γ λq q j u l u q lμlj+j u i= q l i+aμi u q l μ n+ +n u q l i+aμi u q l μ n+ +n u. Here we use the inequality μ l n. Since γ μ =n μ n+ we obtain A.4 for n μ. Second we consider the case n μ. By the definition we have l γ i j = l μ i j i j γ i { n j i = j Z >0 a γ i j = a μ i j i j γ i j Z >0. Hence we obtain μ l N γ λ u = N γ λq q j u u q lμlj+j u j= l q l i+aμi + u q l +n u. i= Since γ μ =n we obtain A.4 for n μ. Lemma A.4 enables us to reduce λ to λ of X ε λμαβ and Y ε λμαβ. Denote by T the q-shift operator with respect to x : T f x... x n = f qx... x n. Downloaded from on 0 July 08
25 CFT APPROACH TO Q-PVI 5 Lemma A.5 For partitions λ μ α βwehave X ε λμαβ σ ; x x = C q ε σ / q ε σ / q lλ ε + +σ +/ T X + λμαβ + σ + ; x x Y + λμαβ σ ; x x = C q± σ / q σ + q lλ++σ T Y + λμαβ + σ + ; x x Y λμαβ σ ; x x = C q σ x x q lλ T Y λμαβ + σ + ; x x where C = α lλ j= β lλ j= q j+ σ / q lαlλj+j+ σ 3/ q j σ / q l β lλj+j σ 3/ q lλ α β x lλ. q lλ i+aαi+ σ +/ lλ i= q lλ i+a β i σ +/ Proof of Proposition A.. By induction. If all partitions λ μ α and β are equal to then the identity A. is the connection formula of basic hypergeometric functions. By definition we have the symmetries lλ X ε λμαβ σ ; x x = X ε μλαβ σ ; x x X λμαβ σ ; x x = X + λμβα σ ; x x Y λμαβ σ ; x x = Y + μλαβ σ ; x x Y ε λμαβ σ ; x x = Y ε λμβα σ ; x x B ε x ] = B σ +ε x ] B σ ε x ] = B σ ε+ x ] σ x and by Lemma A. we have x X ε λμαβ σ ; x x = Y ε β α μ λ σ ; qx q x. Recall also the relations. and. for the braiding matrix. Because of these relations it suffices to show that for any partitions λ μ α and β the connection formula A. is equivalent to the formula A. for λ μ α and β acting by a q-difference operator. i= x x Downloaded from on 0 July 08
26 6 M. JIMBO ET AL. By Lemma A.5 the left-hand side of A. is computed as follows: q q +/4 x ε =± Ɣ q + + ε σ X + λμαβ x Ɣ q + σ ; x x = q q + +/4 x q /4 ε =± Ɣ q ε σ + q ± σ / x Ɣ q + q Cq σ / q lλ + +σ +/ T X + λμαβ + σ + ; x x = Cq σ 3/4 q± σ / q q q lλ+ +σ +3/4 T q + x x ε =± Ɣ q ε σ + Ɣ q + +/4 X + λμαβ + σ. Similarly by Lemma A.5 the right-hand side of A. is computed as follows: εσ+/4 q σ qx ε =± Ɣ q + ε + εσ Y ε λμαβ x ε=± Ɣ q + εσ σ ; x x B ε+ x ] q / x σ x x εσ+/+/4 ε =± Ɣ q + ε + + εσ + q ± σ / Ɣ q + εσ + q = q σ qx +/ x ε=± + B ε+ σ + x ] q +/ +// x x x Cq lλ++εσ +/ T Y ε λμαβ + σ + = Cq σ 3/4 q± σ / q { q lλ+ +σ +3/4 T ε=± qx + B ε+ σ + x ] q +/ +// x x +/ q σ 3/4 q σ +/ ε =± Ɣ q + ε + + εσ + Ɣ q + εσ + εσ+/+/4 Y ε λμαβ + σ + x x +/ }. Therefore the identity A. with parameters σ for λ μ α β is reduced to the identity A. with parameters + / σ + / for λ μ α β. Downloaded from on 0 July 08
27 CFT APPROACH TO Q-PVI 7 References. Gamayun O. Iorgov N. & Lisovyy O. 0 Conformal field theory of Painlevé VI. JHEP p.. Gamayun O. Iorgov N. & Lisovyy O. 03 How instanton combinatorics solves Painlevé VIV and IIIs. J. Phys. A: Math. Theor Iorgov N. Lisovyy O. & Tykhyy Yu. 03 Painlevé VI connection problem and monodromy of c = conformal blocks. JHEP p. 4. Iorgov N. Lisovyy O. & Teschner J. 05 Isomonodromic tau-functions from Liouville conformal blocks. Commun. Math. Phys Bershtein M. & Shchechkin A. 05 Bilinear equations on Painlevé τ functions from CFT. Commun. Math. Phys Gavrylenko P. & Lisovyy O. Fredholm determinant and Nekrasov sum representations of isomonodromic tau functions. arxiv: Nagoya H. 05 Irregular conformal blocks with an application to the fifth and fourth Painleve equations. J. Math. Phys Bershtein M. & Shchechkin A. 07 Bäcklund transformation of Painlevé IIID8 τfunction. J. Phys. A: Math. Theor p. 9. Bonelli G. Lisovyy O. Maruyoshi K. Sciarappa A. & Tanzini A. On Painleve/gauge theory correspondence. arxiv: Gavrylenko P. & Lisovyy O. Pure SU gauge theory partition function and generalized Bessel kernel. arxiv: Bershtein M. & Shchechkin A. 07 q-deformed Painlevé τ function and q-deformed conformal blocks. J. Phys. A: Math. Theor p.. Awata H. Feigin B. & Shiraishi J. 0 Quantum algebraic approach to refined topological vertex. JHEP p. 3. Sakai H. 998 Casorati determinant solutions for the q-difference sixth Painlevé equation. Nonlinearity Tsuda T. & Masuda T. 006 q-painlevé VI equation arising from q-uc hierarchy. Commun. Math. Phys Feigin B. & Tsymbaliuk A. 0 Heisenberg action in the equivariant K-theory of Hilbert schemes via Shuffle Algebra. Kyoto J. Math Feigin B. Hashizume K. Hoshino A. Shiraishi J. & Yanagida S. 009 A commutative algebra on degenerate CP and Macdonald polynomials. J. Math. Phys Miki K. 007 A q γanalog of the W + algebra. J. Math. Phys Shiraishi J. Kubo H. Awata H. & Odake S. 996 A quantum deformation of the Virasoro algebra and the Macdonald symmetric functions. Lett. Math. Phys Awata H. & Yamada Y. 00 Five-dimensional AGT conjecture and the deformed Virasoro algebra. JHEP p. 0. Jimbo M. & Sakai H. 996 A q-analog of the sixth Painlevé equation. Lett. Math. Phys Sakai H. 00 Rational surfaces associated with affine root systmes and geometry of Painlevé equations. Commun. Math. Phys Ramani A. Grammaticos B. & Hietarinta J. 99 Discrete versions of the Painlevé equations. Phys. Rev. Lett Mano T. 00 Asymptotic behaviour around a boundary point of the q-painlevé VI equation and its connection problem. Nonlinearity Downloaded from on 0 July 08
2 Composition. Invertible Mappings
Arkansas Tech University MATH 4033: Elementary Modern Algebra Dr. Marcel B. Finan Composition. Invertible Mappings In this section we discuss two procedures for creating new mappings from old ones, namely,
Διαβάστε περισσότεραCongruence Classes of Invertible Matrices of Order 3 over F 2
International Journal of Algebra, Vol. 8, 24, no. 5, 239-246 HIKARI Ltd, www.m-hikari.com http://dx.doi.org/.2988/ija.24.422 Congruence Classes of Invertible Matrices of Order 3 over F 2 Ligong An and
Διαβάστε περισσότεραChapter 6: Systems of Linear Differential. be continuous functions on the interval
Chapter 6: Systems of Linear Differential Equations Let a (t), a 2 (t),..., a nn (t), b (t), b 2 (t),..., b n (t) be continuous functions on the interval I. The system of n first-order differential equations
Διαβάστε περισσότεραEvery set of first-order formulas is equivalent to an independent set
Every set of first-order formulas is equivalent to an independent set May 6, 2008 Abstract A set of first-order formulas, whatever the cardinality of the set of symbols, is equivalent to an independent
Διαβάστε περισσότεραarxiv: v2 [math-ph] 17 Aug 2017
CFT APPROACH TO THE q-painlevé VI EQUATION arxiv:706.0940v math-ph] 7 Aug 07 M. JIMBO H. NAGOYA AND H. SAKAI Dedicated to Professor Kazuo Okamoto on the occasion of his seventieth birthday Abstract. Iorgov
Διαβάστε περισσότεραLecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3
Lecture 2: Dirac notation and a review of linear algebra Read Sakurai chapter 1, Baym chatper 3 1 State vector space and the dual space Space of wavefunctions The space of wavefunctions is the set of all
Διαβάστε περισσότεραExample Sheet 3 Solutions
Example Sheet 3 Solutions. i Regular Sturm-Liouville. ii Singular Sturm-Liouville mixed boundary conditions. iii Not Sturm-Liouville ODE is not in Sturm-Liouville form. iv Regular Sturm-Liouville note
Διαβάστε περισσότερα6.1. Dirac Equation. Hamiltonian. Dirac Eq.
6.1. Dirac Equation Ref: M.Kaku, Quantum Field Theory, Oxford Univ Press (1993) η μν = η μν = diag(1, -1, -1, -1) p 0 = p 0 p = p i = -p i p μ p μ = p 0 p 0 + p i p i = E c 2 - p 2 = (m c) 2 H = c p 2
Διαβάστε περισσότεραSCHOOL OF MATHEMATICAL SCIENCES G11LMA Linear Mathematics Examination Solutions
SCHOOL OF MATHEMATICAL SCIENCES GLMA Linear Mathematics 00- Examination Solutions. (a) i. ( + 5i)( i) = (6 + 5) + (5 )i = + i. Real part is, imaginary part is. (b) ii. + 5i i ( + 5i)( + i) = ( i)( + i)
Διαβάστε περισσότεραLecture 13 - Root Space Decomposition II
Lecture 13 - Root Space Decomposition II October 18, 2012 1 Review First let us recall the situation. Let g be a simple algebra, with maximal toral subalgebra h (which we are calling a CSA, or Cartan Subalgebra).
Διαβάστε περισσότεραHomework 3 Solutions
Homework 3 Solutions Igor Yanovsky (Math 151A TA) Problem 1: Compute the absolute error and relative error in approximations of p by p. (Use calculator!) a) p π, p 22/7; b) p π, p 3.141. Solution: For
Διαβάστε περισσότεραChapter 6: Systems of Linear Differential. be continuous functions on the interval
Chapter 6: Systems of Linear Differential Equations Let a (t), a 2 (t),..., a nn (t), b (t), b 2 (t),..., b n (t) be continuous functions on the interval I. The system of n first-order differential equations
Διαβάστε περισσότεραEE512: Error Control Coding
EE512: Error Control Coding Solution for Assignment on Finite Fields February 16, 2007 1. (a) Addition and Multiplication tables for GF (5) and GF (7) are shown in Tables 1 and 2. + 0 1 2 3 4 0 0 1 2 3
Διαβάστε περισσότεραC.S. 430 Assignment 6, Sample Solutions
C.S. 430 Assignment 6, Sample Solutions Paul Liu November 15, 2007 Note that these are sample solutions only; in many cases there were many acceptable answers. 1 Reynolds Problem 10.1 1.1 Normal-order
Διαβάστε περισσότεραPartial Differential Equations in Biology The boundary element method. March 26, 2013
The boundary element method March 26, 203 Introduction and notation The problem: u = f in D R d u = ϕ in Γ D u n = g on Γ N, where D = Γ D Γ N, Γ D Γ N = (possibly, Γ D = [Neumann problem] or Γ N = [Dirichlet
Διαβάστε περισσότεραCHAPTER 25 SOLVING EQUATIONS BY ITERATIVE METHODS
CHAPTER 5 SOLVING EQUATIONS BY ITERATIVE METHODS EXERCISE 104 Page 8 1. Find the positive root of the equation x + 3x 5 = 0, correct to 3 significant figures, using the method of bisection. Let f(x) =
Διαβάστε περισσότεραderivation of the Laplacian from rectangular to spherical coordinates
derivation of the Laplacian from rectangular to spherical coordinates swapnizzle 03-03- :5:43 We begin by recognizing the familiar conversion from rectangular to spherical coordinates (note that φ is used
Διαβάστε περισσότεραOrdinal Arithmetic: Addition, Multiplication, Exponentiation and Limit
Ordinal Arithmetic: Addition, Multiplication, Exponentiation and Limit Ting Zhang Stanford May 11, 2001 Stanford, 5/11/2001 1 Outline Ordinal Classification Ordinal Addition Ordinal Multiplication Ordinal
Διαβάστε περισσότεραConcrete Mathematics Exercises from 30 September 2016
Concrete Mathematics Exercises from 30 September 2016 Silvio Capobianco Exercise 1.7 Let H(n) = J(n + 1) J(n). Equation (1.8) tells us that H(2n) = 2, and H(2n+1) = J(2n+2) J(2n+1) = (2J(n+1) 1) (2J(n)+1)
Διαβάστε περισσότερα3.4 SUM AND DIFFERENCE FORMULAS. NOTE: cos(α+β) cos α + cos β cos(α-β) cos α -cos β
3.4 SUM AND DIFFERENCE FORMULAS Page Theorem cos(αβ cos α cos β -sin α cos(α-β cos α cos β sin α NOTE: cos(αβ cos α cos β cos(α-β cos α -cos β Proof of cos(α-β cos α cos β sin α Let s use a unit circle
Διαβάστε περισσότεραMatrices and Determinants
Matrices and Determinants SUBJECTIVE PROBLEMS: Q 1. For what value of k do the following system of equations possess a non-trivial (i.e., not all zero) solution over the set of rationals Q? x + ky + 3z
Διαβάστε περισσότεραSection 8.3 Trigonometric Equations
99 Section 8. Trigonometric Equations Objective 1: Solve Equations Involving One Trigonometric Function. In this section and the next, we will exple how to solving equations involving trigonometric functions.
Διαβάστε περισσότεραFourier Series. MATH 211, Calculus II. J. Robert Buchanan. Spring Department of Mathematics
Fourier Series MATH 211, Calculus II J. Robert Buchanan Department of Mathematics Spring 2018 Introduction Not all functions can be represented by Taylor series. f (k) (c) A Taylor series f (x) = (x c)
Διαβάστε περισσότεραOther Test Constructions: Likelihood Ratio & Bayes Tests
Other Test Constructions: Likelihood Ratio & Bayes Tests Side-Note: So far we have seen a few approaches for creating tests such as Neyman-Pearson Lemma ( most powerful tests of H 0 : θ = θ 0 vs H 1 :
Διαβάστε περισσότεραReminders: linear functions
Reminders: linear functions Let U and V be vector spaces over the same field F. Definition A function f : U V is linear if for every u 1, u 2 U, f (u 1 + u 2 ) = f (u 1 ) + f (u 2 ), and for every u U
Διαβάστε περισσότεραNowhere-zero flows Let be a digraph, Abelian group. A Γ-circulation in is a mapping : such that, where, and : tail in X, head in
Nowhere-zero flows Let be a digraph, Abelian group. A Γ-circulation in is a mapping : such that, where, and : tail in X, head in : tail in X, head in A nowhere-zero Γ-flow is a Γ-circulation such that
Διαβάστε περισσότεραST5224: Advanced Statistical Theory II
ST5224: Advanced Statistical Theory II 2014/2015: Semester II Tutorial 7 1. Let X be a sample from a population P and consider testing hypotheses H 0 : P = P 0 versus H 1 : P = P 1, where P j is a known
Διαβάστε περισσότεραAreas and Lengths in Polar Coordinates
Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the
Διαβάστε περισσότεραA Note on Intuitionistic Fuzzy. Equivalence Relation
International Mathematical Forum, 5, 2010, no. 67, 3301-3307 A Note on Intuitionistic Fuzzy Equivalence Relation D. K. Basnet Dept. of Mathematics, Assam University Silchar-788011, Assam, India dkbasnet@rediffmail.com
Διαβάστε περισσότερα4.6 Autoregressive Moving Average Model ARMA(1,1)
84 CHAPTER 4. STATIONARY TS MODELS 4.6 Autoregressive Moving Average Model ARMA(,) This section is an introduction to a wide class of models ARMA(p,q) which we will consider in more detail later in this
Διαβάστε περισσότεραAreas and Lengths in Polar Coordinates
Kiryl Tsishchanka Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the
Διαβάστε περισσότεραHOMEWORK 4 = G. In order to plot the stress versus the stretch we define a normalized stretch:
HOMEWORK 4 Problem a For the fast loading case, we want to derive the relationship between P zz and λ z. We know that the nominal stress is expressed as: P zz = ψ λ z where λ z = λ λ z. Therefore, applying
Διαβάστε περισσότεραΑπόκριση σε Μοναδιαία Ωστική Δύναμη (Unit Impulse) Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο. Απόστολος Σ.
Απόκριση σε Δυνάμεις Αυθαίρετα Μεταβαλλόμενες με το Χρόνο The time integral of a force is referred to as impulse, is determined by and is obtained from: Newton s 2 nd Law of motion states that the action
Διαβάστε περισσότερα( ) 2 and compare to M.
Problems and Solutions for Section 4.2 4.9 through 4.33) 4.9 Calculate the square root of the matrix 3!0 M!0 8 Hint: Let M / 2 a!b ; calculate M / 2!b c ) 2 and compare to M. Solution: Given: 3!0 M!0 8
Διαβάστε περισσότερα6.3 Forecasting ARMA processes
122 CHAPTER 6. ARMA MODELS 6.3 Forecasting ARMA processes The purpose of forecasting is to predict future values of a TS based on the data collected to the present. In this section we will discuss a linear
Διαβάστε περισσότεραCRASH COURSE IN PRECALCULUS
CRASH COURSE IN PRECALCULUS Shiah-Sen Wang The graphs are prepared by Chien-Lun Lai Based on : Precalculus: Mathematics for Calculus by J. Stuwart, L. Redin & S. Watson, 6th edition, 01, Brooks/Cole Chapter
Διαβάστε περισσότεραFractional Colorings and Zykov Products of graphs
Fractional Colorings and Zykov Products of graphs Who? Nichole Schimanski When? July 27, 2011 Graphs A graph, G, consists of a vertex set, V (G), and an edge set, E(G). V (G) is any finite set E(G) is
Διαβάστε περισσότεραw o = R 1 p. (1) R = p =. = 1
Πανεπιστήµιο Κρήτης - Τµήµα Επιστήµης Υπολογιστών ΗΥ-570: Στατιστική Επεξεργασία Σήµατος 205 ιδάσκων : Α. Μουχτάρης Τριτη Σειρά Ασκήσεων Λύσεις Ασκηση 3. 5.2 (a) From the Wiener-Hopf equation we have:
Διαβάστε περισσότεραPhys460.nb Solution for the t-dependent Schrodinger s equation How did we find the solution? (not required)
Phys460.nb 81 ψ n (t) is still the (same) eigenstate of H But for tdependent H. The answer is NO. 5.5.5. Solution for the tdependent Schrodinger s equation If we assume that at time t 0, the electron starts
Διαβάστε περισσότεραSection 7.6 Double and Half Angle Formulas
09 Section 7. Double and Half Angle Fmulas To derive the double-angles fmulas, we will use the sum of two angles fmulas that we developed in the last section. We will let α θ and β θ: cos(θ) cos(θ + θ)
Διαβάστε περισσότεραg-selberg integrals MV Conjecture An A 2 Selberg integral Summary Long Live the King Ole Warnaar Department of Mathematics Long Live the King
Ole Warnaar Department of Mathematics g-selberg integrals The Selberg integral corresponds to the following k-dimensional generalisation of the beta integral: D Here and k t α 1 i (1 t i ) β 1 1 i
Διαβάστε περισσότερα= λ 1 1 e. = λ 1 =12. has the properties e 1. e 3,V(Y
Stat 50 Homework Solutions Spring 005. (a λ λ λ 44 (b trace( λ + λ + λ 0 (c V (e x e e λ e e λ e (λ e by definition, the eigenvector e has the properties e λ e and e e. (d λ e e + λ e e + λ e e 8 6 4 4
Διαβάστε περισσότεραFinite Field Problems: Solutions
Finite Field Problems: Solutions 1. Let f = x 2 +1 Z 11 [x] and let F = Z 11 [x]/(f), a field. Let Solution: F =11 2 = 121, so F = 121 1 = 120. The possible orders are the divisors of 120. Solution: The
Διαβάστε περισσότεραDiracDelta. Notations. Primary definition. Specific values. General characteristics. Traditional name. Traditional notation
DiracDelta Notations Traditional name Dirac delta function Traditional notation x Mathematica StandardForm notation DiracDeltax Primary definition 4.03.02.000.0 x Π lim ε ; x ε0 x 2 2 ε Specific values
Διαβάστε περισσότεραUniform Convergence of Fourier Series Michael Taylor
Uniform Convergence of Fourier Series Michael Taylor Given f L 1 T 1 ), we consider the partial sums of the Fourier series of f: N 1) S N fθ) = ˆfk)e ikθ. k= N A calculation gives the Dirichlet formula
Διαβάστε περισσότεραCoefficient Inequalities for a New Subclass of K-uniformly Convex Functions
International Journal of Computational Science and Mathematics. ISSN 0974-89 Volume, Number (00), pp. 67--75 International Research Publication House http://www.irphouse.com Coefficient Inequalities for
Διαβάστε περισσότεραInverse trigonometric functions & General Solution of Trigonometric Equations. ------------------ ----------------------------- -----------------
Inverse trigonometric functions & General Solution of Trigonometric Equations. 1. Sin ( ) = a) b) c) d) Ans b. Solution : Method 1. Ans a: 17 > 1 a) is rejected. w.k.t Sin ( sin ) = d is rejected. If sin
Διαβάστε περισσότεραMath221: HW# 1 solutions
Math: HW# solutions Andy Royston October, 5 7.5.7, 3 rd Ed. We have a n = b n = a = fxdx = xdx =, x cos nxdx = x sin nx n sin nxdx n = cos nx n = n n, x sin nxdx = x cos nx n + cos nxdx n cos n = + sin
Διαβάστε περισσότεραLecture 15 - Root System Axiomatics
Lecture 15 - Root System Axiomatics Nov 1, 01 In this lecture we examine root systems from an axiomatic point of view. 1 Reflections If v R n, then it determines a hyperplane, denoted P v, through the
Διαβάστε περισσότερα2. Let H 1 and H 2 be Hilbert spaces and let T : H 1 H 2 be a bounded linear operator. Prove that [T (H 1 )] = N (T ). (6p)
Uppsala Universitet Matematiska Institutionen Andreas Strömbergsson Prov i matematik Funktionalanalys Kurs: F3B, F4Sy, NVP 2005-03-08 Skrivtid: 9 14 Tillåtna hjälpmedel: Manuella skrivdon, Kreyszigs bok
Διαβάστε περισσότεραORDINAL ARITHMETIC JULIAN J. SCHLÖDER
ORDINAL ARITHMETIC JULIAN J. SCHLÖDER Abstract. We define ordinal arithmetic and show laws of Left- Monotonicity, Associativity, Distributivity, some minor related properties and the Cantor Normal Form.
Διαβάστε περισσότεραforms This gives Remark 1. How to remember the above formulas: Substituting these into the equation we obtain with
Week 03: C lassification of S econd- Order L inear Equations In last week s lectures we have illustrated how to obtain the general solutions of first order PDEs using the method of characteristics. We
Διαβάστε περισσότεραSecond Order Partial Differential Equations
Chapter 7 Second Order Partial Differential Equations 7.1 Introduction A second order linear PDE in two independent variables (x, y Ω can be written as A(x, y u x + B(x, y u xy + C(x, y u u u + D(x, y
Διαβάστε περισσότεραQuadratic Expressions
Quadratic Expressions. The standard form of a quadratic equation is ax + bx + c = 0 where a, b, c R and a 0. The roots of ax + bx + c = 0 are b ± b a 4ac. 3. For the equation ax +bx+c = 0, sum of the roots
Διαβάστε περισσότεραProblem Set 3: Solutions
CMPSCI 69GG Applied Information Theory Fall 006 Problem Set 3: Solutions. [Cover and Thomas 7.] a Define the following notation, C I p xx; Y max X; Y C I p xx; Ỹ max I X; Ỹ We would like to show that C
Διαβάστε περισσότεραMath 446 Homework 3 Solutions. (1). (i): Reverse triangle inequality for metrics: Let (X, d) be a metric space and let x, y, z X.
Math 446 Homework 3 Solutions. (1). (i): Reverse triangle inequalit for metrics: Let (X, d) be a metric space and let x,, z X. Prove that d(x, z) d(, z) d(x, ). (ii): Reverse triangle inequalit for norms:
Διαβάστε περισσότεραOn the Galois Group of Linear Difference-Differential Equations
On the Galois Group of Linear Difference-Differential Equations Ruyong Feng KLMM, Chinese Academy of Sciences, China Ruyong Feng (KLMM, CAS) Galois Group 1 / 19 Contents 1 Basic Notations and Concepts
Διαβάστε περισσότεραStatistical Inference I Locally most powerful tests
Statistical Inference I Locally most powerful tests Shirsendu Mukherjee Department of Statistics, Asutosh College, Kolkata, India. shirsendu st@yahoo.co.in So far we have treated the testing of one-sided
Διαβάστε περισσότεραJesse Maassen and Mark Lundstrom Purdue University November 25, 2013
Notes on Average Scattering imes and Hall Factors Jesse Maassen and Mar Lundstrom Purdue University November 5, 13 I. Introduction 1 II. Solution of the BE 1 III. Exercises: Woring out average scattering
Διαβάστε περισσότεραLecture 10 - Representation Theory III: Theory of Weights
Lecture 10 - Representation Theory III: Theory of Weights February 18, 2012 1 Terminology One assumes a base = {α i } i has been chosen. Then a weight Λ with non-negative integral Dynkin coefficients Λ
Διαβάστε περισσότερα= {{D α, D α }, D α }. = [D α, 4iσ µ α α D α µ ] = 4iσ µ α α [Dα, D α ] µ.
PHY 396 T: SUSY Solutions for problem set #1. Problem 2(a): First of all, [D α, D 2 D α D α ] = {D α, D α }D α D α {D α, D α } = {D α, D α }D α + D α {D α, D α } (S.1) = {{D α, D α }, D α }. Second, {D
Διαβάστε περισσότεραTridiagonal matrices. Gérard MEURANT. October, 2008
Tridiagonal matrices Gérard MEURANT October, 2008 1 Similarity 2 Cholesy factorizations 3 Eigenvalues 4 Inverse Similarity Let α 1 ω 1 β 1 α 2 ω 2 T =......... β 2 α 1 ω 1 β 1 α and β i ω i, i = 1,...,
Διαβάστε περισσότεραMINIMAL CLOSED SETS AND MAXIMAL CLOSED SETS
MINIMAL CLOSED SETS AND MAXIMAL CLOSED SETS FUMIE NAKAOKA AND NOBUYUKI ODA Received 20 December 2005; Revised 28 May 2006; Accepted 6 August 2006 Some properties of minimal closed sets and maximal closed
Διαβάστε περισσότεραThe Simply Typed Lambda Calculus
Type Inference Instead of writing type annotations, can we use an algorithm to infer what the type annotations should be? That depends on the type system. For simple type systems the answer is yes, and
Διαβάστε περισσότεραNotes on the Open Economy
Notes on the Open Econom Ben J. Heijdra Universit of Groningen April 24 Introduction In this note we stud the two-countr model of Table.4 in more detail. restated here for convenience. The model is Table.4.
Διαβάστε περισσότεραThe k-α-exponential Function
Int Journal of Math Analysis, Vol 7, 213, no 11, 535-542 The --Exponential Function Luciano L Luque and Rubén A Cerutti Faculty of Exact Sciences National University of Nordeste Av Libertad 554 34 Corrientes,
Διαβάστε περισσότεραPARTIAL NOTES for 6.1 Trigonometric Identities
PARTIAL NOTES for 6.1 Trigonometric Identities tanθ = sinθ cosθ cotθ = cosθ sinθ BASIC IDENTITIES cscθ = 1 sinθ secθ = 1 cosθ cotθ = 1 tanθ PYTHAGOREAN IDENTITIES sin θ + cos θ =1 tan θ +1= sec θ 1 + cot
Διαβάστε περισσότεραApproximation of distance between locations on earth given by latitude and longitude
Approximation of distance between locations on earth given by latitude and longitude Jan Behrens 2012-12-31 In this paper we shall provide a method to approximate distances between two points on earth
Διαβάστε περισσότεραSOLVING CUBICS AND QUARTICS BY RADICALS
SOLVING CUBICS AND QUARTICS BY RADICALS The purpose of this handout is to record the classical formulas expressing the roots of degree three and degree four polynomials in terms of radicals. We begin with
Διαβάστε περισσότεραk A = [k, k]( )[a 1, a 2 ] = [ka 1,ka 2 ] 4For the division of two intervals of confidence in R +
Chapter 3. Fuzzy Arithmetic 3- Fuzzy arithmetic: ~Addition(+) and subtraction (-): Let A = [a and B = [b, b in R If x [a and y [b, b than x+y [a +b +b Symbolically,we write A(+)B = [a (+)[b, b = [a +b
Διαβάστε περισσότεραSpace-Time Symmetries
Chapter Space-Time Symmetries In classical fiel theory any continuous symmetry of the action generates a conserve current by Noether's proceure. If the Lagrangian is not invariant but only shifts by a
Διαβάστε περισσότεραOn a four-dimensional hyperbolic manifold with finite volume
BULETINUL ACADEMIEI DE ŞTIINŢE A REPUBLICII MOLDOVA. MATEMATICA Numbers 2(72) 3(73), 2013, Pages 80 89 ISSN 1024 7696 On a four-dimensional hyperbolic manifold with finite volume I.S.Gutsul Abstract. In
Διαβάστε περισσότεραSOME PROPERTIES OF FUZZY REAL NUMBERS
Sahand Communications in Mathematical Analysis (SCMA) Vol. 3 No. 1 (2016), 21-27 http://scma.maragheh.ac.ir SOME PROPERTIES OF FUZZY REAL NUMBERS BAYAZ DARABY 1 AND JAVAD JAFARI 2 Abstract. In the mathematical
Διαβάστε περισσότεραGenerating Set of the Complete Semigroups of Binary Relations
Applied Mathematics 06 7 98-07 Published Online January 06 in SciRes http://wwwscirporg/journal/am http://dxdoiorg/036/am067009 Generating Set of the Complete Semigroups of Binary Relations Yasha iasamidze
Διαβάστε περισσότεραLecture 21: Properties and robustness of LSE
Lecture 21: Properties and robustness of LSE BLUE: Robustness of LSE against normality We now study properties of l τ β and σ 2 under assumption A2, i.e., without the normality assumption on ε. From Theorem
Διαβάστε περισσότεραENGR 691/692 Section 66 (Fall 06): Machine Learning Assigned: August 30 Homework 1: Bayesian Decision Theory (solutions) Due: September 13
ENGR 69/69 Section 66 (Fall 06): Machine Learning Assigned: August 30 Homework : Bayesian Decision Theory (solutions) Due: Septemer 3 Prolem : ( pts) Let the conditional densities for a two-category one-dimensional
Διαβάστε περισσότεραExercises 10. Find a fundamental matrix of the given system of equations. Also find the fundamental matrix Φ(t) satisfying Φ(0) = I. 1.
Exercises 0 More exercises are available in Elementary Differential Equations. If you have a problem to solve any of them, feel free to come to office hour. Problem Find a fundamental matrix of the given
Διαβάστε περισσότεραNew bounds for spherical two-distance sets and equiangular lines
New bounds for spherical two-distance sets and equiangular lines Michigan State University Oct 8-31, 016 Anhui University Definition If X = {x 1, x,, x N } S n 1 (unit sphere in R n ) and x i, x j = a
Διαβάστε περισσότεραHomework 8 Model Solution Section
MATH 004 Homework Solution Homework 8 Model Solution Section 14.5 14.6. 14.5. Use the Chain Rule to find dz where z cosx + 4y), x 5t 4, y 1 t. dz dx + dy y sinx + 4y)0t + 4) sinx + 4y) 1t ) 0t + 4t ) sinx
Διαβάστε περισσότεραLecture 2. Soundness and completeness of propositional logic
Lecture 2 Soundness and completeness of propositional logic February 9, 2004 1 Overview Review of natural deduction. Soundness and completeness. Semantics of propositional formulas. Soundness proof. Completeness
Διαβάστε περισσότερα5. Choice under Uncertainty
5. Choice under Uncertainty Daisuke Oyama Microeconomics I May 23, 2018 Formulations von Neumann-Morgenstern (1944/1947) X: Set of prizes Π: Set of probability distributions on X : Preference relation
Διαβάστε περισσότεραTesting for Indeterminacy: An Application to U.S. Monetary Policy. Technical Appendix
Testing for Indeterminacy: An Application to U.S. Monetary Policy Technical Appendix Thomas A. Lubik Department of Economics Johns Hopkins University Frank Schorfheide Department of Economics University
Διαβάστε περισσότεραMath 6 SL Probability Distributions Practice Test Mark Scheme
Math 6 SL Probability Distributions Practice Test Mark Scheme. (a) Note: Award A for vertical line to right of mean, A for shading to right of their vertical line. AA N (b) evidence of recognizing symmetry
Διαβάστε περισσότεραLecture Notes Introduction to Cluster Algebra
Lecture Notes Introduction to Cluster Algebra Ivan C.H. Ip Update: May 29, 2017 7.2 Properties of Exchangeable roots The notion of exchangeable is explained as follows Proposition 7.20. If C and C = C
Διαβάστε περισσότεραTwo generalisations of the binomial theorem
39 Two generalisations of the binomial theorem Sacha C. Blumen Abstract We prove two generalisations of the binomial theorem that are also generalisations of the q-binomial theorem. These generalisations
Διαβάστε περισσότεραLecture 16 - Weyl s Character Formula I: The Weyl Function and the Kostant Partition Function
Lecture 16 - Weyl s Character Formula I: The Weyl Function and the Kostant Partition Function March 22, 2013 References: A. Knapp, Lie Groups Beyond an Introduction. Ch V Fulton-Harris, Representation
Διαβάστε περισσότεραDIRECT PRODUCT AND WREATH PRODUCT OF TRANSFORMATION SEMIGROUPS
GANIT J. Bangladesh Math. oc. IN 606-694) 0) -7 DIRECT PRODUCT AND WREATH PRODUCT OF TRANFORMATION EMIGROUP ubrata Majumdar, * Kalyan Kumar Dey and Mohd. Altab Hossain Department of Mathematics University
Διαβάστε περισσότεραBessel functions. ν + 1 ; 1 = 0 for k = 0, 1, 2,..., n 1. Γ( n + k + 1) = ( 1) n J n (z). Γ(n + k + 1) k!
Bessel functions The Bessel function J ν (z of the first kind of order ν is defined by J ν (z ( (z/ν ν Γ(ν + F ν + ; z 4 ( k k ( Γ(ν + k + k! For ν this is a solution of the Bessel differential equation
Διαβάστε περισσότεραSolutions to Exercise Sheet 5
Solutions to Eercise Sheet 5 jacques@ucsd.edu. Let X and Y be random variables with joint pdf f(, y) = 3y( + y) where and y. Determine each of the following probabilities. Solutions. a. P (X ). b. P (X
Διαβάστε περισσότεραSolution Series 9. i=1 x i and i=1 x i.
Lecturer: Prof. Dr. Mete SONER Coordinator: Yilin WANG Solution Series 9 Q1. Let α, β >, the p.d.f. of a beta distribution with parameters α and β is { Γ(α+β) Γ(α)Γ(β) f(x α, β) xα 1 (1 x) β 1 for < x
Διαβάστε περισσότεραCyclic or elementary abelian Covers of K 4
Cyclic or elementary abelian Covers of K 4 Yan-Quan Feng Mathematics, Beijing Jiaotong University Beijing 100044, P.R. China Summer School, Rogla, Slovenian 2011-06 Outline 1 Question 2 Main results 3
Διαβάστε περισσότεραSCITECH Volume 13, Issue 2 RESEARCH ORGANISATION Published online: March 29, 2018
Journal of rogressive Research in Mathematics(JRM) ISSN: 2395-028 SCITECH Volume 3, Issue 2 RESEARCH ORGANISATION ublished online: March 29, 208 Journal of rogressive Research in Mathematics www.scitecresearch.com/journals
Διαβάστε περισσότεραCommutative Monoids in Intuitionistic Fuzzy Sets
Commutative Monoids in Intuitionistic Fuzzy Sets S K Mala #1, Dr. MM Shanmugapriya *2 1 PhD Scholar in Mathematics, Karpagam University, Coimbatore, Tamilnadu- 641021 Assistant Professor of Mathematics,
Διαβάστε περισσότεραStrain gauge and rosettes
Strain gauge and rosettes Introduction A strain gauge is a device which is used to measure strain (deformation) on an object subjected to forces. Strain can be measured using various types of devices classified
Διαβάστε περισσότεραOptimal Parameter in Hermitian and Skew-Hermitian Splitting Method for Certain Two-by-Two Block Matrices
Optimal Parameter in Hermitian and Skew-Hermitian Splitting Method for Certain Two-by-Two Block Matrices Chi-Kwong Li Department of Mathematics The College of William and Mary Williamsburg, Virginia 23187-8795
Διαβάστε περισσότεραBounding Nonsplitting Enumeration Degrees
Bounding Nonsplitting Enumeration Degrees Thomas F. Kent Andrea Sorbi Università degli Studi di Siena Italia July 18, 2007 Goal: Introduce a form of Σ 0 2-permitting for the enumeration degrees. Till now,
Διαβάστε περισσότεραMATH423 String Theory Solutions 4. = 0 τ = f(s). (1) dτ ds = dxµ dτ f (s) (2) dτ 2 [f (s)] 2 + dxµ. dτ f (s) (3)
1. MATH43 String Theory Solutions 4 x = 0 τ = fs). 1) = = f s) ) x = x [f s)] + f s) 3) equation of motion is x = 0 if an only if f s) = 0 i.e. fs) = As + B with A, B constants. i.e. allowe reparametrisations
Διαβάστε περισσότεραΚΥΠΡΙΑΚΗ ΕΤΑΙΡΕΙΑ ΠΛΗΡΟΦΟΡΙΚΗΣ CYPRUS COMPUTER SOCIETY ΠΑΓΚΥΠΡΙΟΣ ΜΑΘΗΤΙΚΟΣ ΔΙΑΓΩΝΙΣΜΟΣ ΠΛΗΡΟΦΟΡΙΚΗΣ 19/5/2007
Οδηγίες: Να απαντηθούν όλες οι ερωτήσεις. Αν κάπου κάνετε κάποιες υποθέσεις να αναφερθούν στη σχετική ερώτηση. Όλα τα αρχεία που αναφέρονται στα προβλήματα βρίσκονται στον ίδιο φάκελο με το εκτελέσιμο
Διαβάστε περισσότεραEcon 2110: Fall 2008 Suggested Solutions to Problem Set 8 questions or comments to Dan Fetter 1
Eon : Fall 8 Suggested Solutions to Problem Set 8 Email questions or omments to Dan Fetter Problem. Let X be a salar with density f(x, θ) (θx + θ) [ x ] with θ. (a) Find the most powerful level α test
Διαβάστε περισσότεραD Alembert s Solution to the Wave Equation
D Alembert s Solution to the Wave Equation MATH 467 Partial Differential Equations J. Robert Buchanan Department of Mathematics Fall 2018 Objectives In this lesson we will learn: a change of variable technique
Διαβάστε περισσότερα